Bài 1:

a: Sửa đề: 1/3^200

1/2^300=(1/8)^100

1/3^200=(1/9)^100

mà 1/8>1/9

nên 1/2^300>1/3^200

b: 1/5^199>1/5^200=1/25^100

1/3^300=1/27^100

mà 25^100<27^100

nên 1/5^199>1/3^300

\(2^{300}=\left(2^3\right)^{100}=8^{100}\\ 3^{200}=\left(3^2\right)^{100}=9^{100}\\ Vì:8^{100}< 9^{100}\Rightarrow2^{300}< 3^{200}\)

\(2^{300}=\left(2^3\right)^{100}=8^{100}\)

\(3^{200}=\left(3^2\right)^{100}=9^{100}>8^{100}\)

\(\Rightarrow2^{300}< 3^{200}\)

`@` `\text {Ans}`

`\downarrow`

Ta có:

\(2^{300}=\left(2^3\right)^{100}=8^{100}\)

\(3^{200}=\left(3^2\right)^{100}=9^{100}\)

Vì `8 < 9 \Rightarrow `\(8^{100}< 9^{100}\)

`\Rightarrow `\(2^{300}< 3^{200}\)

___

`@` So sánh `2` lũy thừa cùng số mũ:

`a^m > b^m` khi `a > b.`

\(2^{300}=\left(2^3\right)^{100}=8^{100}\)

\(3^{200}=\left(3^2\right)^{100}=9^{100}\)

mà \(8^{100}< 9^{100}\left(8< 9\right)\)

nên \(2^{300}< 3^{200}\)

2\(^{300}\)<3\(^{300}\)

`a)2^{300}=(2^3)^100=8^100`

`3^200=(3^2)^100=9^100`

Vì `9^100>8^100`

`=>2^300<3^200`

`b)3xx24^10`

`=3.(3.8)^10`

`=3^{11}.8^10`

`=3^{11}.2^30`

`2^300=2^{30}.2^{270}`

`=2^{30}.8^{90}`

Vì `3^11<8^90`

`=>3^{11}.2^30<8^{90}.2^30=2^300`

`=>3xx24^{10}<2^300+3^20+4^30`

a.

\(3^{200}=\left(3^2\right)^{100}=9^{100}>8^{100}=\left(2^3\right)^{100}=2^{300}\)

Vậy \(3^{200}>2^{300}\)

b.

\(5^{200}=\left(5^2\right)^{100}=25^{100}< 32^{100}=\left(2^5\right)^{100}=2^{500}\)

Vậy \(5^{200}< 2^{500}\)

Ta có : \(3^{200}=3^{2.100}=\left(3^2\right)^{100}=9^{100}\)

\(2^{300}=2^{3.100}=\left(2^3\right)^{100}=8^{100}\)

\(\Rightarrow9^{100}>8^{100}\)

\(\Rightarrow3^{200}>2^{300}\)

Ta có : \(5^{200}=5^{2.100}=\left(5^2\right)^{100}=25^{100}\)

\(2^{500}=2^{5.100}=\left(2^5\right)^{100}=32^{100}\)

\(\Rightarrow25^{100}< 32^{100}\)

\(\Rightarrow5^{200}< 2^{500}\)

ta có :

2³⁰⁰=(2³)¹⁰⁰=8¹⁰⁰

3²⁰⁰=(3²)¹⁰⁰=9¹⁰⁰

vì 8¹⁰⁰<9¹⁰⁰ nên 2³⁰⁰<3²⁰⁰

\(2^{300}=\left(2^3\right)^{100}\) \(\Rightarrow8^{100}\)

\(3^{200}=\left(3^2\right)^{100}\) \(\Rightarrow9^{100}\)

\(\Rightarrow8^{100}<9^{100}\)\(\Leftrightarrow2^{300}<3^{200}\)

2 ³⁰⁰ = [2³]¹⁰⁰ = 8¹⁰⁰

3²⁰⁰ = [3²]¹⁰⁰ = 9¹⁰⁰

vì 8 < 9 nên 2³⁰⁰ < 3²⁰⁰

TC:(1/2)^300=(1/8)^100

     (1/3)^200=(1/9)^100

     Vì (1/8)^100>(1/9)^100  =>(1/2)^300 >(1/3)^200

3²⁰⁰ = 3^2.100 =  9¹⁰⁰  (1)

2³⁰⁰ = 2^3.100 = 8¹⁰⁰  (2)

Từ (1) và(2) ta có: 3²⁰⁰>2³⁰⁰

3²⁰⁰ = 3^2.100 = (3²)¹⁰⁰ = 9¹⁰⁰

2³⁰⁰ = 2^3.100 = (2³)¹⁰⁰ = 8¹⁰⁰

9¹⁰⁰ > 8¹⁰⁰ ( vì 9 > 8 ) nên 3²⁰⁰ > 2³⁰⁰.

\(3^{200}=\left(3^2\right)^{100}=9^{100}>8^{100}=\left(2^3\right)^{100}=2^{300}\)

\(=>3^{200}>2^{300}\)