( 26 - 12 )+( x + 5 ) = 14 - ( 2x - 6 )

14 + ( x + 5 )           = 14 - ( 2x - 6 )

=> x + 5                   = 2x - 6

     x                         = 2x - 6 - 5 

     x                         = 2x - 1

( 26 - 12 )+( x + 5 ) = 14 - ( 2x - 6 )

14 + x + 5 = 14 - 2x + 6

14 - 14 + x + 2x = -5 + 6

3x = 1

x =\(\frac{1}{3}\)

(26-12)+(x+5)=14-(2x-6)

=>14+x+5=14-2x+6

=>19+x=20-2x

=>19+3x=20

=>3x=1

=>x=1/3

\(\left(2x-14\right):12=26\)

\(2x-14=26.12\)

\(2x-14=312\)

\(2x=312+14\)

\(2x=326\)

\(x=326:2\)

\(x=163\)

2x-14=26*12

2x-14=312 

2x=312-14

2x=298

x= 298:2

x=149

x = 163

a: x+(-14)=26

=>x-14=26

=>x=26+14=40

b: 4-x=(-12)+8²

=>4-x=-12+64=52

=>x=4-52=-48

c: \(2x+14=\left(-3\right)+\left(-15\right)\)

=>2x+14=-3-15=-18

=>2x=-18-14=-32

=>x=-32/2=-16

a, x + (-14) = 26

=> x = 40

b, 4 - x = (-12) + 8² 

=> 4 - x = (-12) + 64 = 52

=> x = -48

c, 2x + 14 = (-3) + (-15)

=> 2x + 14 = -18

=> 2x = -32 => x = -16

a: x+(-14)=26

=>x-14=26

=>x=26+14=40

b: 4-x=(-12)+8²

=>4-x=-12+64=52

=>x=4-52=-48

c: 

=>2x+14=-3-15=-18

=>2x=-18-14=-32

=>x=-32/2=-16

2: x=3

3: x=18

1) \(x=51\)

2) \(x=3\)

3) \(x=18\)

4) \(x=2\)

5) \(x=7\)

a) \(\frac{-x}{2}+\frac{2x}{3}+x+\frac{1}{4}+2x+\frac{1}{6}=\frac{3}{8}.\)

\(\frac{-x}{2}+\frac{2x}{3}+3x+\frac{5}{12}=\frac{3}{8}\)

\(x.\left(-\frac{1}{2}+\frac{2}{3}+3\right)+\frac{5}{12}=\frac{3}{8}\)

\(x\cdot\frac{19}{6}=-\frac{1}{24}\)

x = -1/76

b) \(\frac{3}{2x+1}+\frac{10}{4x+2}-\frac{6}{6x+3}=\frac{12}{26}\)

\(\frac{3}{2x+1}+\frac{2.5}{2.\left(2x+1\right)}-\frac{2.3}{3.\left(2x+1\right)}=\frac{6}{13}\)

\(\frac{3}{2x+1}+\frac{5}{2x+1}-\frac{2}{2x+1}=\frac{6}{13}\)

\(\frac{3+5-2}{2x+1}=\frac{6}{13}\)

\(\frac{6}{2x+1}=\frac{6}{13}\)

=> 2x + 1 = 13

2x = 12

x = 6

\(a,-\dfrac{x}{2}+\dfrac{2x}{3}+\dfrac{x+1}{4}+\dfrac{2x+1}{6}=\dfrac{8}{3}\)

\(\Rightarrow-\dfrac{6x}{12}+\dfrac{8x}{12}+\dfrac{3\left(x+1\right)}{12}+\dfrac{2\left(2x+1\right)}{12}=\dfrac{8}{3}\)

\(\Rightarrow\dfrac{-6x+8x+3x+3+4x+2}{12}=\dfrac{8}{3}\)

\(\Rightarrow\dfrac{9x+5}{12}=\dfrac{8}{3}\)

\(\Rightarrow27x+15=96\)

\(\Rightarrow27x=81\)

\(\Rightarrow x=3\left(tm\right)\)

\(b,\dfrac{3}{2x+1}+\dfrac{10}{4x+2}-\dfrac{6}{6x+3}=\dfrac{12}{26}\)

\(\Rightarrow\dfrac{3}{2x+1}+\dfrac{10}{2\left(2x+1\right)}-\dfrac{6}{3\left(2x+1\right)}=\dfrac{6}{13}\)

