a) Ta có: \(\dfrac{x}{3}=\dfrac{7}{25}+\dfrac{-1}{5}\)

\(\Leftrightarrow\dfrac{x}{3}=\dfrac{7}{25}+\dfrac{-5}{25}=\dfrac{2}{25}\)

hay \(x=\dfrac{6}{25}\)

Vậy: \(x=\dfrac{6}{25}\)

b) Ta có: \(\dfrac{4}{9}+\dfrac{x}{5}=\dfrac{5}{11}\)

\(\Leftrightarrow\dfrac{x}{5}=\dfrac{5}{11}-\dfrac{4}{9}=\dfrac{45}{99}-\dfrac{44}{99}=\dfrac{1}{99}\)

hay \(x=\dfrac{5}{99}\)

Vậy: \(x=\dfrac{5}{99}\)

c) Ta có: \(\dfrac{-5}{9}+\dfrac{x}{10}=\dfrac{1}{3}\)

\(\Leftrightarrow\dfrac{x}{10}=\dfrac{1}{3}+\dfrac{5}{9}=\dfrac{3}{9}+\dfrac{5}{9}=\dfrac{8}{9}\)

hay \(x=\dfrac{80}{9}\)

Vậy: \(x=\dfrac{80}{9}\)

Bài 2:

a: -2*(-27)=54

6*9=54

=>Hai phân số này bằng nhau

b: -1/-5=1/5=5/25<>4/25

Bài 3:

a: =>16/x=-4/5

=>x=-20

b: =>(x+7)/15=-2/3

=>x+7=-10

=>x=-17

a) \(\dfrac{-2}{9}\) và \(\dfrac{6}{-27}\)

\(\dfrac{6}{-27}=\dfrac{6:\left(-3\right)}{\left(-27\right):\left(-3\right)}=\dfrac{-2}{9}\)

Vậy \(\dfrac{-2}{9}=\dfrac{6}{-27}\)

b) \(\dfrac{-1}{-5}\) và \(\dfrac{4}{25}\)

\(\dfrac{-1}{-5}=\dfrac{\left(-1\right).\left(-5\right)}{\left(-5\right).\left(-5\right)}=\dfrac{5}{25}\)

Do \(5\ne4\Rightarrow\dfrac{5}{25}\ne\dfrac{4}{25}\)

Vậy \(\dfrac{-1}{-5}\ne\dfrac{4}{25}\)

Bài 3

a) \(\dfrac{-28}{35}=\dfrac{16}{x}\)

\(x=\dfrac{35.16}{-28}\)

\(x=-20\)

b) \(\dfrac{x+7}{15}=\dfrac{-24}{36}\)

\(\left(x+7\right).36=15.\left(-24\right)\)

\(36x+252=-360\)

\(36x=-360-252\)

\(36x=-612\)

\(x=\dfrac{-612}{36}\)

\(x=-17\)

b: =>x(8-7)=-33

=>x=-33

c: =>-12x+60+21-7x=5

=>-19x=-76

hay x=4

d: =>-2x-2-x+5+2x=0

=>3-x=0

hay x=3

b. -6x=18

=> x = 18 : (-6)

=> x = -3

c. 35-3.|x|=5.(2³-4)

=> 35-3.|x|=5.(8-4)

=> 35-3.|x|=5.4

=> 35-3.|x|=20

=> 3.|x|=35-20

=> 3.|x|=15

=> |x|=5

=> x \(\in\){-5; 5}

d. => 10+2.|x|=2.(9-1)

=> 10+2.|x|=2.8

=> 10+2.|x|=16

=> 2.|x|=16-10

=> 2.|x|=6

=> |x|=3

=> x \(\in\){-3; 3}

a. 9 - 25 = ( 7 - x ) - ( 25 + 7 )

=> -16 = 7 - x - 32

=> x = 7 - 32 + 16

=> x = -9.

9-25=(7-x)-(25+7)
9-25=7-x-25-7
=> 9-25-7+25+7=-x
=> x=-9 

a: 9-25=7-x-(25+7)

=>7-x-25-7=-16

=>-x-25=-16

=>x+25=16

hay x=-9

b: \(10+2\left|x\right|=2\cdot\left(3^2-1\right)\)

\(\Leftrightarrow2\left|x\right|=2\cdot8-10=6\)

=>x=3 hoặc x=-3

c: -6x=18

nên x=18:(-6)=-3

b) -6x = 18

       x = 18 : (-6)

       x = -3

c) x . 2 = 4

         x = 4 : 2

          x = 2

mik mới học lớp 5 nên chỉ biết ít về lớp 6

Tìm số nguyên x , biết :

a) 9-25=(7-x)-(25+7)

    9 - 25 = (7 - x )- 32

     -16 = (7 -x)-32

        7-x= -16 - 32

        7-x = -48

          x = 7 -(-48)

          x = 55

b)-6x=18

 x = -( 18 :6)

x = -3

c)x.2=4

  x = 4 : 2

  x = 2

Mình không biết có đúng không nữa nhưng mk mong bạn sẽ k mk

a) 9-25=(7-x)-(25+7)

    9-25=(7-x)-32

    9-25=7-x-32

    x=7-32-9+25

    x=(-9)

b)-6x=18

     x=18:(-6)

      x=(-3)

c)x.2=4

   2x=4

     x=4:2

     x=2

a,11-(15+21)=x-(25-9)

      11-15-21=x-25+9

               -x=-25+9-11+15+21

               -x=9

                x=-9

b,9-25=(7-x)-(25+7)

    -16=7-x-32

      x=7-32+16

     x=-9

a) x= + - 5
b) x\(\in\)\(\left\{-1;-7\right\}\)

a/ \(x^2-25=0\)

\(\Rightarrow\left(x+5\right)\left(x-5\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x+5=0\Rightarrow x=-5\\x-5=0\Rightarrow x=5\end{matrix}\right.\)

b/ \(x\left(x+7\right)+x+7=0\)

\(x\left(x+7\right)+\left(x+7\right)=0\)

\(\left(x+7\right)\left(x+1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x+7=0\Rightarrow x=-7\\x+1=0\Rightarrow x=-1\end{matrix}\right.\)

a) x^2 - 25 = 0 <=> (x + 5)(x - 5) = 0

<=> x = -5 hoặc x = 5

b) x(x + 7) + x + 7 = 0 <=> (x + 7)(x + 1) = 0

<=> x = -7 hoặc x = -1