\(-4x^2+20-16x+4x^2=-3\)

\(\left(-4x^2+4x^2\right)-16x=-3-20\)

\(0-16x=-23\)

\(x=\frac{23}{16}\)

CHÚC BN HX TỐT :))

\(-4x\left(x-5\right)-2x\left(8-2x\right)=-3\)

\(\Leftrightarrow-4x^2+20x-16x+4x^2=-3\)

\(\Leftrightarrow4x=-3\Leftrightarrow x=-\frac{3}{4}\)

-4x(x-5)-2x(8-2x)=-3

có:-4x^2+20x-4x^2-16x=-3

     (-4x^2+4x^2)+(20x-16x)=-3

                                        4x=-3

suy ra:x=-3/4

Thanks

-4x(x-5)-2x(8-2x)=-3

-4x^2+20x-16x+4x^2=-3

4x=-3

x=-3/4

<=>(-4)x(x-5)-2x(8-2x)=4x

=>4x=-3

=>x=\(-\frac{3}{4}\)

-4x(x-5)-2x(8-2x)=-3

=>-4x-(-20)-16-4x=-3

=>-4x+20-4x=-3+16

=>-4x-4x=13-20

=>-8x=-7

=>x=(-7):(-8)

=>x=0,875

-4x(x-5)-2x(8-2x)=3

-4x²-(-4)x5-2x(8-2x)=3

-4x²+20x-2x(8-2x)=3

-4x²+20x-2x8+2x2x=3

-4x²+20x-16x+4x²=3

(-4x²+4x²)+(20x-16x)=3

4x=3

x=3:4

x=3/4

ý, ghi nhầm -3 thành 3 rồi, kết 

kết quả đúng là -3/4

\(a.x=-0,6\)

\(c.x=-11,6\)

Pt nhju ak!!!

a) 2x+8≤ 0 

⇔2x≤-8

⇔x≤-4

b) 4x-7 ≥ 2x -5

⇔2x-12 ≥ 0

⇔2x≥12

⇔x≥6

c) (2x-8)(15-3x)>0

TH1: 2x-8>0 ⇒x>4

        15-3x>0⇒x<5 

TH2:  2x-8<0 ⇒x<4

        15-3x<0⇒x>5 (vô lí)

vậy 4<x<5

\(a,\Leftrightarrow\dfrac{3x^3+6x^2-3x-5x^2-10x+5}{x^2+2x-1}=10\\ \Leftrightarrow\dfrac{3x\left(x^2+2x-1\right)-5\left(x^2+2x-1\right)}{x^2+2x-1}=10\\ \Leftrightarrow3x-5=10\Leftrightarrow3x=15\Leftrightarrow x=5\\ b,\Leftrightarrow\left(x^4+2x^2-4x^2-8\right):\left(x-2\right)=0\\ \Leftrightarrow\left[\left(x^2-4\right)\left(x^2+2\right)\right]:\left(x-2\right)=0\\ \Leftrightarrow\left[\left(x-2\right)\left(x+2\right)\left(x^2+2\right)\right]:\left(x-2\right)=0\\ \Leftrightarrow\left(x+2\right)\left(x^2+2\right)=0\Leftrightarrow x=-2\left(x^2+2>0\right)\\ c,\Leftrightarrow\dfrac{x\left(x-4\right)}{\left(x-4\right)^2}=0\Leftrightarrow\dfrac{x}{x-4}=0\Leftrightarrow x=0\)

b: \(\Leftrightarrow x^4-4x^2+2x^2-8=0\)

hay x=-2