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A,3/4h

B,3/4m

C,9/10kg

D,5/6km/h

Cái gì ba mắt một chân?

a)\(\dfrac{2}{3}giờ< \dfrac{3}{4}giờ\)

b)\(\dfrac{7}{10}m< \dfrac{3}{4}m\)

c)\(\dfrac{7}{8}kg< \dfrac{9}{10}kg\)

d)\(\dfrac{5}{6}\)km/h >\(\dfrac{7}{9}\)km/h

a) h < h

b) m < m

c) kg < kg

d) km/h > km/h.

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a, 2/5 là thời gian ngắn hơn

b, 7/8 là quãng đường dài hơn

Hồng Trâm ơi ! mình kết bạn nhé

a) \(\dfrac{4}{5}\) giờ dài hơn

b) \(\dfrac{3}{5}\) mét ngắn hơn

c) \(\dfrac{7}{8}\) kg lớn hơn

a, \(\dfrac{1}{2}\)= \(\dfrac{5}{10}\) giờ \(\dfrac{4}{5}\)= \(\dfrac{8}{10}\)giờ

=> \(\dfrac{1}{5}\) < \(\dfrac{4}{5}\)

Vậy \(\dfrac{4}{5}\)giờ dài hơn \(\dfrac{1}{2}\) giờ

b, \(\dfrac{2}{3}\)m = \(\dfrac{10}{15}\) m \(\dfrac{3}{5}\) m = \(\dfrac{9}{15}\) m

=>\(\dfrac{10}{15}\) > \(\dfrac{9}{15}\)

Vậy \(\dfrac{2}{3}\) mét dài hơn \(\dfrac{3}{5}\) mét

c, \(\dfrac{6}{7}\) kg = \(\dfrac{48}{56}\)kg \(\dfrac{7}{8}\)kg = \(\dfrac{49}{56}\)kg

=> \(\dfrac{48}{56}\)kg < \(\dfrac{49}{56}\)kg

Vậy \(\dfrac{6}{7}\)kg nhỏ hơn \(\dfrac{7}{8}\)

a) BCNN(3,11)=33

Thừa số phụ: 33 : 3 = 11; 33 : 11 = 3

\(\begin{array}{l}\dfrac{5}{3} = \dfrac{{5.11}}{{3.11}} = \dfrac{{55}}{{33}}\\\dfrac{{15}}{{11}} = \dfrac{{15.3}}{{11.3}} = \dfrac{{45}}{{33}}\end{array}\)

Vì \(\dfrac{{55}}{{33}} > \dfrac{{45}}{{33}}\)

Nên \(\dfrac{5}{3}kg > \dfrac{{15}}{{11}}\)kg

b) BCNN(6,5)=30

Thừa số phụ: 30 : 6 = 5; 30 : 5 = 6

\(\begin{array}{l}\dfrac{5}{6} = \dfrac{{5.5}}{{6.5}} = \dfrac{{25}}{{30}}\\\dfrac{4}{5} = \dfrac{{4.6}}{{5.6}} = \dfrac{{24}}{{30}}\end{array}\)

Vì \(\dfrac{{25}}{{30}} > \dfrac{{24}}{{30}}\)

Nên \(\dfrac{5}{6}km/h > \dfrac{4}{5}km/h\) 

7/8>5/6

Ta có: 6/7 kilogam = 48/56 kilogam; 7/8 kilogam = 49/56 kilogam

Vì 

Vậy khối lượng 7/8 kilogam lớn hơn

Viết phần là / đi cho dễ hiểu nhé