mn giup e vs a / lam chi tiet jup e nha ^^
phan tich thanh nhan tu / a)6x^4-9x^3
b) x^2y^2z+xy^2z^2+x^2yz^2
c)2x(x+3)+2(x+3)
d )(x+5)^2-3(x+5)
e)2x(x-3)-(x-3)^2
a, x^3-x^2-4x^2+8x-4
b, 4x^2-25-(2x-5)2x+7
c, x^3+27+(x+3)(x-9)
d, 2x^2-2y^2+5x-5y
e, x^2-y^2-2y-1
phan tich da thuc thanh nhan tu
phan tich da thuc thanh nhan tu
a)x^4+x^2y^2+y^4
b)x^3+3x-4
c)x^2+9x+8
d)x^2+x-42
e)y^2-13y+12
f)x^2-x-30
g)2x^2+xy-y^2
h)y^2-y-12
i)x^2+x-2
j)x^3+3x^2-2
k)x^3-6x^2+16
l)x^3+3x+4
m)x^4+6x^3-12x^2-8x
a. x4 + x2y2 + y4 = (x4 + 2x2y2 + y4) - x2y2
= (x2 + y2)2 – (xy)2
= [(x2 + y2) + xy] [(x2 + y2) – xy]
= (x2 + xy + y2)(x2 –xy + y2)
h, \(y^2-y-12\)
\(=y^2-4x+3y-12\)
\(=\left(y-4\right)\left(y+3\right)\)
\(i,x^2+x-2\)
\(=x^2+2x-x-2\)
\(=\left(x+2\right)\left(x-1\right)\)
\(j,x^3+3x^2-2\)
\(=x^3+2x^2+x^2-2x+2x-2\)
\(=x^2\left(x+1\right)+2x\left(x+1\right)-2\left(x+1\right)\)
\(=\left(x+1\right)\left(x^2+2x-2\right)\)
phan tich da thuc thanh nhan tu
a)x^4+x^2y^2+y^4
b)x^3+3x-4
c)x^2+9x+8
d)x^2+x-42
e)y^2-13y+12
f)x^2-x-30
g)2x^2+xy-y^2
h)y^2-y-12
i)x^2+x-2
j)x^3+3x^2-2
k)x^3-6x^2+16
l)x^3+3x+4
m)x^4+6x^3-12x^2-8x
minh can gap lam, chiu nay la minh hoc roi
\(\text{a) }x^4+x^2y^2+y^4=x^4+2x^2y^2-x^2y^2+y^4=\left(x^4+2x^2y^2+y^4\right)-\left(x^2y^2\right)=\left(x^2+y^2\right)^2-\left(xy\right)^2\)
\(=\left(x^2+y^2+xy\right)\left(x^2+y^2-xy\right)\)
\(\text{b) }x^3+3x-4=x^3+3x-1-3=\left(x^3-1\right)+\left(3x-3\right)=\left(x-1\right)\left(x^2+x+1\right)+3\left(x-1\right)\)
\(=\left(x-1\right)\left(x^2+x+1+3\right)=\left(x-1\right)\left(x^2+x+4\right)\)
\(\text{c) }x^2+9x+8=x^2+8x+x+8=\left(x^2+8x\right)+\left(x+8\right)=x\left(x+8\right)+\left(x+8\right)\)
\(=\left(x+8\right)\left(x+1\right)\)
\(\text{d) }x^2+x-42=x^2+7x-6x-42=\left(x^2+7x\right)-\left(6x+42\right)=x\left(x+7\right)-6\left(x+7\right)\)
\(=\left(x+7\right)\left(x-6\right)\)
\(\text{e) }y^2-13y+12=y^2-y-12y+12=\left(y^2-y\right)-\left(12y-12\right)=y\left(y-1\right)-12\left(y-1\right)\)
\(=\left(y-1\right)\left(y-12\right)\)
Mấy câu sau mk sẽ giải tiếp, bạn ráng chờ nha
\(\text{f) }x^2-x-30=x^2+5x-6x-30=\left(x^2+5x\right)-\left(6x+30\right)=x\left(x+5\right)-6\left(x+5\right)\)
\(=\left(x+5\right)\left(x-6\right)\)
\(\text{g) }2x^2+xy-y^2=x^2+x^2+xy-y^2=\left(x^2-y^2\right)+\left(x^2+xy\right)=\left(x-y\right)\left(x+y\right)+x\left(x+y\right)\)
\(=\left(x+y\right)\left(x-y+x\right)=\left(x+y\right)\left(2x-y\right)\)
\(\text{h) }y^2-y-12=y^2+3y-4y-12=\left(y^2+3y\right)-\left(4y+12\right)=y\left(y+3\right)-4\left(y+3\right)\)
\(=\left(y+3\right)\left(y-4\right)\)
bai 166 a) 6x^2 -11x +3 phan tich cac da thuc sau thanh nhan tu
b) 2x^+3x-27
c) 2x^2-5xy-3y^2
