a)5x-16=12-x

<=> 5x-x=12+16

<=> 4x=28

<=> x=7

c) Để 3(x-2)>) thì x-2>0 vì 3>0

=> x>2

Vậy để 3(x-2) >0 thì x>2

a,5x - 6 = 12 - x

=> 12 - x - (5x - 6) = 0

=> 12 - x - 5x + 6 = 0

=> 12 - (x + 5x) = 6 

=> 12 - x(5 + 1) = 6

=> 12 - x6 = 6

=> x6 = 12 - 6

=> x6 = 6

=> x = 6 : 6

=> x = 1

mik làm nhầm nha

a) x = 15

b) x = 11

c) x = 68

d) x = 310

(x4)3=x6x19

a) x = 15.              b)      x = 11.        c) x = 68.              d) x = 310

Tìm xx biết:    \left(x^{4}\right)^{3}=\dfrac{x^{19}}{x^{6}}(x4)3=x6x19​

Trả lời: x=x= 

nhấn vào đúng 0 sẽ có câu trả lời

`@` `\text {Ans}`

`\downarrow`

`a,`

`(x - 2)(x - 3) =0`

`<=>`\(\left[{}\begin{matrix}x-2=0\\x-3=0\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x=0+2\\x=0+3\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x=2\\x=3\end{matrix}\right.\)

Vậy, `S = {2; 3}`

`b,`

`x^2 - 5x = 0`

`<=> x(x - 5) = 0`

`<=>`\(\left[{}\begin{matrix}x=0\\x-5=0\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x=0\\x=0+5\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)

Vậy, `S = {0; 5}`

`c,`

`x^2 - 9 = 0`

`<=> x^2 = 0 + 9`

`<=> x^2 = 9`

`<=> x^2 = (+-3)^2`

`<=> x = +-3`

Vậy, `S = {3; -3}`

`d,`

`4x^2 - 25 = 0`

`<=> 4x^2 = 25`

`<=> x^2 = 25/4`

`<=> x^2 = (+-5/2)^2`

`<=> x = +-5/2`

Vậy,` S = {5/2; -5/2}.`

a: =>x-2=0 hoặc x-3=0

=>x=2 hoặc x=3

b: =>x(x-5)=0

=>x=0 hoặc x=5

c: =>(x-3)(x+3)=0

=>x=3 hoặc x=-3

d: =>(2x-5)(2x+5)=0

=>x=5/2 hoặc x=-5/2

Bài 1.

a) \(\left(x+3\right)^2-\left(x-2\right)^3=\left(x+5\right)\left(x^2-5x+25\right)-108\)

\(\Leftrightarrow x^2+6x+9-x^2+4x-4=x^3-5x^2+25x+5x^2-25x+125-108\)

\(\Leftrightarrow x^3-10x+12=0\Leftrightarrow\left(x-2\right)\left(x^2+2x+6\right)=0\)

\(\Leftrightarrow x=2\)( do \(x^2+2x+6=\left(x+1\right)^2+4\ge4>0\))