Tìm GTNN
A = \(\dfrac{x+3\sqrt{x}+11}{\sqrt{x}+1}\)
Với mọi x ≥ 0
Tìm GTNN
A = \(\dfrac{x+6\sqrt{x}+14}{\sqrt{x}+1}+2022\)
Với mọi x ≥ 0.
Tìm GTNN
a) \(y=\sqrt{x^3+2\left(1+\sqrt{x^3+1}\right)}+\sqrt{x^3+2\left(1-\sqrt{x^3+1}\right)}\)
b) \(f\left(x\right)=\dfrac{x}{2}+\dfrac{2}{x-1}\) với x>1
c) \(y=\dfrac{x-2017}{\sqrt{x-2018}}\)
a. ĐKXĐ: \(x\ge-1\)
\(y=\sqrt{x^3+1+2\sqrt{x^3+1}+1}+\sqrt{x^3+1-2\sqrt{x^3+1}+1}\)
\(=\sqrt{\left(\sqrt{x^3+1}+1\right)^2}+\sqrt{\left(\sqrt{x^3+1}-1\right)^2}\)
\(=\left|\sqrt{x^3+1}+1\right|+\left|1-\sqrt{x^3+1}\right|\ge\left|\sqrt{x^3+1}+1+1-\sqrt{x^3+1}\right|=2\)
b.
\(f\left(x\right)=\dfrac{x-1}{2}+\dfrac{2}{x-1}+\dfrac{1}{2}\ge2\sqrt{\dfrac{2\left(x-1\right)}{2\left(x-1\right)}}+\dfrac{1}{2}=\dfrac{5}{2}\)
c.
\(y=\dfrac{x-2018+1}{\sqrt{x-2018}}=\sqrt{x-2018}+\dfrac{1}{\sqrt{x-2018}}\ge2\sqrt{\dfrac{\sqrt{x-2018}}{\sqrt{x-2018}}}=2\)
Tìm GTNN
a)\(\sqrt{x-2\sqrt{x-3}}\)
b)\(\sqrt{x^{2}+2y^{2}-6x+4y+11 }+\sqrt{x^{2}+3y^{2}+2x+6y+4 }\)
a: \(=\sqrt{x-3-2\sqrt{x-3}+3}\)
\(=\sqrt{x-3-2\sqrt{x-3}+1+2}=\sqrt{\left(\sqrt{x-3}-1\right)^2+2}>=\sqrt{2}\)
Dấu = xảy ra khi x-3=1
=>x=4
cho biểu thức P=\(\dfrac{2\sqrt{x}}{\sqrt{x}+3}+\dfrac{\sqrt{x}+1}{\sqrt{x}-3}+\dfrac{3-11\sqrt{x}}{9-x}\) với x\(\ge\)0; x\(\ne\)9
1.tìm ĐKXĐ và rút gọn P
2.tính P khi x=7+2\(\sqrt{3}\)
3.tìm x để P<1
P=\(\dfrac{15\sqrt{x}-11}{x+2\sqrt{x}-3}-\dfrac{3\sqrt{x}-2}{1-\sqrt{x}}-\dfrac{2\sqrt{x}+3}{3+\sqrt{x}}\) với x\(\ge\) 0;x\(\ne\) 1
a) rút gọn BT
B)tím P khi x=9
C) tìm x khi P=\(\dfrac{1}{2}\)
D)tìm x đẻ P g trị nguyên
a: \(P=\dfrac{15\sqrt{x}-11+\left(3\sqrt{x}-2\right)\left(\sqrt{x}+3\right)-\left(2\sqrt{x}+3\right)\left(\sqrt{x}-1\right)}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-1\right)}\)
\(=\dfrac{15\sqrt{x}-11+3x+7\sqrt{x}-6-2x-\sqrt{x}+3}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-1\right)}\)
\(=\dfrac{x+21\sqrt{x}-14}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-1\right)}\)
b: Khi x=9 thì \(P=\dfrac{9+21\cdot3-14}{\left(3+3\right)\left(3-1\right)}=\dfrac{29}{6}\)
cho biểu thức:
P=\(\left(\dfrac{1}{\sqrt{x}-1}-\dfrac{2\sqrt{x}}{x\sqrt{x}-x+\sqrt{x}-1}\right)\)\(:\left(\dfrac{x+\sqrt{x}}{x\sqrt{x}+x+\sqrt{x}+1}+\dfrac{1}{x+1}\right)\)
