bạn làm kiểu này :

0.5x-\(\dfrac{2}{3}\)x=\(\dfrac{7}{6}\)

0-\(\dfrac{2}{3}\)x=\(\dfrac{7}{6}\)

\(\dfrac{2}{3}\)x=0-\(\dfrac{7}{6}\)

0.5x-\(\dfrac{2}{3}\)x=\(\dfrac{7}{6}\)

\(\left(\dfrac{1}{2}-\dfrac{2}{3}\right)\). x=\(\dfrac{7}{6}\)

\(\left(\dfrac{3}{6}-\dfrac{4}{6}\right)\). x=\(\dfrac{7}{6}\)

\(\dfrac{-1}{6}\). x=\(\dfrac{7}{6}\)

x=\(\dfrac{7}{6}\):\(\dfrac{-1}{6}\)

x=\(\dfrac{7}{6}\) . \(\dfrac{6}{-1}\)

x=\(\dfrac{42}{-6}\)

x=\(\dfrac{7}{-1}\)

lại bí rùi

a: \(\Leftrightarrow x^2+4x+3=x^2+4x+0.5x+2\)

=>0,5x+2=3

=>0,5x=1

hay x=2

b: \(\Leftrightarrow\left|7x-9\right|=5x-3\)

\(\Leftrightarrow\left\{{}\begin{matrix}x>=\dfrac{3}{5}\\\left(7x-9-5x+3\right)\left(7x-9+5x-3\right)=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x>=\dfrac{3}{5}\\\left(2x-6\right)\left(12x-12\right)=0\end{matrix}\right.\Leftrightarrow x\in\left\{3;1\right\}\)

c: =>10x+7>-37 và 10x+7<37

=>10x>-44 và 10x<30

=>-4,4<x<3

a,\(\left(0,5x-\dfrac{3}{7}\right):\dfrac{1}{2}=1\dfrac{1}{7}\)

\(0,5x-\dfrac{3}{7}=\dfrac{4}{7}\)

\(0,5x=1\)

\(x=2\)

b,Đề chưa rõ,bạn viết lại nhé!

c,\(\left(\dfrac{1}{5}-\dfrac{3}{2}x\right)^2=\dfrac{9}{4}\)

\(\dfrac{1}{5}-\dfrac{3}{2}x=\dfrac{3}{2}\)

\(\dfrac{3}{2}x=-\dfrac{13}{10}\)

\(x=-\dfrac{13}{15}\)

1,3x+2/5x+7 =3x-1/5x+1

<=> 1,3x+2/5x-3x+1/5x = 1-7

<=> (1,3+2/5-3+1/5)x = -6

<=> -11/10x=-6

<=> x= -6 : (-11/10)

<=> x= 60/11

2.x+1/2x+1 = 0,5x+2/x +3

<=> 2x+1/2x-0,5x-2/1x = 3-1

<=> x(2+1/2-0,5-2 ) =2

<=>0x =2

<=> x=0 

Hinh nhu minh thay ban Kunzy Nguyen giai hoi sai

1,3x o dau ra ???????????????

 Hình như bạn Kunzy Nguyễn ghi nhầm 3x thành 1,3x nhỉ ?!!! 

1) áp dụng tính chất của dãy tỉ số bằng nhau ta có:

\(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}=\frac{\left(3x+2\right)-\left(3x-1\right)}{\left(5x+7\right)-\left(5x+1\right)}=\frac{3x+2-3x+1}{5x+7-5x-1}=\frac{3}{6}=\frac{1}{2}\)

suy ra :

\(\frac{3x-1}{5x+1}=\frac{1}{2}\Rightarrow\left(5x+1\right).1=\left(3x-1\right).2\)

=> 5x+1=6x-2

5x-6x=-2-1

-x=-3

x=3

2)áp dụng tính chất của dãy tỉ số bằng nhau ta có;

\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}=\frac{\left(x+1\right)-2.\left(0,5x+2\right)}{\left(2x+1\right)-2.\left(x+3\right)}=\frac{x+1-x-4}{2x+1-2x-6}=\frac{-3}{-5}=\frac{3}{5}\)

suy ra:

\(\frac{x+1}{2x+1}=\frac{3}{5}\Rightarrow\left(2x+1\right).3=\left(x+1\right).5\)

=>6x+3=5x+5

6x-5x=5-3

x=2

 chỉ có làm mới có ăn

a ) \(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)

\(\Leftrightarrow\left(3x+2\right)\left(5x+1\right)=\left(3x-1\right)\left(5x+7\right)\)

\(\Leftrightarrow3x\left(5x+1\right)+2\left(5x+1\right)=3x\left(5x+7\right)-\left(5x+7\right)\)

\(\Leftrightarrow15x^2+3x+10x+2=15x^2+21x-5x-7\)

\(\Leftrightarrow15x^2+13x+2=15x^2+16x-7\)

\(\Leftrightarrow13x+2=16x-7\)

\(\Leftrightarrow13x-16x=-7-2\)

\(\Leftrightarrow-3x=-9\)

\(\Rightarrow x=3\)

b ) tương tự

x+2=-5

x =-7

x²+2x-3=0

(=) x²-x+3x-3=0

(=) x(x-1)+3(x-1)=0

(=) (x-1)(x+3)=0

=> x-1 = 0 hoặc x+3 = 0

x = 1 x =-3

x+4 = 10

x = 6

-3x + 2 =-7

(=) -3x =-9

(=) x = 3

0.5x + 4 = -1

(=) 0.5x =-5

(=) x =-10

Chúc bạn học tốt ^^

a)x+2=-5

\(\Leftrightarrow\)x =-7

b)x²+2x-3=0

\(\Leftrightarrow\)x²-x+3x-3=0

\(\Leftrightarrow\)x(x-1)+3(x-1)=0

\(\Leftrightarrow\)(x+3)(x-1)=0

\(\Rightarrow\)x+3=0 hoặc x-1=0

\(\Rightarrow\)x=-3 hoặc x=1

c)x+4=10

\(\Leftrightarrow\)x=6

d)-3x+2=-7

\(\Leftrightarrow\)-3x =-7-2

\(\Leftrightarrow\)3x =-9

\(\Leftrightarrow\)x =-3

e)0,5x+4=-1

\(\Leftrightarrow\)0,5x =-1-4

\(\Leftrightarrow\)0,5x = -5

\(\Leftrightarrow\)x =-5:0,5

\(\Leftrightarrow\)x =-10

a) 1/2x - 2/3x = 7/12

    -1/6x = 7/12

     x = \(\frac{7}{12}\div\frac{-1}{6}\)

     x = -7/2

b)  x: 12 = -2,5

     x = -2,5*12

     x = -30

c) 11/2x = 13/15

    x = 13/15:11/2

    x = 26/165

d) 3x/7 + 1 = (-1/28)*(-4)

    3x/7 + 1 = 1/7

    3x/7 = 1/7 - 1

    3x/7 = -6/7

    3x = -6

    x= -6/3

    x= -2