GIAI PHUONG TRINH
CAN 1+3x =X-1
giai phuong trinh x^2-x+6=4 can 3x-2
cho phuong trinh (an x):(m-1)x +m^2 -1=0(1) a,giai phuong trinh (1) voi m=2 b, tim gia tri cua m sao cho phuong trinh (1) nhan x=3 lam nghiem
mk dang can gap .cam on truoc a
giai cac phuong trinh va bat phuong trinh sau:
2(x-1)-5=3(5-3x)
2( x - 1 ) - 5 = 3( 5 - 3x)
2x - 2 - 5 = 15 - 9x
2x - 7 = 15 - 9x
2x + 9x = 15 + 7
11x = 22
x = 2
Vậy x = 2
\(2\left(x-1\right)-5=3\left(5-3x\right)\)
\(\Leftrightarrow2x-2-5=15-9x\)
\(\Leftrightarrow2x-\left(2+5\right)=15-9x\)
\(\Leftrightarrow2x-7=15-9x\)
\(\Leftrightarrow2x+9x=15+7\)
\(\Leftrightarrow11x=22\)
\(\Leftrightarrow x=22\div11\)
\(\Leftrightarrow x=2\)
\(\text{Vậy }x=2\)
2( x - 1 ) - 5 = 3( 5 - 3x)
2x - 2 - 5 = 15 - 9x
2x - 7 = 15 - 9x
2x + 9x = 15 + 7
11x = 22
x = 2
giai phuong trinh
(x-2)^+(3x-1)(3x+1)=(x+1)^3
(x-2)^+(3x-1)(3x+1)=(x+1)^3
<=>x3-6x2+12x-8+9x2-1=x3+3x2+3x+1
<=>-6x2+12x-8+9x2-1=3x2+3x+1
<=>3x2+12x-9=3x2+3x+1
<=>12x-9=3x+1
<=>9x=10
<=>x=\(\dfrac{10}{9}\)
giai phuong trinh √x-1 -√5x-1 =√3x-2
giai cac phuong trinh sau
a) x + 5 can x - 6 =0
b) x - can x + 1/4 = 0
a: \(x+5\sqrt{x}-6=0\)
\(\Leftrightarrow\sqrt{x}-1=0\)
hay x=1
b: \(x-\sqrt{x}+\dfrac{1}{4}=0\)
\(\Leftrightarrow\sqrt{x}-\dfrac{1}{2}=0\)
hay \(x=\dfrac{1}{4}\)
giai cac phuong trinh sau
a) x + 5 can x - 6 =0
b) x - can x + 1/4 = 0
a: \(x+5\sqrt{x}-6=0\)
\(\Leftrightarrow\sqrt{x}-1=0\)
hay x=1
b: \(x-\sqrt{x}+\dfrac{1}{4}=0\)
\(\Leftrightarrow\sqrt{x}-\dfrac{1}{2}=0\)
hay \(x=\dfrac{1}{4}\)
giai cac phuong trinh sau
a) x + 5 can x - 6 =0
b) x - can x + 1/4 = 0
a: \(x+5\sqrt{x}-6=0\)
\(\Leftrightarrow\sqrt{x}-1=0\)
hay x=1
b: \(x-\sqrt{x}+\dfrac{1}{4}=0\)
\(\Leftrightarrow\sqrt{x}-\dfrac{1}{2}=0\)
hay \(x=\dfrac{1}{4}\)
Giai he phuong trinh
x(x+y)+can (x+y)=can (2y) [can(2y^3)+1]
8x^2-8y+2(x^3-y^3)+3=8y can(2x^3-3x+1)
tat ca deu la can bac hai