Question

mn giup e vs a / lam chi tiet jup e nha ^^

phan tich thanh nhan tu / a)6x^4-9x^3

b) x^2y^2z+xy^2z^2+x^2yz^2

c)2x(x+3)+2(x+3)

d )(x+5)^2-3(x+5)

e)2x(x-3)-(x-3)^2

Answer 1

a) Ta có: \(6x^4-9x^3\)

\(=3x^3\cdot2x-3x^3\cdot3\)

\(=3x^3\left(2x-3\right)\)

b) Ta có: \(x^2y^2z+xy^2z^2+x^2yz^2\)

\(=xyz\cdot\left(xy+yz+xz\right)\)

c) Ta có: \(2x\left(x+3\right)+2\left(x+3\right)\)

\(=2\cdot\left(x+3\right)\cdot x+2\cdot\left(x+3\right)\cdot1\)

\(=2\left(x+3\right)\left(x+1\right)\)

d) Ta có: \(\left(x+5\right)^2-3\left(x+5\right)\)

\(=\left(x+5\right)\left(x+5-3\right)\)

\(=\left(x+5\right)\left(x+2\right)\)

e) Ta có: \(2x\left(x-3\right)-\left(x-3\right)^2\)

\(=\left(x-3\right)\left(2x-x+3\right)\)

\(=\left(x-3\right)\left(x+3\right)\)

Answer 2

a, 6x⁴ - 9x³ = 3x³ (2x-3x) = 3x³ (-x) = -3x⁴

b, x²y²z + xy²z² + x²yz² = xyz (xy+yz+xz)

c, 2x (x+3) + 2 (x+3) = (x+3) (2x+2) = (x+3) 2 (x+1)

d, (x+5)² - 3 (x+5) = (x+5) (x+5-3) = (x+5) (x+2)

e, 2x (x-3) - (x-3)² = (x-3) [2x-(x-3)] = (x-3) (2x-x+3) = (x-3) (x+3) = x² - 9

Tự làm á! Đúng sai thì chịu