a  21-4x=13
  -4x=13-21
-4x=-8
x=-8/-4
x=2
 

b x=5

  chúc bạn học tốt

cần kết quả đúng ko 

a: =>x>5

a, 35 - \(x\) < 35 - 5

    35 - \(x\) < 30

           \(x\) < 35 - 30

           \(x\) < 5

\(x\) = 1; 2; 3; 4; 5

b, \(x\) - 10 < 35 - 10

    \(x\) - 10 < 15

   \(x\)         < 15 + 10

   \(x\)        < 25

   \(x\) = 0; 1; 2; 3; 4; 5; ....;24

c, \(x\) - 10 < 45

    \(x\)        < 45 + 10

    \(x\)         < 55

   \(x\) = 0; 1; 2; 3; 4;...;54

a) \(128-3\left(x+4\right)=23\)

\(\Rightarrow3\left(x+4\right)=128-23\)

\(\Rightarrow3\left(x+4\right)=105\)

\(\Rightarrow x+4=35\)

\(\Rightarrow x=35-4\)

\(\Rightarrow x=31\)

b) \(\left[\left(4x+28\right)\cdot3+55\right]:5=35\)

\(\Rightarrow\left(4x+28\right)\cdot3+55=35\cdot5\)

\(\Rightarrow\left(4x+28\right)\cdot3+55=175\)

\(\Rightarrow\left(4x+28\right)\cdot3=120\)

\(\Rightarrow4x+28=40\)

\(\Rightarrow4x=12\)

\(\Rightarrow x=3\)

a, \(128-3\left(x+4\right)=23\)

\(=>3\left(x+4\right)=128-23\)

\(=>3\left(x+4\right)=105\)

\(=>x+4=105:3\)

\(=>x+4=35\)

\(=>x=35-4\)

\(=>x=31\)

b, \(\left[\left(4x+28\right).3+55\right]:5=35\)

\(=>\left(4x+28\right).3+55=35.5\)

\(=>\left(4x+28\right).3+55=175\)

\(=>\left(4x+28\right).3=175-55\)

\(=>\left(4x+28\right).3=120\)

\(=>4x+28=120:3\)

\(=>4x+28=40\)

\(=>4x=40-28\)

\(=>4x=12\)

\(=>x=12:4\)

\(=>x=3\)

\(#WendyDang\)

a) 128 - 3 (x + 4) =23

      3.( x + 4) = 128 -23

      3. ( x + 4) =  105

      x + 4 = 105 :3

      x + 4 =  35

      x = 35 -4

     x = 31

a) 150- x = -9

x = 150 -(-9)

x=150+9

x=159

b)4 (x-3)=48

x-3=48÷4

x-3=12

x=12+3

x=15

Bài 13: 

a: =>20-x=15-8+13=20

hay x=0

a: =>3x-9+26 chia hết cho x-3

=>\(x-3\in\left\{1;-1;2;-2;13;-13;26;-26\right\}\)

=>\(x\in\left\{4;2;5;1;16;-10;29;-23\right\}\)

b: =>6x+38 chia hết cho 2x-3

=>6x-9+47 chia hết cho 2x-3

=>\(2x-3\in\left\{1;-1;47;-47\right\}\)

=>\(x\in\left\{2;1;25;-22\right\}\)

c: Ta có: 11+x:5=13

\(\Leftrightarrow x:5=2\)

hay x=10

d: Ta có: \(13+2\left(x+1\right)=15\)

\(\Leftrightarrow2x+2=2\)

\(\Leftrightarrow2x=0\)

hay x=0

e: Ta có: 2x+21=41

\(\Leftrightarrow2x=20\)

hay x=10

f: Ta có: \(12+3\left(x-2\right)=60\)

\(\Leftrightarrow3\left(x-2\right)=48\)

\(\Leftrightarrow x-2=16\)

hay x=18

g: Ta có: \(24x-11\cdot13=11\cdot11\)

\(\Leftrightarrow24x=11\cdot24\)

hay x=11

h: Ta có: \(17-\left(x-4\right):2=3\)

\(\Leftrightarrow\left(x-4\right):2=14\)

\(\Leftrightarrow x-4=28\)

hay x=32