1 + 3x = x- 1
=> x = 3x - x = -1 - 1
2x = -2
x = -1
\(\text{ĐK: }x\ge1\)
\(\sqrt{1+3x}=x-1\Leftrightarrow1+3x=\left(x-1\right)^2\Leftrightarrow1+3x=x^2-2x+1\)
\(\Leftrightarrow x^2-5x=0\Leftrightarrow x.\left(x-5\right)=0\Leftrightarrow x=0\left(\text{loại}\right)\text{ hoặc }x=5\)