Rút gọn biểu thức sau:\(A=\left[tan\frac{17\pi}{4}+tan\left(\frac{7\pi}{2}-x\right)\right]^2+\left[cot\frac{17\pi}{4}+cot\left(7\pi\right)-x\right]^2\)
Tính giá trị biểu thức:
\(P=\left[Tan\dfrac{17\Pi}{4}+Tan\left(\dfrac{7\Pi}{2}-x\right)\right]^2+\left[Cot\dfrac{13\Pi}{4}+Cot\left(7\Pi-x\right)\right]^2\)
\(P=\left[tan\dfrac{17\pi}{4}+tan\left(\dfrac{7\pi}{2}-x\right)\right]^2+\left[cot\dfrac{13\pi}{4}+cot\left(7\pi-x\right)\right]^2\)
\(=\left[tan\dfrac{\pi}{4}+tan\left(-\dfrac{\pi}{2}-x\right)\right]^2+\left[cot\left(-\dfrac{3\pi}{4}\right)+cot\left(-\pi-x\right)\right]^2\)
\(=\left[tan\dfrac{\pi}{4}-cotx\right]^2+\left[tan\dfrac{\pi}{4}-cotx\right]^2\)
\(=2\left(1-cotx\right)^2\)
Rút gọn các biểu thức sau:
a) \(\frac{1}{{\tan \alpha + 1}} + \frac{1}{{\cot \alpha + 1}}\)
b) \(\cos \left( {\frac{\pi }{2} - \alpha } \right) - \sin \left( {\pi + \alpha } \right)\)
c) \(\sin \left( {\alpha - \frac{\pi }{2}} \right) + \cos \left( { - \alpha + 6\pi } \right) - \tan \left( {\alpha + \pi } \right)\cot \left( {3\pi - \alpha } \right)\)
\(a,\dfrac{1}{tan\alpha+1}+\dfrac{1}{cot\alpha+1}\\ =\dfrac{cot\alpha+1+tan\alpha+1}{\left(tan\alpha+1\right)\left(cot\alpha+1\right)}\\ =\dfrac{tan\alpha+cot\alpha+2}{tan\alpha\cdot cot\alpha+tan\alpha+cot\alpha+1}\\ =\dfrac{tan\alpha+cot\alpha+2}{tan\alpha+cot\alpha+2}\\ =1\)
\(b,cos\left(\dfrac{\pi}{2}-\alpha\right)-sin\left(\pi+\alpha\right)\\ =sin\alpha+sin\alpha\\ =2sin\alpha\)
\(c,sin\left(\alpha-\dfrac{\pi}{2}\right)+cos\left(-\alpha+6\pi\right)-tan\left(\alpha+\pi\right)cot\left(3\pi-\alpha\right)\\ =-sin\left(\dfrac{\pi}{2}-\alpha\right)+cos\left(\alpha\right)-tan\left(\alpha\right)cot\left(\pi-\alpha\right)\\ =-cos\left(\alpha\right)+cos\left(\alpha\right)+tan\left(\alpha\right)\cdot cot\left(\alpha\right)\\ =1\)
GPT
a) \(tan\left(3x-\frac{\pi}{3}\right)=-tanx\)
b) \(cot\left(x-\frac{\pi}{4}\right)=-cotx\)
c) \(cot\left(2x-\frac{3\pi}{4}\right)=tan\left(x-\frac{\pi}{6}\right)\)
d) \(cos\left(2x+\frac{\pi}{3}\right)=-cos\left(x+\frac{\pi}{4}\right)\)
a.
ĐKXĐ: ...
\(\Leftrightarrow tan\left(3x-\frac{\pi}{3}\right)=tan\left(-x\right)\)
\(\Leftrightarrow3x-\frac{\pi}{3}=-x+k\pi\)
\(\Leftrightarrow x=\frac{\pi}{12}+\frac{k\pi}{4}\)
b.
ĐKXĐ: ...
\(\Leftrightarrow cot\left(x-\frac{\pi}{4}\right)=cot\left(-x\right)\)
\(\Leftrightarrow x-\frac{\pi}{4}=-x+k\pi\)
\(\Leftrightarrow x=\frac{\pi}{8}+\frac{k\pi}{2}\)
c.
ĐKXĐ: ...
\(\Leftrightarrow cot\left(2x-\frac{3\pi}{4}\right)=cot\left(\frac{2\pi}{3}-x\right)\)
\(\Leftrightarrow2x-\frac{3\pi}{4}=\frac{2\pi}{3}-x+k\pi\)
\(\Leftrightarrow x=\frac{17\pi}{36}+\frac{k\pi}{3}\)
d.
