(x-2)^+(3x-1)(3x+1)=(x+1)^3
<=>x3-6x2+12x-8+9x2-1=x3+3x2+3x+1
<=>-6x2+12x-8+9x2-1=3x2+3x+1
<=>3x2+12x-9=3x2+3x+1
<=>12x-9=3x+1
<=>9x=10
<=>x=\(\dfrac{10}{9}\)
Giai phuong trinh:
a)\(\frac{4+9x}{9x^21}=\frac{3}{3x+1}-\frac{2}{1-3x}\)
b)\(\frac{2x-3}{x+1}+\frac{x^2-5x+10}{\left(x+1\right)\left(x-3\right)}=\frac{3x-5}{x-3}\)
c)\(\frac{x\left(x+4\right)}{2x-3}=\frac{x^2+4}{2x-3}+1-\frac{2}{3-2x}\)
d)\(\frac{1}{x+2}+\frac{x}{x-3}=1-\frac{5x}{\left(x+2\right)\left(3-x\right)}-\frac{1}{x+2}\)
Giai phuong trinh:
a, x3+\(\frac{x^3}{\left(x-1\right)^3}\)+\(\frac{3x^2}{x-1}\)=2
b, \(\frac{2x}{3x^2-5x+2}\)+\(\frac{13x}{3x^2+x+2}\)=6
c, x2+\(\frac{25x^2}{\left(x+5\right)^2}\)=11
d, \(\frac{x^2}{3}\)+\(\frac{48}{x^2}\)=10.(\(\frac{x}{3}-\frac{4}{x}\))
giai phuong trinh:
a, x+1/x2+x+1 - x-1/x2-x+1 = 3/x.(x4+x2+1)
giải giúp mình hai câu này của phuong trình chứa ẩn ơ mẫu
A) x^2 - 4x =0
B)5/x-2 - 3/x+2 = 3x - 1/x^2-4
Giair ca phương trình sau
1/ \(\dfrac{7x-3}{x-1}=\dfrac{2}{3}\)
2/ \(\dfrac{5x-1}{3x+2}=\dfrac{5x-7}{3x-1}\)
3/ \(\dfrac{1-x}{x+1}+3=\dfrac{2x+3}{x+1}\)
4/ \(\dfrac{1-6x}{x-2}+\dfrac{9x+4}{x+2}=\dfrac{x\left(3x-2\right)+1}{x^2-4}\)
5/ \(\dfrac{3x+2}{3x-2}-\dfrac{6}{2+3x}=\dfrac{9x^2}{9x^2-4}\)
6/ \(1+\dfrac{1}{x+2}=\dfrac{12}{8-x^3}\)
giai pt (giup toi voi)
1.\(\dfrac{4x}{4x^2-8x+7}+\dfrac{3x}{4x^2-10x+7}=1\)
2.\(\dfrac{2x}{x^2+3x-10}\)+\(\dfrac{5x}{x^2+7x-10}=4\)
Giải phương trình:
a, \(\frac{2}{\left(1-3x\right)\left(3x+11\right)}=\frac{1}{9x^2-6x+1}-\frac{3}{\left(3x+11\right)^2}\)
b,\(\frac{x+1}{x^2+x+1}-\frac{x-1}{x^1-x+1}=\frac{3}{x\left(x^4+x^2+1\right)}\)
a. 3x-1=-17
b. 40-(3x-8)=3(3-5x)
c. x/2(x-2) + x/2x+2 = 2x/(x+1)(x-2) e cảm ơn mng nhìuu
