a) 570 - 225 - 167 + 67

= 345 - 167 + 67

= 178 + 67

= 245

168 x 2 : 6 x 4

= 336 : 6 x 4

= 56 x 4

= 224

b) 468 : 6 + 61 x 2

= 78 + 122

= 200

5625 - 5000 : (726 : 6 - 113)

=5625-5000:(121-113)

=5625-5000:8

=5625-625

=5000

a) \(2x-x^2-4=-\left(x^2-2x+1\right)-3\)

\(=-\left(x-1\right)^2-3\le-3\)

Dấu "=" xảy ra \(\Leftrightarrow x=1\)

b) \(-9x^2+24x-18=-\left(9x^2-24x+16\right)-2\)

\(=-\left(3x-4\right)^2-2\le-2\)

Dấu "=" xảy ra \(\Leftrightarrow x=\dfrac{4}{3}\)

a) \(2x-x^2-4\)

\(-x^2+2x-4\)

\(-\left(x^2-2x+1\right)-3\)

 \(-\left(x-1\right)^2-3\text{ }\text{≤}-3\)

Min =-3 ⇔\(-\left(x-1\right)^2=0\)

               ⇔\(x-1=0\)

               ⇔\(x=1\)

a) 7,89

b) 2398 

c) 58,85 

d) 14 

\(\text{a. 78,9 : 2,5 : 4. }\)

\(=31,56:4=7,89.\)

\(\text{ b. 56,75 + 8,4 : 4}.\)

\(=56,75+2,1=58,85.\)

\(\text{c. 23,6 x 100 + 2,9 : 0,1. }\)

\(=2360+29=2389.\)

\(\text{ d. 58 - 4,4 : 0,1}.\)

\(=58-44=14.\)

a) 7,89

b) 2398 

c) 58,85 

d) 14 

\(A=\dfrac{x-4+5}{\sqrt{x}-2}=\dfrac{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)+5}{\sqrt{x}-2}=\sqrt{x}+2+\dfrac{5}{\sqrt{x}-2}\)

\(=\sqrt{x}-2+\dfrac{5}{\sqrt{x}-2}+4\ge2\sqrt{\dfrac{5\left(\sqrt{x}-2\right)}{\sqrt{x}-2}}+4=4+2\sqrt{5}\)

\(A_{min}=4+2\sqrt{5}\) khi \(9+4\sqrt{5}\)

b.

Đặt \(\left(a;b;c\right)=\left(\dfrac{1}{x};\dfrac{1}{y};\dfrac{l}{z}\right)\Rightarrow xyz=1\)

\(B=\dfrac{x^2}{y+z}+\dfrac{y^2}{z+x}+\dfrac{z^2}{x+y}\ge\dfrac{\left(x+y+z\right)^2}{2\left(x+y+z\right)}=\dfrac{x+y+z}{2}\ge\dfrac{3\sqrt[3]{xyz}}{2}=\dfrac{3}{2}\)

\(B_{min}=\dfrac{3}{2}\) khi \(x=y=z=1\Rightarrow a=b=c=1\)

\(a,A=\dfrac{x+\sqrt{x}+2+\sqrt{x}-2}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}=\dfrac{\sqrt{x}\left(\sqrt{x}+2\right)}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}=\dfrac{\sqrt{x}}{\sqrt{x}-2}\\ b,x=36\Leftrightarrow A=\dfrac{6}{6-2}=\dfrac{6}{4}=\dfrac{3}{2}\\ c,A=-\dfrac{1}{3}\Leftrightarrow\dfrac{\sqrt{x}}{\sqrt{x}-2}=-\dfrac{1}{3}\Leftrightarrow3\sqrt{x}=2-\sqrt{x}\\ \Leftrightarrow\sqrt{x}=\dfrac{1}{2}\Leftrightarrow x=\dfrac{1}{4}\left(tm\right)\\ d,A\in Z\Leftrightarrow1+\dfrac{2}{\sqrt{x}-2}\in Z\\ \Leftrightarrow\sqrt{x}-2\inƯ\left(2\right)=\left\{-2;-1;1;2\right\}\\ \Leftrightarrow\sqrt{x}\in\left\{0;1;3;4\right\}\\ \Leftrightarrow x\in\left\{0;1;9;16\right\}\)

\(e,A:B=\dfrac{\sqrt{x}}{\sqrt{x}-2}\cdot\dfrac{\sqrt{x}-2}{\sqrt{x}+1}=\dfrac{\sqrt{x}}{\sqrt{x}+1}=-2\\ \Leftrightarrow\sqrt{x}=-2\sqrt{x}-2\\ \Leftrightarrow\sqrt{x}=-\dfrac{2}{3}\left(ktm\right)\\ \Leftrightarrow x\in\varnothing\)

a: Ta có: \(A=\dfrac{x}{x-4}+\dfrac{1}{\sqrt{x}-2}+\dfrac{1}{\sqrt{x}+2}\)

\(=\dfrac{x+\sqrt{x}+2+\sqrt{x}-2}{x-4}\)

\(=\dfrac{\sqrt{x}}{\sqrt{x}-2}\)

a) thay x=4 và y=5 vào biểu thức ta đc :129

b) tương tự....To be continued

a:\(A=x^2+2xy-3x^3+2y^3+3x^3-y^3\)

\(=x^2+2xy+y^3\)

\(=5^2+2\cdot5\cdot4+4^3\)

\(=25+40+64=129\)

Thay x = 4 vào biểu thức ta được 

( − 75 ) . ( − 25 ) .4 = ( − 75 ) . ( − 100 ) = 7500

a)-19

b)22