\(\Leftrightarrow cos\left(2x+\frac{\pi}{3}\right)=cos\left(\frac{3\pi}{4}-x\right)\)
\(\Leftrightarrow\left[{}\begin{matrix}2x+\frac{\pi}{3}=\frac{3\pi}{4}-x+k2\pi\\2x+\frac{\pi}{3}=x-\frac{3\pi}{4}+k2\pi\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\frac{5\pi}{36}+\frac{k2\pi}{3}\\x=-\frac{13\pi}{12}+k2\pi\end{matrix}\right.\)
\(\cos\left(5\Pi+x\right)+\sin\left(\frac{9\Pi}{2}-x\right)-\tan\left(\frac{3\Pi}{2}+x\right)\cot\left(\frac{3\Pi}{2}-x\right)\)
\(=cos\left(4\pi+\pi+x\right)+sin\left(4\pi+\frac{\pi}{2}-x\right)-tan\left(\pi+\frac{\pi}{2}+x\right).cot\left(\pi+\frac{\pi}{2}-x\right)\)
\(=cos\left(\pi+x\right)+sin\left(\frac{\pi}{2}-x\right)-tan\left(\frac{\pi}{2}+x\right).cot\left(\frac{\pi}{2}-x\right)\)
\(=-cosx+cosx-\left(-cotx\right).tanx\)
\(=1\)
Rút gọn các biểu thức sau:
1) \(A=2cosx+3cosx\left(\pi-x\right)-sin\left(\frac{7\pi}{2}-x\right)+tan\left(\frac{3\pi}{2}-x\right)\)
2) \(B=2sin\left(\frac{\pi}{2}+x\right)+sin\left(5\pi-x\right)+sin\left(\frac{3\pi}{2}+x\right)+cos\left(\frac{\pi}{2}+x\right)\)
\(A=2cosx-3cosx-sin\left(3\pi+\frac{\pi}{2}-x\right)+tan\left(\pi+\frac{\pi}{2}-x\right)\)
\(A=-cosx+sin\left(\frac{\pi}{2}-x\right)+tan\left(\frac{\pi}{2}-x\right)\)
\(A=-cosx+cosx+cotx=cotx\)
\(B=2cosx+sin\left(4\pi+\pi-x\right)+sin\left(2\pi-\frac{\pi}{2}+x\right)-sinx\)
\(B=2cosx+sin\left(\pi-x\right)+sin\left(-\frac{\pi}{2}+x\right)-sinx\)
\(B=2cosx+sinx-sin\left(\frac{\pi}{2}-x\right)-sinx\)
\(B=2cosx-cosx=cosx\)
Rút gọn các biểu thức sau :
a) A= 3sin(11\(\pi\) -x) sin(\(\frac{5\pi}{2}-x\)) +2sin(9\(\pi\)+x)
b) B=sin(1980\(^o\)+x)-cos(90\(^o\) -x)+tan(\(270^o-x\)) +cot (360\(^o\) -x)
c) C=-2sin(\(\frac{-5\pi}{2}\)+x)-3cos(3\(\pi\)-x)+5sin(\(\frac{7\pi}{2}\)-x)+cot(\(\frac{3\pi}{2}\)-x)
d) D=tan(x-\(\pi\)) cos (x-\(\frac{\pi}{2}\))cos(x+\(\pi\))
e) E=cos(\(\frac{115\pi}{2}-x\))+sin(\(x-\frac{235\pi}{2}\))+cos(x-\(\frac{187\pi}{2}\))+sin(\(\frac{143\pi}{2}-x\))
f) F= cot(x-\(107\pi\)) cos(x-\(\frac{303\pi}{2}\))+cos(x+1008\(\pi\))-3sin(x-1019\(\pi\))
g) G=cot(19\(\pi\)-x)+cos(x-37\(\pi\))+sin(\(-\frac{31\pi}{2}-x\))+tan(x-\(\frac{47\pi}{2}\))
h) H=cos(1170\(^o\)+x)+2sin(x-540\(^o\))-tan(630\(^o\)+x) cot(810\(^o\)-x)
i) I=\(\frac{sin\left(\pi-x\right)cos\left(x-\frac{9\pi}{2}\right)tan\left(9\pi+x\right)}{cos\left(7\pi-x\right)sin\left(\frac{7\pi}{2}-x\right)cot\left(x-\frac{17\pi}{2}\right)}\)
Nhìn đề bài hãi quá :(
a/ \(A=3\sin\left(5.2\pi+\pi-x\right).\sin\left(2\pi+\frac{\pi}{2}-x\right)+2\sin\left(4.2\pi+\pi+x\right)\)
