a) x²-2x-y²+2y

=(x²-y²)-(2x-2y)

=(x-y)(x+y)-2(x-y)

=(x-y)(x+y-2)

d) x²-25+y²+2xy

=(x²+y²+2xy)-5²

=(x+y)²-5²

=(x+y+5)(x+y-5)

a) \(3x^2-6xy+3y^2-12x^2=3\left(x^2-2xy+y^2\right)-12x^2=3\left(x-y\right)^2-12x^2=3\left[\left(x-y\right)^2-4x^2\right]=3\left(x-y-2x\right)\left(x-y+2x\right)=3\left(-x-y\right)\left(3x-y\right)\)

b)\(3x^2y^2-6x^2y^3+12x^2y^2=3x^2y^2\left(1-2y+4\right)=3x^2y^2\left(5-2y\right)\)

c) \(3x^2-3y^2+12x-12y=3\left(x^2-y^2\right)+12\left(x-y\right)=3\left(x-y\right)\left(x+y+4\right)\)

a: \(3x^2-6xy+3y^2-12x^2\)

\(=3\left(x^2-2xy+y^2-4x^2\right)\)

\(=3\left[\left(x-y\right)^2-4x^2\right]\)

\(=3\left(x-y-2x\right)\left(x-y+2x\right)\)

\(=3\left(-x-y\right)\left(3x-y\right)\)

b: \(3x^2y^2-6x^2y^3+12x^2y^2\)

\(=3x^2y^2\left(1-2y+4\right)\)

\(=3x^2y^2\left(-2y+5\right)\)

c: Ta có: \(3x^2-3y^2+12x-12y\)

\(=3\left(x-y\right)\left(x+y\right)+12\left(x-y\right)\)

\(=3\left(x-y\right)\left(x+y+4\right)\)

3x2 + 6xy + 3y2 – 3z2

= 3.(x2 + 2xy + y2 – z2)

(Nhận thấy xuất hiện x2 + 2xy + y2 là hằng đẳng thức nên ta nhóm với nhau)

= 3[(x2 + 2xy + y2) – z2]

= 3[(x + y)2 – z2]

= 3(x + y – z)(x + y + z)

\(3x^2+6xy+3y^2=3\cdot\left(x^2+2xy+y^2\right)=3\cdot\left(x+y\right)^2\)

3x² + 6xy + 3y² 

=3.(x²+2xy+y²)

=3.(x+y)²

3x^2 - 6xy + 3y^2
=3.(x^2 - 2xy + y^2)
=3.(x - y)^2

a)

\(9x^2-3x+2y-4y^2\\=(9x^2-4y^2)-(3x-2y)\\=[(3x)^2-(2y)^2]-(3x-2y)\\=(3x-2y)(3x+2y)-(3x-2y)\\=(3x-2y)(3x+2y-1)\)

b)

\(3x^2-6xy+3y^2-5x+5y\\=3(x^2-2xy+y^2)-5(x-y)\\=3(x-y)^2-5(x-y)\\=(x-y)[3(x-y)-5]\\=(x-y)(3x-3y-5)\\Toru\)

b, (\(x^2\) - \(xy\) ) + (\(x-y\))

= (\(x-y\)).\(x\) + (\(x-y\))

= (\(x-y\)).(\(x\) + 1)

c, \(x^2\) - 2\(x\) - 15

= (\(x^2\) - 2\(x\) + 1) - 16

= (\(x\) - 1)² - 4²

= (\(x-1-4\)).(\(x-1+4\))

= (\(x-5\)).(\(x+3\))

d, 2\(x^2\) + 3\(x\) - 5

= 2\(x^2\) - 2 + 3\(x\) - 3

= 2.(\(x^2\) - 1) + 3.(\(x-1\))

= 2.(\(x-1\)).(\(x\) + 1) + 3.(\(x-1\))

= (\(x-1\)).(2\(x\) + 2  + 3)

= (\(x\) -1).(2\(x\) + 5)

a/ x² + 4x - 21= x² - 3x +4x - 21

                       = (x²+4x)-(3x+21)

                       = x(x+4)- 3(x+7)

                       = (x-3).(x+7)

 b/ 3x²-6xy+3y²-3z² = 3(x²- 2xy+y²- z²)

                                  = 3[(x² + 2xy + y²) – z²]

                                  = 3[(x + y)² – z²]

                                  = 3(x + y – z)(x + y + z)

  c/ 2x²y + 12xy + 18y = 2y(x²+6x+9)

`@` `\text {Ans}`

`\downarrow`

`a,`

`3x^2 + 6xy + 3y^2 - 3z`

`= 3*x^2 + 3*2xy + 3y^2 - 3z`

`= 3(x^2 + 2xy + y^2 - z)`

`b,`

`x^3 + x^2y - x^2z - xyz`

`= x(x + y)(x-z)`

\(3x^4y-12x^2y^3=3x^2y\left(x^2-4y^2\right)=3x^2y\left(x-2y\right)\left(x+2y\right)\)

\(x^2-y^2-8y-16=x^2-\left(y^2+8y+16\right)=x^2-\left(y+4\right)^2=\left(x+y+4\right)\left(x-y-4\right)\)

\(x^3+3x^2+4x+12=x^2\left(x+3\right)+4\left(x+3\right)=\left(x^2+4\right)\left(x+3\right)\)

\(3x^2-6xy+3y^2-27=3\left[\left(x-y\right)^2-9\right]=3\left(x-y-3\right)\left(x-y+3\right)\)