a: A={71;72;73;74}

b: B={41;43;45;47;49}

c: C={0}

d: D=R

A = ( 71,72,73,74 )

B = ( 41,43,45,47,49 )

C = ( 0)

D = ( 1,2,3,4,5,6,7,......., N )

câu d mk làm sai rồi

d) (x-15)-75=0

x-15=0+75=75

x=75+15=90

 

a, x= 15

b, x = 11

c, x =?

d, x = 90

e, ?

g, x=20

a) (x-15)x15=0

=>x-15=0

    x=0+15=15

b) 32(x-10)=32

x-10=32:32=1

x=1+10=11

c)315 (125-x)=435

125-x=435-315=120

x=125-120=5

d) (x-15)-75=0

=>x-15=0

    x=0+15=0

e) 575-(6x 70)=445

6x70=575-445=130

6x=130:70=13/7

x=13/7:6=13/42

g)x-105:21=15'

x-5=15

x=15+5=20

**** nhé

`@` `\text {Ans}`

`\downarrow`

`c)`

`( 34 - 2x ) . ( 2x - 6 ) = 0`

`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

Vậy, `x \in {17; 3}`

`d)`

`( 2019 - x ) . ( 3x - 12 ) =0` `?`

`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=12\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)

Vậy, `x \in {2019; 4}`

`e) `

`57 . ( 9x - 27 ) = 0`

`=>`\(9x-27=0\div57\)

`=> 9x - 27 = 0`

`=> 9x = 27`

`=> x = 27 \div 9`

`=> x = 3`

Vậy, `x = 3`

`f)`

`25 + ( 15 - x ) = 30`

`=> 15 - x = 30 - 25`

`=> 15 - x = 5`

`=> x = 15 -5 `

`=> x = 10`

Vậy, `x = 10`

`g) `

`43 - ( 24 - x ) = 20`

`=> 24 - x = 43 - 20`

`=> 24 - x = 23`

`=> x = 24 - 23`

`=> x = 1`

Vậy, `x = 1`

`h) `

`2 . ( x - 5 ) - 17 = 25`

`=> 2 ( x - 5) = 25+17`

`=> 2 ( x - 5) = 42`

`=> x - 5 = 42 \div 2`

`=> x - 5 = 21`

`=> x = 21 + 5`

`=> x = 26`

Vậy, `x = 26`

`i)`

`3 . ( x + 7 ) - 15 = 27`

`=> 3(x + 7) = 27 + 15`

`=> 3(x + 7) = 42`

`=> x +7 = 42 \div 3`

`=> x + 7 = 14`

`=> x = 14 - 7`

`=> x = 7`

Vậy, `x = 7`

`j)`

`15 + 4 . ( x - 2 ) = 95`

`=> 4(x - 2) = 95 - 15`

`=> 4(x - 2) = 80`

`=> x - 2 = 80 \div 4`

`=> x - 2 = 20`

`=> x = 20 + 2`

`=> x = 22`

Vậy, `x = 22`

`k)`

`20 - ( x + 14 ) = 5`

`=> x + 14 = 20 - 5`

`=> x + 14 = 15`

`=> x = 15 - 14`

`=> x = 1`

Vậy, `x = 1`

`l) `

`14 + 3 . ( 5 - x ) = 27`

`=> 3(5 - x) = 27 - 14`

`=> 3(5 - x) = 13`

`=> 5 - x = 13 \div 3`

`=> 5 - x = 13/3`

`=> x = 5- 13/3`

`=> x = 2/3`

Vậy, `x = 2/3.`

`@` `\text {Kaizuu lv uuu}`

nhanh mik tick cho nha

Theo mik: Theo mik: a, 45.(76-x) =90 X= 90:45 X= 2 X=76-2 X=74 B,(2.x-6).(3.x-8)=0 2.x=0+6 2.x=6 X=6.2 X=3 C, 5.x+73.31=73.36 5.x+ 2263=2628 5.x=2628-2263 5.x=365 X=365:5 X=73 D, (x-12). 105=0 X-12=0:105 X-12=0 X=0+12 X=12 E,2.x+69.2=69.4 2.x+138=276 2.x=276-138 2.x=38 X=38:2 X=19 F,(x-40).15=15.3 (x-40).15=45 X-40=45:15 X-40=3 X=40+3 X=43 G,(x-280):35=56:5 (x-280):35=11,2 X-280=11,2.35 X-280=392 X=392+280 X=672 H, X-280:35=5.54 X-8=270 X=270+8 X=278 L, x:15+42=13+25.8 X:57=213 X=213.57 X=12141 K, (x-128+20):193=0 (x-148):193=0 X-148=0.193 X-148=0 X=0+148 X=148 Bn tính thử có đúng ko hộ mik

