\(\left(2x-3\right)\cdot4,8=\left(3x+1\right)\cdot\left(-2,4\right)\)

\(9,6x-14,4=-7,2x-2,4\)

\(9,6x+7,2x=14,4-2,4\)

\(16,8x=12\)

\(x=\dfrac{12}{16,8}=\dfrac{5}{7}\)

x = 5/7

P(x)=2x^4+2x^3-5x+3

Q(x)=4x^4-2x^3+2x^2+5x-2

P(x)+Q(x)

=2x^4+2x^3-5x+3+4x^4-2x^3+2x^2+5x-2

=6x^4+2x^2+1

   18/37 + 8/24 + 19/37 - 1/23/24 + 2/3

= 18/37 + 19/37 +  1/3 + 2/3 - 1/23/24

= 1 + 1 - 1/23/24

= 2 - 1/23/24

= 1/24

( chú ý : 1/3 là rút gọn của 8/24 )

\(\frac{18}{37}+\frac{8}{24}+\frac{19}{37}-1\frac{23}{24}+\frac{2}{3}\)

\(=\frac{18}{37}+\frac{1}{3}+\frac{19}{37}-1\frac{23}{24}+\frac{2}{3}\)

\(=\left(\frac{18}{37}+\frac{19}{37}\right)+\left(\frac{1}{3}+\frac{2}{3}\right)-1\frac{23}{24}\)

\(=1+1-1\frac{23}{24}\)

\(=2-1\frac{23}{24}=\frac{1}{24}\)

\(\frac{18}{27}+\frac{8}{24}+\frac{19}{37}-1\frac{23}{24}+\frac{2}{3}\)

\(=\frac{18}{27}+\frac{8}{24}+\frac{19}{37}-\frac{47}{24}+\frac{16}{24}\)

\(=\left(\frac{18}{37}+\frac{19}{37}\right)+\left(\frac{8}{24}+\frac{16}{24}\right)-\frac{47}{24}\)

\(=\frac{37}{37}+\frac{24}{24}-\frac{47}{24}\)

\(=1+1-\frac{47}{24}\)

\(=2-\frac{47}{24}\)

\(=\frac{48}{24}-\frac{47}{24}\)

\(=\frac{1}{24}\)

4) (3x-2)(x-3)= 3x(x-3)-2(x-3)

=3x.x+3x.(-3)-2.x-2.(-3)

=\(3x^2\)-9x-4x+6

=\(3x^2\)+(-9x-4x)+6

=\(3x^2\)-13x+6

5) (2x+1)(x+3)=2x(x+3)+1(x+3)

=2x.x+2x.3+1.x+1.3

=\(2x^2\)+6x+1x+3

=\(2x^2\)+(6x+1x)+3

=\(2x^2\)+7x+3

6) (x-3)(3x-1)=x(3x-1)-3(3x-1)

=x.3x+x.(-1)-3.3x-3.(-1)

=\(3x^2\)-1x-9x+3

=\(3x^2\)+(-1x-9x)+3

=\(3x^2\)-10x+3

rút gọn biểu thức

A) \(x^2\)-(x+4)(x-1)=\(x^2\)- x(x-1)-4(x-1)

=\(x^2\)-x.x-x.(-1)-4.x-4.(-1)

=\(x^2\)-\(x^2\)+1x-4x+4

=(\(x^2-x^2\))+(1x-4x)+4

= -3x+4

B) x(x+2)-(x-2)(x+4)=x.x+x.2-x(x+4)+2(x+4)

=\(x^2+2x\)-x.x-x.4+2.x+2.4

=\(x^2+2x-x^2-4x+2x+8\)

=(\(x^2-x^2\))+(2x-4x+2x)+8

=8

tính giá trị biểu thức

A=3(x-2)-(2+x)(x-3)

=3.x+3.(-2)-2(x-3)-x(x-3)

