Tính:
a, 75918 + 54135
b, 3265 : 32
65+3=?
Vậy 36+32+32+32+32+sdf=??????????????????????
Hỏi 3265+?+gh+y+3265=?????????????????????????????????????????????????????????
x - 1234 = 3265
3265*955=
Tính:
A= \(49\dfrac{8}{23}-\left(5\dfrac{7}{32}+14\dfrac{8}{32}\right)\)
\(=49+\dfrac{8}{23}-5-\dfrac{7}{32}-14-\dfrac{8}{32}\)
\(=30-\dfrac{89}{736}=\dfrac{21991}{736}\)
Tính:
a) \({\log _3}3\sqrt 3 ;\)
b) \({\log _{\frac{1}{2}}}32.\)
a: \(=log_3\left(\sqrt{3}\right)^3=log_3\left(3^{\dfrac{1}{2}}\right)^3=log_3\left(3^{\dfrac{3}{2}}\right)=\dfrac{3}{2}\)
b: \(log_{\dfrac{1}{2}}32=log_{\dfrac{1}{2}}\left(\dfrac{1}{2}\right)^{-5}=-5\)
Bài 1. Đặt tính rồi tính:
a) 77,2 : 8 b) 346,8 : 20 c) 21,6 : 32
Đặt tính rồi tính:
a)
32 × 3
41 × 2
124 × 2
312 × 3
b)
39 : 3
85 : 4
336 : 3
487 : 2
Bỏ dấu ngoặc rồi tính:
a) (56 - 27) - (11 + 28 - 16)
b) 28 + (19 - 28) - (32 - 57)
a) (56 - 27) - (11 + 28 - 16)
= 56 - 27 - 11 - 28 + 16
= (56 + 16) – (27 + 11 + 28)
= 72 – (38 + 28)
= 72 – 66
= 6
b) 28 + (19 - 28) - (32 - 57)
= 28 + 19 – 28 – 32 + 57
= (28 – 28) + (19 + 57) – 32
= 0 + 76 – 32
= 76 - 32
= 44
\(a,=56-27-11-28+16=6\)
\(b,=28+19-28-32+57=44\)
Bỏ dấu ngoặc rồi tính:
a, (56- 27 ) - ( 11+ 28 - 16 )
b, 28+ ( 19- 28) - ( 32- 57 )
a) (56 - 27) - (11 + 28 - 16)
= 56 - 27 - 11 - 28 + 16
= (56 + 16) – (27 + 11 + 28)
= 72 – (38 + 28)
= 72 – 66
= 6
b) 28 + (19 - 28) - (32 - 57)
= 28 + 19 – 28 – 32 + 57
= (28 – 28) + (19 + 57) – 32
= 0 + 76 – 32
= 76 - 32
= 44