Tóm lại : A, 74/ B.,3/ C, 73/ D, 12/ E, 19 F.,43/ G, 672/ H, 278/ K, 148

A.\(\left(x-15\right).15=0\)

\(x-15=0:15\)

\(x-15=0\)

\(x=15+0\)

\(x=15\)

B.\(32\left(x-10\right)=32\)

\(x-10=32:32\)

\(x-10=1\)

\(x=10+1\)

\(x=11\)

 

`a) `

`(x-15)xx15=0`

`<=> x-15 = 0 : 15`

`<=> x-15 = 0`

`<=> x = 0 + 15`

`<=> x =15`

`b)`

`32.(x-10)=32`

`<=> x - 10 = 32:32`

`<=>x-10=1`

`<=> x = 1+10`

`<=> x =11`

`c)`

`(x-5).(x-7)=0`

`<=>` \(\left[ \begin{array}{l}x-5 = 0\\x-7=0\end{array} \right.\) 

`<=>` \(\left[ \begin{array}{l}x=5\\x=7\end{array} \right.\) 

`d)`

`(x-35)xx35=35`

`<=> x - 35 = 35:35`

`<=> x - 35 = 1`

`<=> x = 1+35`

`<=> x = 36`

 

dài quá ko làm nha!!!

 

a) \(5\left(x-7\right)=0\)

\(\Rightarrow x-7=0\)

\(\Rightarrow x=7\)

b) \(25\left(x-4\right)=0\)

\(\Rightarrow x-4=0\)

\(\Rightarrow x=4\)

c) \(\left(34-2x\right)\left(2x-6\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

d) \(\left(2019-x\right)\left(3x-12\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2019\\x=\dfrac{12}{3}=4\end{matrix}\right.\)

e) \(57\left(9x-27\right)=0\)

\(\Rightarrow9x-27=0\)

\(\Rightarrow9\left(x-3\right)=0\)

\(\Rightarrow x-3=0\)

\(\Rightarrow x=3\)

a) 5.(x-7)=0⇔x-7=0⇔x=7

b) 25(x-4)=0⇔x-4=0⇔x=4

c) (34-2x).(2x-6)=0

⇔ 34-2x=0 hoặc 2x-6=0

⇔2x=34 hoặc 2x=6

⇔ x=17 hoặc x=3

d) (2019-x).(3x-12)=0

⇔ 2019-x=0 hoặc 3x-12=0

⇔ x=2019 hoặc x=4

e) 57.(9x-27)=0

⇔ 9x-27=0

⇔ x=3

f) 25+(15-x)=30

⇔ 15-x=5

⇔ x=10

g) 43-(24-x)=20

⇔ 24-x=23

⇔ x=1

h) 2.(x-5)-17=25

⇔ 2(x-5)=42

⇔x-5=21

⇔ x=26

i) 3(x+7)-15=27

⇔ 3(x+7)=42

⇔ x+7=14

⇔ x=7

j) 15+4(x-2)=95

⇔ 4(x-2)=80

⇔ x-2=20

⇔ x=22

k) 20-(x+14)=5

⇔ x+14=15

⇔ x=1

l) 14+3(5-x)=27

⇔ 3(5-x)=13

⇔ 5-x=13/3

⇔ x=5-13/3

⇔ x=2/3

a) \(x:15=37=>x=37.15\)

\(=>x=555\)

b) \(554:x=17\)

\(=>x=554:17\)

\(=>x=\frac{554}{17}\)

c) \(15\left(x-9\right)=0\)

\(=>x-9=0=>x=9\)

d) \(0:x=0\)

\(=>x\in R\)

e) \(\left(x-714\right)-142=0\)

\(=>x-714=142\)

\(=>x=856\)

g) \(315+\left(146-x\right)=401\)

\(=>146-x=86\)

\(=>x=60\)

a/ x:15=37

         x=37.15

         x=555

b/ 544:x=17

          x=544:17

          x=32

c/ 15(x-9)=0

       (x-9)=0:15

       (x-9)=0

        x-9=0

           x=0+9

           x=9

d/ 0:x=0

       x=0:0

       x=0

e/ (x-714)-142=0

    (x-714)=0+142

    (x-714)=142

      x-714=142

             x=142+714

             x=856

g/ 315+(146-x)=401

            (146-x)=401-315

            (146-x)=86

              146-x=86

                     x=146-86

                     x=60

CHÚC BẠN HỌC TỐT NHA!