với x\(\ge\)0;x\(\ne\)1
1)Rút gọn P
2)Tìm x để P<\(\dfrac{1}{2}\)
3) tìm m để phương trình (\(\sqrt{x}+1\))P= m-x có nghiệm x
1: \(P=\dfrac{x+1-2\sqrt{x}}{\left(\sqrt{x}-1\right)\left(x+1\right)}:\dfrac{x+\sqrt{x}+\sqrt{x}+1}{\left(x+1\right)\left(\sqrt{x}+1\right)}\)
\(=\dfrac{\sqrt{x}-1}{x+1}\cdot\dfrac{\left(x+1\right)\left(\sqrt{x}+1\right)}{\left(\sqrt{x}+1\right)\left(x+1\right)}=\dfrac{\sqrt{x}-1}{x+1}\)
2: P<1/2
=>P-1/2<0
=>\(2\sqrt{x}-2-x-1< 0\)
=>-x+2căn x-1<0
=>(căn x-1)^2>0(luôn đúng)
cho biểu thuwcsl A= \(\dfrac{2\sqrt{x}}{\sqrt{x}+3}+\dfrac{\sqrt{x}+1}{\sqrt{x}-3}-\dfrac{3-11\sqrt{x}}{x-9}\)với x≥0,x≠9
a) chứng minh A=\(\dfrac{3\sqrt{x}}{\sqrt{x}-3}\)
b) tính giá trị của A khi x=36
c) tìm x để A<\(\dfrac{1}{2}\)
a: \(A=\dfrac{2x-6\sqrt{x}+x+4\sqrt{x}+3-3+11\sqrt{x}}{x-9}\)
\(=\dfrac{3\sqrt{x}}{\sqrt{x}-3}\)
Cho các biểu thức: A = \(\dfrac{2\sqrt{x}}{\sqrt{x}+3}\) và B = \(\dfrac{\sqrt{x}-1}{\sqrt{x}-3}+\dfrac{11\sqrt{x}-3}{x-9}\) với x≥0; x≠9
a. M = A + B
b. Tìm x sao cho M = \(M^4\)
a: \(M=A+B=\dfrac{2\sqrt{x}}{\sqrt{x}+3}+\dfrac{\sqrt{x}-1}{\sqrt{x}-3}+\dfrac{11\sqrt{x}-3}{x-9}\)
\(=\dfrac{2x-6\sqrt{x}+x+2\sqrt{x}-3+11\sqrt{x}-3}{x-9}\)
\(=\dfrac{3x+7\sqrt{x}-6}{x-9}\)
\(=\dfrac{3x+9\sqrt{x}-2\sqrt{x}-6}{x-9}=\dfrac{3\sqrt{x}-2}{\sqrt{x}-3}\)
b: M=M^4
=>M=0 hoặc M=1
=>3 căn x-2=căn x-3 hoặc 3 căn x-2=0
=>x=4/9
1) cho biểu thức A= \(\dfrac{2\sqrt{x}}{\sqrt{x}+3}+\dfrac{\sqrt{x}+1}{\sqrt{x}-3}-\dfrac{3-11\sqrt{x}}{9-x}\)
B= \(\dfrac{\sqrt{x}-3}{\sqrt{x}+1}\) với \(0\le x\ne9\)
b) rút gọn A
c) tìm số nguyên x để P= A. B là số nguyên
giúp mk vs ah mk cần gấp lắm
\(A=\dfrac{2\sqrt{x}\left(\sqrt{x}-3\right)}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}+\dfrac{\left(\sqrt{x}+3\right)\left(\sqrt{x}+1\right)}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}+\dfrac{3-11\sqrt{x}}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}\)\(A=\dfrac{2x-6\sqrt{x}+x+\sqrt{x+}3\sqrt{x}+3+3-11\sqrt{x}}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}\)\(A=\dfrac{3x-13\sqrt{x}+6}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}\)