1. Tính:

a) 23 + 24 - ( 65 x 2 - 4 ) x 4 + 66 + 44 - ( 54 : 9 x 9 : 9 + 45 ) : 1 + 1 - 1 x ( 23 + 23 - 23 x 2 +1 ) = 51

b) 4444444444444444444444444444444444444444444444444444444444444444444 : 1

= 4444444444444444444444444444444444444444444444444444444444444444444

c) 3⁰ = 0

d) 1/1 = 1

e)

a) - 530

b) 44444444444444444444444444444444444444444444444444444444444444444444

c) 0

d) 1

e) Em là em

-530

444444444444444444444444444444444444444444444444444444444444444

0

1

...

\(2^3+3\cdot\left(\dfrac{1}{9}\right)^0-2^{-2}\cdot4+\left[\left(-2\right)^2:\dfrac{1}{2}\right]\cdot8\)

\(=8+3\cdot1-\dfrac{1}{4}\cdot4+\left(4:\dfrac{1}{2}\right)\cdot8\)

\(=8+3-\dfrac{4}{4}+4\cdot2\cdot8\)

\(=11-1+8\cdot8\)

\(=10+64\)

\(=74\)

\(=8+3-2^{-2}\cdot2^2+\left[4\cdot2\right]\cdot8\)

=11-1+8*8

=64+10=74

=8+3−2^(−2)⋅2^2+[4⋅2]⋅8=8+3−2−2⋅22+[4⋅2]⋅8

=11-1+8*8

=64+10=74

A=\(2^2-9^3+4^{-2}.16-2.5^2\)
\(=4-729+1-50=-774\)
B=\(\left(2^3.2\right).\dfrac{1}{2}+3^{-2}.3^2-7.1+5\)
\(B=2^4.\dfrac{1}{2}+1-7+5=8+1-7+5=7\)
 

 C = 2^-3 + (5²)³.5^-3 + 4^-3.16 - 2.3² - 105.(\(\dfrac{24}{51}\))⁰

C =  \(\dfrac{1}{8}\) + 5⁶.5^-3 + 4^-3.4² - 2.9 - 105.1

C =  \(\dfrac{1}{8}\) + 5³ + \(\dfrac{1}{4}\) - 18 - 105

C =  (\(\dfrac{1}{8}\) + \(\dfrac{1}{4}\))  - (105 - 125 + 18)

C = \(\dfrac{3}{8}\) - (-20 + 18)

C = \(\dfrac{3}{8}\)  + 2

C = \(\dfrac{19}{8}\)

D = 2^-3 . \(\dfrac{1}{2^{-2}}\).\(\dfrac{2}{3}\) + 4^-2.8 - 7. (\(\dfrac{17}{23}\))⁰ + 19

D = 2^-1.\(\dfrac{2}{3}\) + \(\dfrac{1}{16}\).8 - 7.1 + 19

D = \(\dfrac{1}{3}\) + \(\dfrac{1}{2}\) - 7 + 19

D = \(\dfrac{5}{6}\)  + (19 - 7)

D = \(\dfrac{5}{6}\) + 12

D = \(\dfrac{77}{6}\)

\(\left(-\frac{1}{2}\right)^2\div\left(-\frac{1}{4}\right)-2\times\left(-\frac{1}{2}\right)^3+\left(25-23\right)^2\)

\(=\frac{1}{4}\div\left(-\frac{1}{4}\right)-2\times\left(-\frac{1}{8}\right)+2^2\)

\(=-1+\frac{1}{4}+4\)

\(=\frac{13}{4}\)

*****

\(25^{10}\times\left(\frac{1}{5}\right)^{20}+\left(-\frac{3}{4}\right)^8\times\left(-\frac{4}{3}\right)^8-2016^0\)

\(=25^{10}\times\left[\left(\frac{1}{5}\right)^2\right]^{10}+\left[\left(-\frac{3}{4}\right)\times\left(-\frac{4}{3}\right)\right]^8\)

\(=25^{10}\times\left(\frac{1}{25}\right)^{10}+1^8-0\)

\(=\left(25\times\frac{1}{25}\right)^{10}+1\)

\(=1^{10}+1\)

= 1 + 1

= 2

2 câu khác nhau đấy nhé!

a) A = 3² . 1/243 . 81² . 1/3²

= 3² . 1/3⁵ . (3⁴)² . 1/3²

= 3² . 1/3⁷ . 3⁸

= 3¹⁰ . 1/3⁷

= 3³

= 27

b) B = (4.2⁵) : (2³ . 1/6)

= (4.32) : (8 . 1/6)

= 128 : 4/3

= 96

c)  C = (-1/3)³.(-1/3)².(-1/3)

= (-1/3)³⁺²⁺¹

= (-1/3)⁶

= 1/729

d) D = (-1/3)⁻¹ - (-6/7)⁰ + (1/2)² : 2

= -3 - 1 + 1/4 : 2

= -4 + 1/8

= -31/8

a)x=0+45

x=45

b)x=23:23=1

x=42-1

x=41

c)x=613+5=618

x=618:6

x=13

a)x=45

b)x=41

c)x=103

d)x=111

e)x=60

g)x=5

h)x=3^x=26

1,2 x (2,4 x n - 0,23 - 0,05) = 1,44

Coi phần trong ngoặc là thừa số : 

(2,4 x n - 0,23 - 0,05) = 1,44 : 1,2

2,4 x n - 0,23 - 0,005 = 1,2

Coi 2,4 x n - 0,23 là số bị trừ

2,4 x n - 0,23 = 1,2 + 0,05

2,4 x n - 0,23 =1,25

Coi 2,4 x n là SBT

2,4 x n = 1,25 + 0,23

2,4 x n = 1,48

n=1,48 : 2,4 = 148/240

Bạn xem lại đề bài, có thể bị nhầm số rồi.