a. x + \(\dfrac{3}{7}\)= \(\dfrac{2}{5}:\dfrac{18}{25}=>x+\dfrac{3}{7}=\dfrac{2}{5}\)x\(\dfrac{35}{18}=>x+\dfrac{3}{7}=\dfrac{7}{9}\)

=> x = \(\dfrac{7}{9}-\dfrac{3}{7}=\dfrac{49}{63}-\dfrac{27}{63}=\dfrac{22}{63}\)

b. \(x\) x \(\dfrac{5}{9}\)= \(\dfrac{4}{5}-\dfrac{1}{3}\)

=> \(x\) x \(\dfrac{5}{9}\)= \(\dfrac{12}{15}-\dfrac{5}{15}=>x\) x \(\dfrac{5}{9}\)= \(\dfrac{7}{15}\)

=> x = \(\dfrac{7}{15}:\dfrac{5}{9}\)

=> x = \(\dfrac{21}{25}\)

a,x + 3/7 = 2/5 : 18/35

   x + 3/7 = 7/9

   x          = 7/9 - 3/7

   x          = 22/63

vậy x = ...

b, X x 5/9 = 4/5 - 1/3

    X x 5/9 = 7/15

            X  = 7/15 : 5/9

            X  = 21/25

vậy X = ...

\(a.x+\dfrac{3}{7}=\dfrac{2}{5}:\dfrac{18}{35}\\x+\dfrac{3}{7}=\dfrac{2}{5}\times\dfrac{35}{18} \\ x+\dfrac{3}{7}=\dfrac{7}{9}\\ x=\dfrac{7}{9}-\dfrac{3}{7}\\ x=\dfrac{22}{63}\)

\(b.x\times\dfrac{5}{9}=\dfrac{4}{5}-\dfrac{1}{3}\\x\times\dfrac{5}{9}=\dfrac{7}{15}\\ x=\dfrac{7}{15}:\dfrac{5}{9}\\ x= \dfrac{21}{25}\)

mk đã giải cho bạn rồi nhé! bạn xem lại phần thông báo ạ!

\(\dfrac{4x+3}{5}-\dfrac{6x-2}{7}-\dfrac{5x+4}{3}>3\)

=>4/5x+3/5-6/7x+2/7-5/3x-4/3>3

=>-181/105x>362/105

=>x<-2

Ta có: |-2x +1| = -2x+1 khi -2x+1 ≥ 0 hay x ≤ \(\dfrac{1}{2}\)

           |-2x +1| = - ( -2x+1) = 2x-1 khi  -2x +1 < 0 hay x > \(\dfrac{1}{2}\)

Với x ≤ \(\dfrac{1}{2}\) ta có phương trình:

-2x+1  = x + 3

-2x - x = 3 - 1

   -3x   = 2

      x   =  \(\dfrac{-2}{3}\) ( nhận)

Với x > \(\dfrac{1}{2}\) ta có phương trình:

2x-1  = x + 3

2x - x = 3+1

       x = 4 (nhận)

Vậy phương trình có tập nghiệm S = {\(\dfrac{-2}{3};\) 4 }

a, Thay x = 3 và y = -6 vào bt ta đc

\(5.3-4.\left(-6\right)=15-\left(-24\right)=39\\ b,\\ 2.\left(-2\right)^2-5.4=8-20=\left(-12\right)\\ c,\\ 5.\left(-1\right)^2+3.\left(-1\right)-1=5+\left(-3\right)-1=1\)

a) Thay x=3; y=-6

\(5x-4y=5.3-4.\left(-6\right)=15+24=39\)

b) Thay x=-2; y=4

\(2x^4-5y=2.\left(-2\right)^4-5.4=32-20=12\)

c, Thay x=0

\(5x^2+3x-1=5.0+3.0-1=-1\)

+) x=-1

\(5x^2+3x-1=5.\left(-1\right)^2+3.\left(-1\right)-1=5-3-1=1\)

+) \(x=\dfrac{1}{3}\)

\(5x^2+3x-1=5.\left(\dfrac{1}{3}\right)^2+3.\dfrac{1}{3}-1\)

\(=\dfrac{5}{9}+1-1=\dfrac{5}{9}\)

  36 x ( 10 + 1 )

= 36 x 11

= 396

  36 x 10 + 36 x 1

= 360 + 36

= 396

Cách 1 :

36 x ( 10 + 1 )

= 36 x 11

= 396

Cách 2 :

36 x ( 10 + 1 )

= 36 x 10 + 36 x 1

= 360 + 36 

= 396

cách 1 :

36 x (10+1)

=36 x 11

= 396

cách 2:

36 x (10+1)

=(36 x 10) +( 36 x 1)

= 360         +      36

= 396

 k cho mik nha 

a) 1/2.x+3/5.(x-2)=3

<=>1/2.x+3/5.x-6/5=3

<=>11/10.x-6/5=3

<=>11/10x=41/10

<=>x=41/11

b) (3x-4).(5x+15)=0

<=>3x-4=0 hoặc 5x+15=0

<=>x=4/3 hoặc x=-3

\(-\dfrac{1}{2}x+6< 0\Leftrightarrow-\dfrac{1}{2}x< -6\Leftrightarrow\cdot\dfrac{1}{2}x>6\Leftrightarrow x>12\)

(sai thì thoi nha)

\(-\dfrac{1}{2}x+6< 0\)

\(\Leftrightarrow-\dfrac{1}{2}x< -6\)

\(\Leftrightarrow x>\left(-6\right):\left(-\dfrac{1}{2}\right)\)

\(\Leftrightarrow x>12\)

--> Chọn A