\(1,\\ a,=4\left(x-2\right)^2+y\left(x-2\right)=\left(4x-8+y\right)\left(x-2\right)\\ b,=3a^2\left(x-y\right)+ab\left(x-y\right)=a\left(3a+b\right)\left(x-y\right)\\ 2,\\ a,=\left(x-y\right)\left[x\left(x-y\right)^2-y-y^2\right]\\ =\left(x-y\right)\left(x^3-2x^2y+xy^2-y-y^2\right)\\ b,=2ax^2\left(x+3\right)+6a\left(x+3\right)\\ =2a\left(x^2+3\right)\left(x+3\right)\\ 3,\\ a,=xy\left(x-y\right)-3\left(x-y\right)=\left(xy-3\right)\left(x-y\right)\\ b,Sửa:3ax^2+3bx^2+ax+bx+5a+5b\\ =3x^2\left(a+b\right)+x\left(a+b\right)+5\left(a+b\right)\\ =\left(3x^2+x+5\right)\left(a+b\right)\\ 4,\\ A=\left(b+3\right)\left(a-b\right)\\ A=\left(1997+3\right)\left(2003-1997\right)=2000\cdot6=12000\\ 5,\\ a,\Leftrightarrow\left(x-2017\right)\left(8x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2017\\x=\dfrac{1}{4}\end{matrix}\right.\\ b,\Leftrightarrow\left(x-1\right)\left(x^2-16\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=4\\x=-4\end{matrix}\right.\)

1A:

a: \(x^3+2x=x\left(x^2+2\right)\)

b: \(3x-6y=3\left(x-2y\right)\)

c: \(5\left(x+3y\right)-15x\left(x+3y\right)\)

\(=5\left(x+3y\right)\left(1-3x\right)\)

d: \(3\left(x-y\right)-5x\left(y-x\right)\)

\(=3\left(x-y\right)+5x\left(x-y\right)\)

\(=\left(x-y\right)\left(5x+3\right)\)

1A. a. x(x²+2) 

b. 3(x-2y)

c. 5(x+3y)(1-3x) 

d. (x-y) (3-5x)

1B. a. 2x(2x-3)

b.xy(x²-2xy+5)

c. 2x(x+1)(x+2)

d. 2x(y-1)+2y(y-1)=2(y-1)(x-y)

1B:

a: \(4x^2-6x=2x\left(2x-3\right)\)

b: \(x^3y-2x^2y^2+5xy\)

\(=xy\left(x^2-2xy+5\right)\)

`5a(x-y)-x+y`

`=5a(x-y)-(x-y)`

`=(x-y)(5a-1)`

\(5a\left(x-y\right)-x+y=\left(x-y\right)\left(5a-1\right)\)

2(x - y) + x - y

= 2(x - y) + (x - y)

= 3(x - y)

\(2\left(x-y\right)+\left(x-y\right)=3\left(x-y\right)\)

\(2\left(x-y\right)+x-y=3\left(x-y\right)\)

Ta có: \(2x\left(x-y\right)+y\left(y-x\right)-\left(y-x\right)\)

\(=2x\left(x-y\right)-y\left(x-y\right)+\left(x-y\right)\)

\(=\left(x-y\right)\left(2x-y+1\right)\)

\(=\left(x\sqrt{y}-y\sqrt{x}\right)+\left(x-y\right)\)

\(=\sqrt{xy}\left(\sqrt{x}-\sqrt{y}\right)+\left(\sqrt{x}-\sqrt{y}\right)\left(\sqrt{x}+\sqrt{y}\right)\)

\(=\left(\sqrt{x}-\sqrt{y}\right)\left(\sqrt{xy}+\sqrt{x}+\sqrt{y}\right)\)

10x(x-y)-(y-x)²

=10x(x-y)+(x-y).(y-x)

=(x-y).(10x+y-x)

=(x-y).(9x+y)

\(10x\left(x-y\right)-\left(y-x\right)^2\)

\(=10x\left(x-y\right)-\left(x-y\right)^2\)

\(=\left(x-y\right)\left(10x-x+y\right)\)

\(=\left(x-y\right)\left(9x+y\right)\)

đề bài có bị thiếu k bạn ?

3x(x-y)+x-y

=3x(x-y)+(x-y)

=(x-y)(3x+1)

\(3x\cdot\left(x-y\right)+x-y\\=3x\cdot\left(x-y\right)+\left(x-y\right)\\ =\left(x-y\right)\left(3x+1\right)\)