\(A=3\sin\left(\pi-x\right).\sin\left(\frac{\pi}{2}-x\right)+2\sin\left(\pi+x\right)\)
\(A=3\sin x.\cos x-2\sin x=\sin x\left(3\cos x-2\right)\)
b/ \(B=\sin\left(5.2.180^0+180^0+x\right)-\cos\left(90^0-x\right)+\tan\left(90^0+180^0-x\right)+\cot\left(2.180^0-x\right)\)
\(B=\sin\left(180^0+x\right)-\sin x+\tan\left(90^0-x\right)+\cot\left(-x\right)\)
\(B=-\sin x-\sin x+\cot x-\cot x=-2\sin x\)
c/ \(C=-2\sin\left(-(2\pi+\frac{\pi}{2}-x)\right)-3\cos\left(2\pi+\pi-x\right)+5\sin\left(2.2\pi-\left(\frac{\pi}{2}+x\right)\right)+\cot\left(\pi+\frac{\pi}{2}-x\right)\)
\(C=2\sin\left(\frac{\pi}{2}-x\right)-3\cos\left(\pi-x\right)-5\sin\left(\frac{\pi}{2}+x\right)+\cot\left(\frac{\pi}{2}-x\right)\)
\(2\cos x+3\cos x-5\cos x+\tan x=\tan x\)
d/ \(D=\tan\left(-\left(\pi-x\right)\right).\cos\left(-\left(\frac{\pi}{2}-x\right)\right).\left(-\cos x\right)\)
\(D=\tan\left(\pi-x\right).\cos\left(\frac{\pi}{2}-x\right).\cos x\)
\(D=-\tan x.\sin x.\cos x=-\sin^2x\)
e/ \(E=\cos\left(28.2\pi+\pi+\frac{\pi}{2}-x\right)+\sin\left(-\left(58.2\pi+\pi+\frac{\pi}{2}-x\right)\right)+\cos\left(-\left(46.2\pi+\pi+\frac{\pi}{2}-x\right)\right)+\sin\left(35.2\pi+\pi+\frac{\pi}{2}-x\right)\)
\(E=-\cos\left(\frac{\pi}{2}-x\right)+\sin\left(\frac{\pi}{2}-x\right)-\cos\left(\frac{\pi}{2}-x\right)-\sin\left(\frac{\pi}{2}-x\right)\)
\(E=-2\sin x\)
Thôi, stop ở đây, làm nữa chắc tẩu hỏa nhập ma quá :(
Mình thấy hầu hết các bài này đều có chung 1 điểm, và chắc đó cũng là điểm mà bạn thắc mắc: Đó chính là tách các hạng tử ra và biến đổi
Tách cũng đơn giản thôi, cứ gặp sin, cos thì tách sao cho về dạng 2pi+..., gặp tan, cot thì pi.
Còn tách mấy cái phân số như vầy:
Ví dụ \(\frac{7\pi}{2}\) , 7 chia 2 được 3, ta lấy \(\frac{7}{2}-3=\frac{1}{2}\) thì suy ra: \(\frac{7\pi}{2}=3\pi+\frac{\pi}{2}\)
Đó, thế là được :D
a) Rút gọn biểu thức
\(A=\dfrac{\sin4x+2\sin2x}{\sin4x-2\sin2x}.\cot\left(\dfrac{3\pi}{2}-x\right)\) (khi biểu thức có nghĩa)
b) Cho \(\cot\alpha=\dfrac{4}{3},3\pi< \alpha< \dfrac{7\pi}{2}\). Tính \(\cos\left(\dfrac{2\pi}{3}-\alpha\right)\)
Cho \(\sin x=\frac{-1}{3}\).
Tính P=\(cos\left(2\pi-x\right).tan\left(\pi+x\right)-tan\left(\frac{\pi}{2}-x\right).cot\left(\pi-x\right)\).
\(P=cos\left(-x\right).tanx-cotx.\left(-cotx\right)\)
\(=cosx.tanx+cot^2x=sinx+cot^2x\)
\(=sinx+\frac{1}{1+sin^2x}=-\frac{1}{3}+\frac{1}{1+\frac{1}{9}}=\frac{17}{30}\)
Thu gọn biểu thức
\(A=sin\left(\pi+x\right)-cos\left(\frac{\pi}{2}-x\right)+cot\left(2\pi-x\right)\)
\(A=-sinx-sinx+cot\left(-x\right)=-2sinx-cotx\)