=3x-6-2.x-2.(-3)-x.x-x(-3)

=3x-6-2x+6-\(x^2\)+3x

=(3x-2x+3x)+(-6+6)\(-x^2\)

=4x - \(x^2\)

thay x=-8 vào biểu thức thu gọn ta được:

4.(-8)- (-8)\(^2\)

= - 32 +64

= 32

B= x(3-x)-(1+x)(1-x)

=x.3+x.(-x)-1(1-x)-x(1-x)

=3x -\(x^2\)-1.1-1 .(-x)-x.1-x.(-x)

=3x\(-x^2\)-\(1^2\)+1x-1x+\(x^2\)

=(3x+1x-1x)+(\(-x^2+x^2\))-1

=3x-1

thay x=-5 vào biểu thức thu gọn ta được:

3.(-5)-1

=-15-1

=-16

Thu gọn biểu thức

4) (3x - 2) (x - 3) 

= ( 3x² - 2x ) - ( 3x x 3 - 2 x 3 )

= 3x² - 2x - 3x x 3 + 2 x 3

= 3x² - 2x - 9x + 6

= 3x² - 11x + 6 

5) (2x + 1) (x + 3) 

= ( 2x² + 1x ) + ( 6x + 3 )

= 2x² + 1x + 6x + 3

= 2x² + 7x + 3

6) (x - 3) (3x - 1) 

= ( 3x² - 9x ) - ( x - 3 )

= 3x² - 9x - x + 3

= 3x² - 10 + 3

Rút gọn biểu thức

A) x^2 - (x + 4) (x - 1)

= x² - ( x² + 4x ) - ( x + 4 )

= x² - x² - 4x - x - 4

= -5x - 4

B) x (x + 2) - (x - 2) (x + 4)

= x² + 2x - ( x² - 2x ) + ( 4x - 8 )

= x² + 2x - x² + 2x + 4x - 8

= 8x - 8

Tính giá trị biểu thức

A = 3 (x - 2) - (2 + x) (x - 3) tại x = - 8

Thế x = -8 vào, ta có :

= 3 ( -8 -2 ) - ( 2 + -8 ) ( -8 - 3 )

= 3 x ( -10 ) - ( - 6 ) ( -11 )

= -30 - 66

= -96

B = x (3 - x) - (1 + x) ( 1 - x) tại x = - 5

Thế x = - 5 vào, ta có :

= -5 ( 3 - -5 ) - ( 1+ -5 ) ( 1 - -5 )

= -5 x 8 - (-4) x 6

= - 40 - -24

= -40 + 24

= -16

100% đúng 

hok tốt nha 

3 x 6 + 3 x 70 + 24 x 3

= 3 x (6 + 70 + 24)

= 3 x 100

= 300

   3 x 6 + 3 x 70 + 24 x 3

= 3 x (6 + 70 + 24)

= 3 x 100 = 300

3x6+3x70+24x3

=3x (6+70+24)

=3x100

=300

\(\left(3x+2\right)^3=11.121=11.11^2=11^3\\ Nên:3x+2=11\\ Vậy:3x=11-2=9\\ Vậy:x=\dfrac{9}{3}=3\)

\(\left(3x+2\right)^3=11\cdot121\)

\(\Rightarrow\left(3x+2\right)^3=11^3\)

\(\Rightarrow3x+2=11\)

\(\Rightarrow3x=11-2\)

\(\Rightarrow3x=9\)

\(\Rightarrow x=\dfrac{9}{3}\)

\(\Rightarrow x=3\)

ngu quá

ê ku giải đc hông mà bảo tui ngu 

(2¹⁷ + 17²) . (9¹⁵ - 3¹⁵) . (2⁴ - 4²)

= (2¹⁷ + 17²) . (9¹⁵ - 3¹⁵) . (16 - 16)

= (2¹⁷ + 17²) . (9¹⁵ - 3¹⁵) . 0

= 0