A= (3x+4)^3

thay vào ta được : (3*32+4)^3=1000000

- Kết quả là 1000000

- Đúng thì k hộ mình nhé :))

108x(x-43)=0

\(\Rightarrow\left[{}\begin{matrix}108x=0\\x-43=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=43\end{matrix}\right.\)

108𝑥²−4644𝑥

thank ban

\(x+53,67=139,5\times12\)

\(x+53,67=1674\)

\(x=1620,33\)

\(x-42,3=21,15+13,7\)

\(x-42,3=34,85\)

\(x=77,15\)

\(7,2+x:4=108\)

\(x:4=100,8\)

\(x=403,2\)

\(x\times4-7,2=10,8\)

\(x\times4=18\)

\(x=4,5\)

x + 53,67 = 139,5 x 12

x+53,67=1674

x=1674-53,67

x=1620,33

x - 42,3 = 21,15 + 13,7

x-42,3=34,85

x=34,85+42,3

x=77,15

7,2 + x : 4 = 108

x:4=108-7,2

x:4=100,8

x=100,8x4

x=403,2

x x 4 -7,2 =10,8

x x 4=10,8+7,2

x x 4=18

x=18:4

x=4,5

`x + 53,67 = 139,5 xx 12`

`=>x + 53,67 = 1674`

`=>x=1674-53,67`

`=>x=1620,33`

`-------`

`x - 42,3 = 21,15 + 13,7`

`=>x - 42,3 =34,85`

`=>x=34,85+42,3`

`=>x=77,15`

`-------`

`7,2 + x : 4 = 108`

`=>x:4=108-7,2`

`=>x:4=100,8`

`=>x=100,8 xx 4`

`=>x=403,2`

`-------`

`x xx 4 -7,2 =10,8`

`=>x xx 4=10,8 + 7,2`

`=>x xx 4= 18`

`=>x=18:4`

`=>x=4,5`

tồn tại với x= 5

\(\sqrt{108x^3}.\sqrt{3x}=\sqrt{108x^3.3x}=\sqrt{324x^4}=18x^2\)( vì x >= 0)

\(a,M=27x^3+108x^2+144x+64=\left(3x+4\right)^2\)Tại \(x=32\Rightarrow M=\left(3.32+4\right)^3=100^3=1000000\)

\(b,N=27x^3-54x^2+36x-8=\left(3x-2\right)^3\)

Tại \(x=14\Rightarrow N=\left(3.14-2\right)^3=40^3=64000\)

c)
\(x^3-3.x^2.6+3.x.6^2-6^3=0\)
\(\left(x-6\right)^3=0\)
x-6=0
x=6
d)
\(x^3-3.x^2.1+3.x.1^2-1-x^3-3x-2=0\)
\(x^3-3x^2+3x-1-x^3-3x^2-2=0\)
\(-6x^2-3=0\)
\(-3\left(2x^2+1\right)=0\)
\(2x^2+1=0\)
2x²=-1
x²=1/2
x=\(\dfrac{\sqrt{2}}{2}\)