Muốn đc tick hơm -_- , vô đây cho zui
\(7^x+7^{2x+3}=344\)
Muốn tick nx k lè zô đây cho zui
3x=4x và y-x =3
Lại là câu hỏi tìm x nx nha mn
sai đề :>>>
Trả lời :
Đề : 3x = 4y, y - x = 3
\(\Rightarrow\frac{x}{3}=\frac{y}{4}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có :
\(\Rightarrow\frac{x}{3}=\frac{y}{4}=\frac{y-x}{4-3}=\frac{3}{1}=3\)
\(\Rightarrow\hept{\begin{cases}\frac{x}{3}=3\\\frac{y}{4}=3\end{cases}\Rightarrow\hept{\begin{cases}x=9\\y=12\end{cases}}}\)
8 + 3 x 7 = ??????????
có ai hơm kb với mk nha
mk tick cho
lm đc cho 3 tick
(x-3)*(2x-7)=0
\((x-3)(2x-7)=0\)
\(\Rightarrow\orbr{\begin{cases}x-3=0\\2x-7=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=3\\x=\frac{7}{2}\end{cases}}\)
Vậy \(x\in\left\{3;\frac{7}{2}\right\}\)
\(\left(x-3\right)\left(2x-7\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-3=0\\2x-7=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=3\\x=\frac{7}{2}\end{cases}}\)
Vậy ...
\(\left(x-3\right)\cdot\left(2x-7\right)=0\)
Ta có
\(+:::x-3=0=>x=3\)
\(+:::2x-7=0=>x=\frac{7}{2}\)
t ii ck mik
tìm x biết 7^2x+7^2x+3=344
\(7^{2x}+7^{2x+3}=344\\ 7^{2x}\left(1+343\right)=344\\ 7^{2x}.344=344\\ 7^{2x}=1\\ 2x=0\\ x=0\)
Vậy x = 0
Ta có: \(7^{2x}+7^{2x+3}=344\)
\(\Leftrightarrow7^{2x}+7^{2x}\cdot7^3=344\)
\(\Leftrightarrow7^{2x}\left(1+7^3\right)=344\)
\(\Leftrightarrow7^{2x}=1\)
\(\Leftrightarrow2x=0\)
Vì 2>0
nên x=0
Vậy: x=0
7^x + 7^x+3 = 344
mk làm đen :
7^x * 1 + 7^x * 7^3 = 344
7^x ( 1 + 7^3 ) = 344
7 ^x * ( 1+343 ) = 344
7^x * 344 = 344
7 ^x = 344 : 344
7 ^x = 1
k bt làm nx
- giúp mk vs ạ
tìm x biết
a)1/6+x=5/12
b3/4+1/4x=-1/2
c)7 mũ 2x +7 mũ 2x +3=344
\(\dfrac{1}{6}+x=\dfrac{5}{12}\)
\(=>x=\dfrac{5}{12}-\dfrac{2}{12}=\dfrac{1}{4}\)
\(\dfrac{3}{4}+\dfrac{1}{4}x=-\dfrac{1}{2}\)
\(=>\dfrac{1}{4}x=-\dfrac{5}{4}\)
\(=>x=-\dfrac{5}{4}.4=-5\)
\(7^{2x}+7^{2x+3}=344\)
\(< =>49^x+49^x.343=344\)
\(=>x=?\)
Tìm x ; 2x + 12=3.(x-7)
Ai trả lời đc mình sẽ tick cho
Ta có : 2x + 12 = 3 . ( x - 7 )
2x + 12 = 3x - 3 . 7
2x + 12 = 3x -21
2x + 12 + 21 = 3x
2x + 33 = 3x
33 = 3x - 2x
x = 33
\(2x+12=3\left(x-7\right)\)
\(\Leftrightarrow\)\(2x+12=3x-21\)
\(\Leftrightarrow\)\(3x-2x=12+21\)
\(\Leftrightarrow\)\(x=33\)
Vậy \(x=33\)
2x + 12 = 3 ( x - 7 )
2x + 12 = 3x - 21
2x - 3 x = -12 - 21
- 1x = - 33
x = - 33 : ( - 1 )
x = 33
\(7^{2x}+7^{2x+3}=344\)
\(7^{2x}+7^{2x+3}=344\)
\(7^{2x}+7^{2x}.7^3=344\)
\(7^{2x}+7^{2x}.343=344\)
\(7^{2x}.1+7^{2x}.343=344\)
\(7^{2x}.\left(1+343\right)=344\)
\(7^{2x}.344=344\)
\(7^{2x}=344:344\)
\(7^{2x}=1\)
\(\Rightarrow7^{2x}=7^0\)
\(2x=0\)
\(x=0:2\)
\(x=0\)
\(7^{2x}+7^{2x+3}=344\)
\(7^{2x}+7^{2x+3}=344\\\Rightarrow7^{2x}+7^{2x}\cdot7^3=344\\\Rightarrow7^{2x}\cdot(1+7^3)=344\\\Rightarrow7^{2x}\cdot(1+343)=344\\\Rightarrow7^{2x}\cdot344=344\\\Rightarrow7^{2x}=1\\\Rightarrow2x=0\\\Rightarrow x=0\)