=> cái vế  trong ngoặc là 0.

rồi bạn làm tiếp nha

\(\dfrac{-12}{25}.\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)

\(\dfrac{3}{4}-x+\dfrac{-6}{11}-\dfrac{5}{6}=0\)

\(\dfrac{3}{4}-x+\dfrac{-91}{66}=0\)

\(\dfrac{3}{4}-x=0-\left(\dfrac{-91}{66}\right)\)

\(\dfrac{3}{4}-x=\dfrac{91}{66}\)

\(x=\dfrac{-83}{132}\)

a: Ta có: \(-\dfrac{12}{25}\cdot\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)

\(\Leftrightarrow x+\dfrac{83}{132}=0\)

hay \(x=-\dfrac{83}{132}\)

Với B = 3

Ta có: 

a) \(6x+15\times8=12\times\left(19-x\right)\)

\(6x+120=228-12x\)

\(6x+120-228+12x=0\)

\(18x-108=0\)

\(18x=108\)

\(x=6\)

b) \(160-\left(35\div x+3\right)\times15=15\)

\(160-\left(35\div x+3\right)=1\)

\(35\div x+3=159\)

\(35\div x=156\)

\(x=\dfrac{35}{156}\)

c) \(2x-\left(1309\div11-19\right)-2=0\)

\(2x-1309\div11-19=2\)

\(2x-119-19=2\)

\(2x-119=21\)

\(2x=140\)

\(x=70\)

d) \(\left(x-7\right)\times\left(2x-16\right)=0\)

\(x-7=0;2x-16=0\)

\(x=7;2x=16\)

\(x=7;x=8\)

a) $6x+15\times 8=12\times \left(19-x\right)$

$6x+120=228-12x$

$6x+120-228+12x=0$

$18x-108=0$

$18x=108$

$x=6$

b) $160-\left(35÷x+3\right)\times 15=15$

$160-\left(35÷x+3\right)=1$

$35÷x+3=159$

$35÷x=156$

�=35156x=15635​
 

a: x=12

b: x=-19

c)x=-25

d)x=30

\(xx.2+11=x2x\)

tới đó  chắc b cx bik làm rồi nhỉ nhưng đó là cách của mik thoy chứ mik ko bik đúng ko nx

=(( huhu

<=> x = 9/22 + 3/11 = 9/22 + 6/22 = 15/22 

x-3/11=9/22

       x =9/22+6/22

        x=15/22

x = 9/22 + 3/11 = 9/22 + 6/22 = 15/22 

\(x-\dfrac{3}{11}=\dfrac{9}{12}\Rightarrow x=\dfrac{9}{12}+\dfrac{3}{11}=\dfrac{45}{44}\)

x-3/11=9/12

x=9/12+3/11

x=45/44

x-3/11=9/12

x=9/12+3/11

x=45/44

⇒ \(x=\dfrac{23}{5}:\dfrac{8}{11}\)

⇒ \(x=\dfrac{253}{40}\)

=>x^2+x-x+2=11

=>x^2=9

=>x=3 hoặc x=-3

\(x\left(x+1\right)-\left(x-2\right)=11\)

\(\Rightarrow x^2+x-x+2=11\)

\(\Rightarrow x^2+2=11\)

\(\Rightarrow x^2=11-2\)

\(\Rightarrow x^2=9\)

\(\Rightarrow x^2=3^2\)

\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)