\(\Leftrightarrow164-4\left(x-5\right)=80\\ \Leftrightarrow4\left(x-5\right)=84\\ \Leftrightarrow x-5=21\Leftrightarrow x=26\)

x x 3 + : 0,5=12,8

x x (3 + 2)=12,8

x x 5=12,8

x     = 12,8 :5

x      = 2,56

`5(x+2) -2x=18`

`=> 5x+10 -2x=18`

`=> 3x+10=18`

`=>3x=18-10`

`=>3x=8`

`=>x=8/3`

=>5x+10-2x=18

=>3x+10=18

=>3x=18-10=8

=>x=\(\dfrac{8}{3}\)

5x+10-2x=18

3x+10=18

3x=18-10=8

x=8/3

\(x\times10=124\)

\(x=12,4\)

=>3x-2x^2-3+2x+2x^2+6x-x-3=14

=>10x-6=14

=>x=2

\(\left(x-1\right)\left(3-2x\right)+\left(2x-1\right)\left(x+3\right)=14\)

\(\Leftrightarrow3x-2x^2-3+2x+2x^2+6x-x-3=14\)

\(\Leftrightarrow\left(-2x^2+2x^2\right)+\left(3x+2x+6x-x\right)-\left(3+3\right)=14\)

\(\Leftrightarrow10x-6=14\)

\(\Leftrightarrow10x=14+6\)

\(\Leftrightarrow10x=20\)

\(\Leftrightarrow x=20:10\)

\(\Leftrightarrow x=2\)

Vậy: \(x=2\)

D=|x-2010| + |x-2011| + |x-2012|
D=|x-2010| + |x-2011| + |2012-x|
=>D>=|x-2010+2012-x| + |x-2011|
=>D>=|2| + |x-2011|=2 + |x-2011|
Dấu = xảy ra <=> (x-2010)(2012-x)>=0<=>2010<=x<=2012(1)
                           x-2011=0 => x =2011(2)
Từ 1,2 => x=2011
Vậy Bmin=2 khi x=2011
 

=>(x-2023)[(x-2023)^21-1]=0

=>x-2023=0 hoặc x-2023=1

=>x=2023 hoặc x=2024

5; 5,01

\(2x-49=5.32\\ \Leftrightarrow2x-49=160\\ \Leftrightarrow2x=209\\ \Leftrightarrow x=\dfrac{209}{2}\)

\(200-\left(2x+6\right)=43\\ \Leftrightarrow2x+6=157\\ \Leftrightarrow2x=151\\ \Leftrightarrow x=\dfrac{151}{2}\)

\(135-5\left(x+4\right)=35\\ \Leftrightarrow5\left(x+4\right)=100\\ \Leftrightarrow x+4=20\\ \Leftrightarrow x=16\)

3.5.(x+4)=135-35

       x+4=100:5

       x    =20-4

       x    =16