Rút gọn rồi tính:
a) \(\dfrac{8}{18}+\dfrac{5}{3}\) b) \(\dfrac{8}{24}+\dfrac{4}{48}\) c) \(\dfrac{20}{15}-\dfrac{4}{45}\) d) \(\dfrac{40}{32}-\dfrac{1}{2}\)
a: \(\dfrac{8}{18}+\dfrac{5}{3}=\dfrac{4}{9}+\dfrac{5}{3}=\dfrac{4}{9}+\dfrac{15}{9}=\dfrac{4+15}{9}=\dfrac{19}{9}\)
b: \(\dfrac{8}{24}+\dfrac{4}{48}=\dfrac{1}{3}+\dfrac{1}{12}=\dfrac{4}{12}+\dfrac{1}{12}=\dfrac{4+1}{12}=\dfrac{5}{12}\)
c: \(\dfrac{20}{15}-\dfrac{4}{45}=\dfrac{4}{3}-\dfrac{4}{45}=\dfrac{60}{45}-\dfrac{4}{45}=\dfrac{60-4}{45}=\dfrac{56}{45}\)
d: \(\dfrac{40}{32}-\dfrac{1}{2}=\dfrac{5}{4}-\dfrac{1}{2}=\dfrac{5-2}{4}=\dfrac{3}{4}\)
mẫu số chung nhỏ nhất của các phân số \(\dfrac{3}{5}\) , \(\dfrac{3}{8}\) , \(\dfrac{3}{10}\) , và \(\dfrac{3}{20}\)
A. 80 B. 60 C. 40 D. 20
Câu 2: Chọn câu sai?
A.\(\dfrac{1}{3}=\dfrac{45}{135}\)
B.\(\dfrac{-13}{20}=\dfrac{26}{-40}\)
C. \(\dfrac{-4}{15}=\dfrac{-16}{-60}\)
D. \(\dfrac{6}{7}=\dfrac{-42}{-49}\)
rút gọn
a)\(\sqrt{20}\)+\(\sqrt{80}\)-\(\sqrt{45}\)
b)4.\(\sqrt{\dfrac{2}{9}}\)+\(\sqrt{2}\)+\(\sqrt{\dfrac{1}{18}}\)
c)\(\dfrac{1}{\sqrt{3}-1}\)-\(\dfrac{1}{\sqrt{3}+1}\)
d)\(\dfrac{1}{\sqrt{x}-1}\)-\(\dfrac{1}{\sqrt{x}+1}\)+1
e)\(\sqrt{x}\)-2+\(\dfrac{10-x}{\sqrt{x}+2}\)
g)\(\dfrac{1}{\sqrt{x}+2}\)-\(\dfrac{2}{\sqrt{x}-2}\)-\(\dfrac{\sqrt{x}}{4-x}\)
tính nhanh
a.125 *45 +45 *25 +90 *25
b. 303 *85 -85 -103 -85 *100
c.25 *20 *4 -200 *40
d. 175 - 26 + 25 - 125 * 1,6 *80
a) 125 x 45 + 45 x 25 + 90 x 25
=125 x 45 + 45 x 25 + 2 x 45 x 25
=45 x [125 + 25 + ( 2 x 25 )]
=45 x [125 + 25 + 50]
=45 x 200
= 9000
c) 25 x 20 x 4 - 200 x 40
=25 x 2 x 10 x 4 - 200 x 40
=(25 x 2 x 4) x 10 - 200 x 40
=200 x 10 - 200 x 40
=200 x (10 - 40)
=200 x (-30)
= -6000
Câu 17: Giá trị \(\dfrac{1}{3}\)của 60 là:
A.45 B.20 C.40 D.50
60 . \(\dfrac{1}{3}\) = 20
Vậy chọn B
* Tính giá trị các biểu thức sau
a. \(\dfrac{45^{10}.5^{20}}{75^{15}}\) b. \(\dfrac{2^{15}.9^4}{6^68^3}\)
* Tính
A=\(\dfrac{3^6.45^4-15^{13}.5^{-9}}{27^4.25^3+45^6}\)
Giúp mình nhanh nhanh với nha, tối nay mình đi học rồi
Bài 1:
a: \(\dfrac{45^{10}\cdot5^{20}}{75^{15}}=\dfrac{5^{10}\cdot3^{20}\cdot5^{20}}{\left(5^2\right)^{15}\cdot3^{15}}=3^5\)
b: \(\dfrac{2^{15}\cdot9^4}{6^6\cdot8^3}=\dfrac{2^{15}\cdot3^8}{2^6\cdot2^9\cdot3^6}=3^2\)
a,(-123)+|-13|+(-7)
b,-|-33|+(-15)+20-|45-40|-57
c,9.|40-37|_2.13-52|
d,12+15+18+...+90
e,140:{80-[130-(12-4)^2]}
giúp mk với
\(\text{(-123) +|–13| +(-7)}\)
\(\text{= (-123) + 13 + (-7)}\)
\(\text{= (-110) + (-7)}\)
\(=\text{(-117)}\)
b
b)\(\sqrt{4x-20}+\sqrt{x+5}-\dfrac{1}{3}\sqrt{9x-45}=4\)
c) \(\sqrt{\dfrac{3x-2}{x+1}}=3\)
d) \(\dfrac{\sqrt{5x-4}}{\sqrt{x+2}}=2\)
b: Sửa đề: \(\sqrt{4x-20}+\sqrt{x-5}-\dfrac{1}{3}\cdot\sqrt{9x-45}=4\)(1)
ĐKXĐ: \(x>=5\)
\(\left(1\right)\Leftrightarrow2\sqrt{x-5}+\sqrt{x-5}-\dfrac{1}{3}\cdot3\sqrt{x-5}=4\)
=>\(2\sqrt{x-5}=4\)
=>\(\sqrt{x-5}=2\)
=>x-5=4
=>x=9(nhận)
c: ĐKXĐ: \(\dfrac{3x-2}{x+1}>=0\)
=>\(\left[{}\begin{matrix}x>=\dfrac{2}{3}\\x< -1\end{matrix}\right.\)
\(\sqrt{\dfrac{3x-2}{x+1}}=3\)
=>\(\dfrac{3x-2}{x+1}=9\)
=>9(x+1)=3x-2
=>9x+9=3x-2
=>6x=-11
=>\(x=-\dfrac{11}{6}\left(nhận\right)\)
d: ĐKXĐ: \(\left\{{}\begin{matrix}5x-4>=0\\x+2>0\end{matrix}\right.\Leftrightarrow x>=\dfrac{4}{5}\)
\(\dfrac{\sqrt{5x-4}}{\sqrt{x+2}}=2\)
=>\(\sqrt{\dfrac{5x-4}{x+2}}=2\)
=>\(\dfrac{5x-4}{x+2}=4\)
=>5x-4=4x+8
=>x=12(nhận)
