\(x+-\dfrac{1}{9}=-\dfrac{1}{6}\)

\(\Rightarrow x-\dfrac{1}{9}=-\dfrac{1}{6}\)

\(\Rightarrow x=-\dfrac{1}{6}+\dfrac{1}{9}\)

\(\Rightarrow x=-\dfrac{1}{18}\)

_______________

\(5x-3x-\dfrac{5}{6}=\dfrac{2}{3}\)

\(\Rightarrow2x-\dfrac{5}{6}=\dfrac{2}{3}\)

\(\Rightarrow2x=\dfrac{2}{3}+\dfrac{5}{6}\)

\(\Rightarrow2x=\dfrac{3}{2}\)

\(\Rightarrow x=\dfrac{3}{2}:2\)

\(\Rightarrow x=\dfrac{3}{4}\)

Lời giải:

$15x^2-65x+110=-10$

$\Leftrightarrow 15x^2-65x+120=0$

$\Leftrightarrow 3x^2-13x+24=0$

$\Leftrightarrow 3(x^2-\frac{13}{3}x+\frac{13^2}{6^2})+\frac{119}{12}=0$

$\Leftrightarrow 3(x-\frac{13}{6})^2+\frac{119}{12}=0$ 

$\Leftrightarrow 3(x-\frac{13}{6})^2=-\frac{119}{12}<0$ (vô lý)

Vậy pt vô nghiệm/.

a) 2⁸

b) 10⁵

c) 8³ . 6³ . 7³

d) a⁹

e) 10⁹

f) 2x⁵

a. => \(2^{6+x}=2^{10}\)

=> 6+x=10

=> x=10-6

Vậy x=4.

b. => \(7^{3x-1}:7^2=7^6\)

=> 7^3x-1-2=7⁶

=> 7^3x-3=7⁶

=> 3x-3=6

=> 3x=6+3

=> 3x=9

Vậy x=3.

c. =>\(7^{5x-1}-25=24\)

=>7^5x-1=24+25

=>7^5x-1=49

=>7^5x-1=7²

=>5x-1=2

=>5x=3

Vậy x=\(\frac{3}{5}\).

d. => \(10^{x-3}=10^0\)

=>x-3=0

Vậy x=3.

e. => 2x=10

=> x=10:2

Vậy x=5.