Bài 1: Thực hiện các phép tính sau:

\(a)\)Chưa rỏ đề

\(b)\)\(5025\div5-25\div5\)

\(=\)\(1005-5\)

\(=\)\(1000\)

\(c)\)\(218-180\div2\div9\)

\(=\)\(218-10\)

\(=\)\(208\)

\(d)\)\(\left(328-8\right)\div32\)

\(=\)\(320\div32\)

\(=\)\(10\)

Bài 1:

a) ( Tôi không nhìn rõ đầu bài )

b) 5025  :  5  -  25  :  5

=  ( 5025  -  25 )  :  5

=        5000   :   5

=       1000

c)   218  -  180  :  2  :  9

=     218   -    180  :  (  2  .  9 )

=      218    -    180   :  18

=       218    -    10

=       208

d)   (  328  -  8  )  :  32

=      320   :   32

=     10 

Bài 2: Thực hiện phép tính:

\(a)\)\(27.75+25.27-150\)

\(=\)\(27.\left(75+25\right)-150\)

\(=\)\(27.100-150\)

\(=\)\(2700-150\)

\(=\)\(2550\)

\(b)\)\(12\div\left\{400\div\left[500-\left(125+25.7\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-\left(125+175\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-300\right]\right\}\)

\(=\)\(12\div\left\{400\div200\right\}\)

\(=\)\(12\div2\)

\(=\)\(6\)

\(c)\)\(13.17-256\div16+14\div7-1\)

\(=\)\(221-16+2-1\)

\(=\)\(206\)

\(d)\)\(18\div3+182+3.\left(51\div17\right)\)

\(=\)\(6+182+3.3\)

\(=\)\(6+182+9\)

\(=\)\(197\)

15.{550: [450-(3.5^3-2^3.25)]}

= 15.{550: [ 450-(3.125-8.25)]}

= 15.{550:[ 450-( 375-200)]}

= 15.{550:[450- 175]}

=15.{550: 275}

= 15. 2

= 30

15 . { 550 : [ 450 - ( 3 . 5³ - 2³ . 25 )]}

= 15 . { 550 : [ 450 - ( 3 . 125 - 8 . 25 )]}

= 15 . { 550 : [ 450 - ( 375 - 200 )]}

= 15 . { 550 : [ 450 - 175 ]}

= 15 . { 550 : 275 }

= 15 . 2

= 30.

#Y/n

15 . { 550 : [ 450 - ( 3 . 5^3 - 2^3 . 25 ) ] } 

= 15 . { 550 : [ 450 - ( 3. 125 - 8 .25 )]}

= 15 . { 550 : [ 450 - ( 375 -  200 )]}

= 15 . { 550 : [ 450 - 175 ] }

= 15 . { 550 : 275 )

= 15 .  2 

= 30 

1:

a: \(\sqrt{36}-\sqrt{100}=6-10=-4\)

b: Để \(\sqrt{\dfrac{2}{2x-1}}\) có nghĩa thì \(\dfrac{2}{2x-1}>=0\)

=>2x-1>0

=>x>1/2

2:

a: \(A=\dfrac{\left(15\sqrt{180}-5\sqrt{200}-3\sqrt{450}\right)}{\sqrt{10}}\)

\(=15\sqrt{\dfrac{180}{10}}-5\sqrt{\dfrac{200}{10}}-3\sqrt{\dfrac{450}{10}}\)

\(=15\sqrt{18}-5\sqrt{20}-3\sqrt{45}\)

\(=45\sqrt{2}-10\sqrt{5}-9\sqrt{5}\)

\(=45\sqrt{2}-19\sqrt{5}\)

b: \(B=\sqrt{32}-\sqrt{50}-16\sqrt{\dfrac{1}{8}}\)

\(=4\sqrt{2}-5\sqrt{2}-\dfrac{16}{\sqrt{8}}\)

\(=-\sqrt{2}-2\sqrt{8}=-\sqrt{2}-4\sqrt{2}=-5\sqrt{2}\)

\(a,3^3+3^2-\left(2^7:2^5+7^8:7^7\right)=27+9-\left(2^2+7\right)=36-11=25\)

\(b,27.77+27.27-27=27\left(77+27-1\right)=27.103=2781\)

\(c,52:\left(43-30\right)+144-16=52:13+128=4+128=132\)

\(f,3^2.101-3^2.101^0=3^2\left(101-101^0\right)=9\left(101-1\right)=9.100=900\)

a.=27+9-(2^2+7^1)                                                 =36-(4+7)                                                               =36-11                                                                   =25

3³+3²-(2⁷:2⁵+7⁸:7⁷)

=27+9-(2²+7)

=36-(4+7)

=36-11

=25

b.bạn tự lm nha

c.52:(43-30)+144-16

=52:13+144-16

=4+144-16

=148-16

=132

d.174:{2[36+(4²-23)]}

=174:{2[36+(16-23)]}

=174:{2[36+-7]}

=174:{2.29}

=174:58

=3

Ai tick mik 8 tick nữa cho tròn 160 điểm hỏi đáp với

a. |-65|+(-120)+|35|-103

= 65-120+35-103

= (65+35)+(-120-103)

= 100-223

= -123

b. 2³.29-72:3²

= 8.29-72:9

= 232-8

= 224

c. 407-{[-132+180):4+9]:3}

= 407-[(48:4+9):3]

= 407-[(12+9):3]

= 407-(21:3)

= 407-7

= 400

a) \(\dfrac{3}{10}\)

b) \(\dfrac{9}{28}\)

c) \(\dfrac{88}{195}\)

a) (-5) + (-10) + 20 

= 20 - 5 - 10 

= 5

b) 29 + (-40) + (-12) 

= 29 - 40 - 12  

= -23

c) 58 + (-14) + (-73) 

= 58 - 14 - 73 

= -29

\(a\text{)}\left(-5\right)+\left(-10\right)+20\)

\(=\left(-15\right)+20\)

\(=5\)

\(b\text{)}29+\left(-40\right)+\left(-12\right)\)

\(=\left(-11\right)+\left(-12\right)\)

\(=-23\)

\(c\text{)}58+\left(-14\right)+\left(-73\right)\)

\(=44+\left(-73\right)\)

\(=-29\)

\(\text{Hok tốt!}\)

\(\text{@Kaito Kid}\)

a: \(\left(-2\right)^3-45:\left(-3\right)^2+\left(-2019\right)^0\cdot1^{2019}\)

\(=-8-45:9+1\)

\(=-8-5+1\)

=-13+1

=-12

b: \(11^{25}:11^{13}-3^5:\left(1^{10}+2^3\right)-60\)

\(=11^{25-13}-3^5:3^2-60\)

\(=11^{12}-27-60\)

\(=11^{12}-87\)