a. (9x + 2).3 = 60

<=> 9x + 2 = 20

<=> 9x = 18

<=> x = 2

b. 71 + (26 - 3x):5 = 75

<=> (26 - 3x) : 5 = 4

<=> 26 - 3x = 4/5

<=> 3x = 26 - 4/5 

<=> x = 42/5

c. 2^x = 32

<=> 2^x = 2⁵

<=> x = 5

d. (x - 6)² = 9

<=> x - 6 = 3

<=> x = 9

a) \(\left(9x+2\right)\times3=60\)

\(\Rightarrow9x+2=60:3\)

\(\Rightarrow9x+2=20\)

\(\Rightarrow9x=20-2\)

\(\Rightarrow9x=18\)

\(\Rightarrow x=18:9\)

\(\Rightarrow x=2\)

Vậy x = 2

b) \(71+\left(26-3x\right):5=75\)

\(\Rightarrow\left(26-3x\right):5=75-71\)

\(\Rightarrow\left(26-3x\right):5=4\)

\(\Rightarrow26-3x=4\times5\)

\(\Rightarrow26-3x=20\)

\(\Rightarrow3x=26-20\)

\(\Rightarrow3x=6\)

\(\Rightarrow x=6:3\)

\(\Rightarrow x=2\)

Vậy x = 2

c) \(2^x=32\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

Vậy x = 5

d) \(\left(x-6\right)^2=9\)

\(\Rightarrow\orbr{\begin{cases}x-6=3\\x-6=-3\end{cases}}\Rightarrow\orbr{\begin{cases}x=9\\x=3\end{cases}}\)

Vậy x = 9 hoặc x = 3

_Chúc bạn học tốt_

a) (9x+2).3=60

       9x+2  = 20

           9x  = 18

             x  = 2

b) 71 + (26-3x) : 5 = 75

   (26 - 3x) : 5         = 4

    26 - 3x                = 20

          3x                  = 26 - 20

            x                 = 6 : 3

            x                  = 2

c) 2^x = 32

   2^x  = 2⁵

     x = 5

d) (x-6)² = 9

   (x-6)²  = 3²

      x - 6 = 3

         x =  9

bao đúng bn nhé

c) 3(x -1 ) + 3(2 – x) = 0
3x-3+6-3x=0
 3=0 (vô lí)
không có giá trị x thỏa mãn 
d) 5x + 3(x – 8) = 8
5x+3x-24=8
8x=32
x=32:8
x=4

a. 23 + 3x = 5⁶ : 5³

23 + 3x     = 5³

3x             = 5³ - 23

x               = 102 : 3

x               = 34

b. 541 + (218 - x) = 735

218 - x                 = 735 - 541

x                          = 218 - 194

x                          = 24

c. 9x + 2 = 60 : 3

9x           = 20 - 2

x             = 18 : 9

x             = 2

Lời giải:
a.

$(x-15).27=0$

$x-15=0:27=0$

$x=15+0=15$

b.

$23(42-x)=0$

$42-x=0$

$x=42$

c.

$(9x+2).3=60$

$9x+2=60:3=20$

$9x=18$

$x=2$
d.

$71+(26-3x):5=75$

$(26-3x):5=75-71=4$

$26-3x=4.5=20$

$3x=26-20=6$

$x=6:2=3$

a)

\(\begin{array}{l}\left( {9x - {2^3}} \right):5 = 2\\9x - {2^3} = 2.5\\9x - 8 = 10\\9x = 18\\x = 2\end{array}\)

Vậy \(x = 2\)

b)

\(\begin{array}{l}\left[ {{3^4} - \left( {{8^2} + 14} \right):13} \right]x = {5^3} + {10^2}\\\left[ {81 - \left( {64 + 14} \right):13} \right]x = 125 + 100\\\left[ {81 - 78:13} \right]x = 125 + 100\\\left[ {81 - 6} \right]x = 225\\75x = 225\\x = 3\end{array}\)

Vậy \(x = 3\)

Tìm x không cần tìm y sao ?

(9x-2)(2y+3)=26

=>9x-2=26 hoặc 2y+3=26

9x=28                          2y=23

x=28:9                         y=23:2

  x  xấp xỉ 3                 y=11,5

tìm cả y ak hay k tìm z

9x+17 = 3(3x+2) +11  chia hết cho 3x+2 

=> 11 chia hết cho  3x+2

=> 3x+2 là Ư(11) ={1;11}

Vì x thuộc N => 3x+2 >1

=> 3x+2 = 11 => x =3

x=3

x=3 tick cho mk nha bn thân mến

a) \(5\left(x+7\right)-10=2^3\cdot5\)

\(\Rightarrow5\left(x+7\right)-10=40\)

\(\Rightarrow5\left(x+7\right)=40+10\)

\(\Rightarrow x+7=\dfrac{50}{5}\)

\(\Rightarrow x+7=10\)

\(\Rightarrow x=10-7\)

\(\Rightarrow x=3\)

b) \(9x-2\cdot3^2=3^4\)

\(\Rightarrow9x-18=81\)

\(\Rightarrow9x=81+18\)

\(\Rightarrow9x=99\)

\(\Rightarrow x=\dfrac{99}{9}\)

\(\Rightarrow x=11\)

c) \(5^{25}\cdot5^{x-1}=5^{25}\)

\(\Rightarrow5^{x-1}=5^{25}:5^{25}\)

\(\Rightarrow5^{x-1}=1\)

\(\Rightarrow5^{x-1}=5^0\)

\(\Rightarrow x-1=0\)

\(\Rightarrow x=1\)

a) 5(�+7)−10=23⋅55(x+7)−10=23⋅5

$\Rightarrow 5\left(x+7\right)-10=40$

$\Rightarrow 5\left(x+7\right)=40+10$

⇒�+7=505⇒x+7=550​

$\Rightarrow x+7=10$

$\Rightarrow x=10-7$

$\Rightarrow x=3$

b) 9�−2⋅32=349x−2⋅32=34

$\Rightarrow 9x-18=81$

$\Rightarrow 9x=81+18$

$\Rightarrow 9x=99$

⇒�=999⇒x=999​

$\Rightarrow x=11$

c) 525⋅5�−1=525525⋅5x−1=525

⇒5�−1=525:525⇒5x−1=525:525

⇒5�−1=1⇒5x−1=1

$\Rightarrow$