bai 167 a) x^3+2x-3 b) x^3-7x+6 c)x^3 +5x^2 +8x +4 d) x^3 -9x^2 +6x +16
e)x^3-x^2-x-2 g ) x^3+x^2-x+2 h)x^3 -6x^2-x+30
bai 169 a) 27x^3-27x^2 +18x-4
b)2x^3-x^2+5x+3
c)(x^2-3)^2+16
Dài 166
b) 2x2+3x-27=2x2-6x+9x-27=2x(x-3)+9(x-3)=(x-3)(2x+9)
Cach phan tich da thuc thanh nhan tu
a)X^3+2X^2+2X+1
b)X^3-4X^2+12X-27
c)a^6-a^4+2a^3+2a^2
d)x^4+2x^3+2x^2+2x+1
e)x^5+x^4+x^3+x^2+x+1
a)
=x3+x2+x2+x+x+1
=x2(x+1)+x(x+1)+(x+1)
=(x+1)(x2+x+1)
b)
=x3-3x2-x2+3x+9x-27
=x2(x-3)-x(x-3)+9(x-3)
=(x-3)(x2-x+9)
a)
=x3+x2+x2+x+x+1
=x2(x+1)+x(x+1)+(x+1)
=(x+1)(x2+x+1)
b)
=x3-3x2-x2+3x+9x-27
=x2(x-3)-x(x-3)+9(x-3)
=(x-3)(x2-x+9)
d)x^4+2x^3+2x^2+2x+1(no)
e)x^5+x^4+x^3+x^2+x+1 ( no)
10 Phân tích các đa thức sau thành nhân tử:
a) 5xy(x-y)-2x+2y ; b) 6x-2y-x(y-3x)
c) x^2+4x-xy-4y ; d) 3xy+2z-6y-xz
11 Tìm x, biết: a) 4-9x^2=0 ; b) x^2+x+1/4=0 ; c) 2x(x-3)+(x-3)=0
d) 3x(x-4)-x+4=0 ; e) x^3-1/9x=0 ; f) (3x-y)^2-(x-y)^2=0
a) 5xy ( x - y ) - 2x + 2y
= 5xy ( x - y ) - 2 ( x - y )
= ( x - y ) ( 5xy - 2 )
b) 6x-2y-x(y-3x)
= 2 ( y - 3x ) - x ( y - 3x )
= ( y - 3x ( ( 2 - x )
c) x2 + 4x - xy-4y
= x ( x + 4 ) - y ( x + 4 )
( x + 4 ) ( x - y )
d) 3xy + 2z - 6y - xz
= ( 3xy - 6y ) + ( 2z - xz )
= 3y ( x - 2 ) + z ( x - 2 )
= ( x - 2 ) ( 3y + z )
a,5xy(x-y)-2x+2y=5xy(x-y)-2(x-y)=(x-y)(5xy-2)
b,6x-2y-x(y-3x)=-2(y-3x)-x(y-3x)=(y-3x)(-2-x)
c,x^2+4x-xy-4y=x(x+4)-y(x+4)=(x+4)(x-y)
d,3xy+2z-6y-xz=(3xy-6y)+(2z-xz)=3y(x-2)+z(2-x)=3y(x-2)-z(x-2)=(x-2)(3y-z)
11)
a,4-9x^2=0
(2-3x)(2+3x)=0
2-3x=0=>x=2/3 hoặc 2+3x=0=>x=-2/3
b,x^2 +x+1/4=0
(x+1/2)^2 =0
x+1/2=0
x=-1/2
c,2x(x-3)+(x-3)=0
(x-3)(2x+1)=0
x-3=0=>x=3 hoặc 2x+1=0=>x=-1/2
d,3x(x-4)-x+4=0
3x(x-4)-(x-4)=0
(x-4)(3x-1)=0
x-4=0=>x=4 hoặc 3x-1=0=>x=1/3
e,x^3-1/9x=0
x(x^2-1/9)=0
x(x+1/3)(x-1/3)=0
x=0 hoặc x+1/3=0=>x=-1/3 hoặc x-1/3=0=>x=1/3
f,(3x-y)^2-(x-y)^2 =0
(3x-y-x+y)(3x-y+x-y)=0
2x(4x-2y)=0
4x(2x-y)=0
x=0hoặc 2x-y=0=>x=y/2
phan tich da thuc thanh nhan tu
a)a^2x+a^2y-7x-7y
b)x^4-x^3-x+1
c)x.(x+1)^2+x.(x-5)-5.(x+1)^2
d)a^3-a^2x-ay+xy
Đây mà là toán lớp 8ak
Đặt hết nhân tử chung ra là ra có gì đâu
Đây mà là toán lớp 8ak
Đặt hết nhân tử chung ra là ra có gì đâu
BT10: Thực hiện phép tính
\(a,\dfrac{4}{5}y^2x^5-x^3.x^2y^2\)
\(b,-xy^3-\dfrac{2}{7}y^2.xy\)
\(c,\dfrac{5}{6}xy^2z-\dfrac{1}{4}xyz.y\)
\(d,15x^4+7x^4-20x^2.x^2\)
\(e,\dfrac{1}{2}x^5y-\dfrac{3}{4}x^5y+xy.x^4\)
\(f,13x^2y^5-2x^2y^5+x^6\)
a: =-1/5x^5y^2
b: =-9/7xy^3
c: =7/12xy^2z
d: =2x^4
e: =3/4x^5y
f: =11x^2y^5+x^6
Bài 2 : Phân tích các đa thức thành nhân tử
a, x^4 - 2x^3 + 2x - 1
b, a^6 - a^4 + 2a^3 + 2a^2
c, x^4 + x^3 + 2x^2 + x + 1
d, x^4 + 2x^3 + 2x^2 + 2x + 1
e, x^2y + xy^2 + x^2z + y^2z + 2xyz
f, x^5 + x^4 + x^3 + x^2 + x + 1
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