3. A

4. A

5. C

6. B

37. What is the price of the bicycle? (How much)

=> How much does the bicycle costs?

38. The tea doesn't taste the same as the one I usually drink. (from)

=> The tea tastes diferrently from the one I usually drink.

39. I really like listening to pop ballad songs. (fond)

=> I'm really fond of listening to pop ballad songs.

40. I want some iced tea because I am hot. (so)

=> I am hot so I want some iced tea.

37 How much is the bicycle?

38 This tea tastes different from the one I usually drink

39 I am really fond of pop ballad sóng

40 I am hot so I want some iced tea

Câu 1:

\(1,\\ a,=\sqrt{28,9\cdot90}=\sqrt{2601}=51\\ b,=\dfrac{\sqrt{15}}{5}\\ 2,ĐK:4x+16\ge0\Leftrightarrow x\ge-4\\ 3,\\ a,3\sqrt{2}=\sqrt{18}>\sqrt{15}\\ b,=6-2\cdot3-2=-2\)

Câu 2:

\(1,\\ a,=6\sqrt{3}+8\sqrt{3}-3\sqrt{3}=11\sqrt{3}\\ b,=\dfrac{\sqrt{5}+\sqrt{3}+\sqrt{5}-\sqrt{3}}{5-3}=\dfrac{2\sqrt{5}}{2}=\sqrt{5}\\ 2,\\ A=\dfrac{x\sqrt{x}-3x-x\sqrt{x}-3x}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\cdot\dfrac{-\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}{\sqrt{3}\sqrt{x}}\\ A=\dfrac{6x}{\sqrt{3}\sqrt{x}}=2\sqrt{3x}\)

\(3,\Leftrightarrow2x-3=7\Leftrightarrow x=5\)

29. My father never lets the children splash around in the pool for a while yesterday

30. Their parents always let them buy some sweets and candies when going shopping

31. Trees are planted in the garden

32. Dinner is cooked in the kitchen.

\(A=\left(x^2+y^2\right)^2-2x^2y^2=18^2-2\cdot5^2=274\)

1 B 

2 A

3 D

4 A

5 A

6 C

1:

#include <bits/stdc++.h>
using namespace std;
const long long maxn=1e6+10;
long long a[maxn],i,n;
int main()
{
    freopen("sxso.inp","r",stdin);
    freopen("sxso.out","w",stdout);
    cin>>n;
    for (i=1; i<=n; i++)
        cin>>a[i];
    sort(a+1,a+n+1);
    for (i=n; i>=1; i--)
        cout<<a[i]<<" ";
    return 0;
}

a và b có thể bằng 0 hoặc 5