\(\Rightarrow\dfrac{3}{2x+1}+\dfrac{5}{2x+1}-\dfrac{2}{2x+1}=\dfrac{6}{13}\)

\(\Rightarrow\dfrac{3+5-2}{2x+1}=\dfrac{6}{13}\)

\(\Rightarrow\dfrac{6}{2x+1}=\dfrac{6}{13}\)

\(\Rightarrow2x+1=13\)

\(\Rightarrow2x=12\)

\(\Rightarrow x=6\left(tm\right)\)

#Toru

a) \(-\dfrac{x}{2}+\dfrac{2x}{3}+\dfrac{x+1}{4}+\dfrac{2x+2}{6}=\dfrac{8}{3}\) 

\(\Rightarrow\dfrac{-6x}{12}+\dfrac{8x}{12}+\dfrac{3\left(x+1\right)}{12}+\dfrac{2\left(2x+1\right)}{12}=\dfrac{4\cdot8}{12}\)

\(\Rightarrow-6x+8x+3x+3+4x+2=32\)

\(\Rightarrow9x+5=32\)

\(\Rightarrow9x=32-5\)

\(\Rightarrow9x=27\)

\(\Rightarrow x=\dfrac{27}{9}\)

\(\Rightarrow x=3\)

b) \(\dfrac{3}{2x+1}+\dfrac{10}{4x+2}-\dfrac{6}{6x+3}=\dfrac{12}{26}\) (ĐK: \(x\ne-\dfrac{1}{2}\)) 

\(\Rightarrow\dfrac{3}{2x+1}+\dfrac{10}{2\left(2x+1\right)}-\dfrac{6}{3\left(2x+1\right)}=\dfrac{6}{13}\)

\(\Rightarrow\dfrac{3}{2x+1}+\dfrac{5}{2x+1}-\dfrac{2}{2x+1}=\dfrac{6}{13}\)

\(\Rightarrow\dfrac{6}{2x+1}=\dfrac{6}{13}\)

\(\Rightarrow2x+1=13\)

\(\Rightarrow2x=12\)

\(\Rightarrow x=\dfrac{12}{2}\)

\(\Rightarrow x=6\left(tm\right)\)

x=100.5188285 nha ai ra giống mik cho mik 1 k nha

Ê mà tớ giải hpt đó nha!! sai nhớ sửa lại dùm tớ!! -_-

\(x+y=102\Leftrightarrow y=102-x\)

\(thay\) \(y\)\(vào\)\(BT\)

\(2X+8X\div12+18Y=26\)

\(\Leftrightarrow2X+8X\div12+18\left(102-X\right)=26\)

\(\Leftrightarrow\)\(2X+\frac{8X}{12}+1836-18X=26\)

\(\Leftrightarrow24X+8X+22032-216X=312\)

\(\Leftrightarrow-184X=-21720\)

\(\Leftrightarrow X\approx118\)

a) 12-3x=0

    3x=12-0

    3x=12

    x=12:3

    x=4

b)2x-26=25.12

   2x-26=300

   2x=300+26

   2x=326

   x=326:2

   x=163

c)5x+28=234:3

  5x+28=78

  5x=78-28

  5x=50

  x=50:5

  x=10

d)72-7x=529:23

   72-7x=23

   7x=72-23

   7x=49

   x=49:7

   x=7

k cho mình nhoa~~

a, (12-3x):20=0

=> 12-3x=0

=> 3x=12

=> x= 4             Vậy x=4

b, (2x-26):12=25

=> 2x-26=300

=> 2x=326

=> x=163           Vậy x= 163

c, 234:( 5x+28)=3

=> 5x+28=78

=> 5x=50

=> x= 10            Vậy x= 10

d, 529: (72-7x)=23

=> 72-7x=23

=> 7x=49

=> x= 7             Vậy x= 7

   Nhớ k cho mik nhé!!!! CẢM ƠN !!!

a) x - 12 - 2x - 32 = -11

-x - 44 = -11

-x  = 33

x = -33 

a/ (x-12)-(2x+31)=-6-5

    x-12-2x-31=-11

    -x=(-11)+43

-x=32

=> x=-32

a/ (x-12)-(2x+31)=-6-5

    x-12-2x-31=-11

    -x=(-11)+43

-x=32

=> x=-32