Tìm x , biết :
a, 5x - 6 = 12 - x
b, 2 - ( x+2 ) 3 = -25
c, 3.( x - 2) > 0
Tìm x , biết :
a, 5x - 6 = 12 - x
b, 2 - ( x+2 ) 3 = -25
c, 3.( x - 2) > 0
a)5x-16=12-x
<=> 5x-x=12+16
<=> 4x=28
<=> x=7
c) Để 3(x-2)>) thì x-2>0 vì 3>0
=> x>2
Vậy để 3(x-2) >0 thì x>2
a,5x - 6 = 12 - x
=> 12 - x - (5x - 6) = 0
=> 12 - x - 5x + 6 = 0
=> 12 - (x + 5x) = 6
=> 12 - x(5 + 1) = 6
=> 12 - x6 = 6
=> x6 = 12 - 6
=> x6 = 6
=> x = 6 : 6
=> x = 1
mik làm nhầm nha
Tìm x, biết:
a) (x - 3.5).12 = 0;
b) 35. (x - 10) = 35;
c) ( x - 5): 3 + 3 = 24
d) ( x - 4) : 3 - 2 = 100
c) 25.(2.x - 4).12 = 0
d) (x - 4) : 6 - 5 = 10
Tìm x, biết:
a) (x - 3.5).12 = 0; b) 35. (x-10) = 35;
c) ( x -5): 3 + 3 = 24 d) ( x- 4) : 3 - 2 = 100
c) 25.(2.x - 4).12 = 0 d) (x- 4) : 6 - 5 = 10
a) x = 15. b) x = 11. c) x = 68. d) x = 310
Tìm xx biết: \left(x^{4}\right)^{3}=\dfrac{x^{19}}{x^{6}}(x4)3=x6x19
Trả lời: x=x=
Tìm x
a) ( x + 7 ) - 25 = 135x + 2x =6^5 - 5^0
b) 5x + x = 150 : 2 + 3
c) 6x + x = 5^11 : 5^9 + 3^1
d) 5x + 3x = 3^6 : 3^3 . 4 + 12
BT8: Tìm x, biết
\(a,\left(x-2\right)\left(x-3\right)=0\)
\(b,x^2-5x=0\)
\(c,x^2-9=0\)
\(d,4x^2-25=0\)
`@` `\text {Ans}`
`\downarrow`
`a,`
`(x - 2)(x - 3) =0`
`<=>`\(\left[{}\begin{matrix}x-2=0\\x-3=0\end{matrix}\right.\)
`<=>`\(\left[{}\begin{matrix}x=0+2\\x=0+3\end{matrix}\right.\)
`<=>`\(\left[{}\begin{matrix}x=2\\x=3\end{matrix}\right.\)
Vậy, `S = {2; 3}`
`b,`
`x^2 - 5x = 0`
`<=> x(x - 5) = 0`
`<=>`\(\left[{}\begin{matrix}x=0\\x-5=0\end{matrix}\right.\)
`<=>`\(\left[{}\begin{matrix}x=0\\x=0+5\end{matrix}\right.\)
`<=>`\(\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)
Vậy, `S = {0; 5}`
`c,`
`x^2 - 9 = 0`
`<=> x^2 = 0 + 9`
`<=> x^2 = 9`
`<=> x^2 = (+-3)^2`
`<=> x = +-3`
Vậy, `S = {3; -3}`
`d,`
`4x^2 - 25 = 0`
`<=> 4x^2 = 25`
`<=> x^2 = 25/4`
`<=> x^2 = (+-5/2)^2`
`<=> x = +-5/2`
Vậy,` S = {5/2; -5/2}.`
a: =>x-2=0 hoặc x-3=0
=>x=2 hoặc x=3
b: =>x(x-5)=0
=>x=0 hoặc x=5
c: =>(x-3)(x+3)=0
=>x=3 hoặc x=-3
d: =>(2x-5)(2x+5)=0
=>x=5/2 hoặc x=-5/2
Tìm x, biết : a.,(x-y)^2-(x-3).(x+3)=6; b, x^2-5x=0;c,x^2+6x+5=0
thanks các bạn rất nhìu ạk!!
tìm x:
a) 2^3 - 50x = 0
b) x^2 - 25 + 2 ( x + 5 ) = 0
c) x^3 - 3 = 0
d) 5x ( x - 3 ) - 2x + 6 = 0
Bài 7. Tìm x,biết:
a) x-3x2=0 e) 5x(3x-1)+x(3x-1)-2(3x-1)=0
b) (x+3)2-x(x-2)=13 c) (x-4)2-36=0
d) x2-7x+12=0 g) x2-2018x-2019=0
Bài 8. Tìm x, biết
a) (2x-1)2=(x+5)2 b) x2-x+1/4
c) 4x4-101x2+25=0 d) x3-3x2+9x-91=0
1,tìm x a) (x+3)^2-(x-2)^3=(x+5)(x^2-5x+25)-108 b) 4(x^2+2x-1)^2-(2x^2-3)^2=0 c) (2x-1)(4x^2+2x+1)-(x-2)^2=-x(x-6)-5
a) \(\left(x+3\right)^2-\left(x-2\right)^3=\left(x+5\right)\left(x^2-5x+25\right)-108\)
\(\Leftrightarrow x^2+6x+9-x^2+4x-4=x^3-5x^2+25x+5x^2-25x+125-108\)
\(\Leftrightarrow x^3-10x+12=0\Leftrightarrow\left(x-2\right)\left(x^2+2x+6\right)=0\)
\(\Leftrightarrow x=2\)( do \(x^2+2x+6=\left(x+1\right)^2+4\ge4>0\))