tim GTLN
B=\(\frac{-4}{x^2-4}\)
Tìm GTNN hoặc GTLN
B=|2x+1|+|2x3|
C=3căn bậc 2 của 2x-1+3/4
Tìm x ϵ N để P=\(\dfrac{\sqrt{x}+2}{\sqrt{x}-3}\)
a) Đạt GTLN
b) Đạt GTNN
a: \(P=\dfrac{\sqrt{x}-3+5}{\sqrt{x}-3}=1+\dfrac{5}{\sqrt{x}-3}\)
căn x-3>=-3
=>5/căn x-3<=-5/3
=>P<=-5/3+1=-2/3
Dấu = xảy ra khi x=0
Tim x:
\(x-\frac{\frac{x}{2}-\frac{x}{3}}{4}-\frac{x}{6}=\frac{2\left(1+x\right)}{3}-\frac{\frac{x}{3}+\frac{1-x^7}{4}}{2}\)
\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)
tim x
\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)
\(\Rightarrow\left(\frac{x+1}{99}+1\right)+\left(\frac{x+2}{98}+1\right)+\left(\frac{x+3}{97}+1\right)+\left(\frac{x+4}{96}+1\right)=-4+4\)
\(\Rightarrow\frac{x+100}{99}+\frac{x+100}{98}+\frac{x+100}{97}+\frac{x+100}{96}=0\)
\(\Rightarrow\left(x+100\right).\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\right)=0\)
Mà \(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}>0\)
\(\Rightarrow x+100=0\)
\(\Rightarrow x=0-100\)
\(\Rightarrow x=-100\)
Chúc bạn học tốt !!!!
\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)
\(\Leftrightarrow\left(\frac{x+1}{99}+1\right)+\left(\frac{x+2}{98}+1\right)+\left(\frac{x+3}{97}+1\right)+\left(\frac{x+4}{96}+1\right)=0\)
\(\Leftrightarrow\frac{x+100}{99}+\frac{x+100}{98}+\frac{x+100}{97}+\frac{x+100}{96}=0\)
\(\Leftrightarrow\left(x+100\right)\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\right)=0\)
\(\Leftrightarrow x+100=0\)
\(\Leftrightarrow x=-100\)
Vậy...
\(\Rightarrow\left(\frac{x+1}{99}+1\right)+\left(\frac{x+2}{98}+1\right)+\left(\frac{x+3}{97}+1\right)+\left(\frac{x+4}{96}+1\right)=-4+1+1+1+1\)
\(\Rightarrow\frac{x+100}{99}+\frac{x+100}{98}+\frac{x+100}{97}+\frac{x+100}{96}=0\)
\(\Rightarrow\left(x+100\right).\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\right)=0\)
Vì 1/99+1/98+1/97+1/96>0
\(\Rightarrow x+100=0\Rightarrow x=-100\)
tim x
\(8\left(x+\frac{1}{x}\right)^2+4\left(x^2+\frac{1}{x^2}\right)-4\left(x^2+\frac{1}{x^2}\right)\left(x+\frac{1}{x}\right)^2=\left(x+4\right)^2\)
Nhân hết ra,giải phương trình bậc cao đi
1) Cho bieu thức: \(C=\left(\frac{4}{x-4}-\frac{4}{x+4}\right):\frac{x^2+8x+16}{32}\)
a) tim ĐKXĐ của C va rút gọn C
b) Tim x de C = 1/3
c) Tim x de C=1
d) Tìm x thuộc Z để C thuộc Z
e) Tìm x để C>0
1. Tim nghiem nguyen cua pt:
\(\sqrt{9x^2+16x+96}=3x-16y-24\)
2. Tim nghiem nguyen duong:
\(2+\sqrt{x+\frac{1}{4}+\sqrt{x+\frac{1}{4}}}=4\)
Không biết bạn có gõ đúng đề cả 2 câu không ? Câu 2 không có nghiệm nguyên dương nhé bạn. Bạn xem lại.
có đúng đề không bạn
tim x
\(\frac{1\frac{1}{2}}{3\frac{1}{2}}=\frac{x}{4}\)
\(\text{đề }\Rightarrow3\frac{1}{2}.x=1\frac{1}{2}.4\)
\(\frac{7}{2}x=6\)
\(x=\frac{12}{7}\)
từng bước nè b
Tim x : \(\frac{2}{\left(x+2\right)\left(x+4\right)}+\frac{4}{\left(x+4\right)\left(x+8\right)}+\frac{6}{\left(x+8\right)\left(x+14\right)}=\frac{x}{\left(x+2\right)\left(x+14\right)}\)
\(A=\frac{\sqrt{x}+4}{\sqrt{x}+2};B=\left(\frac{\sqrt{x}}{\sqrt{x}+4}+\frac{4}{\sqrt{x}-4}\right):\frac{x+16}{\sqrt{x}+2}\)
a. rut gon B
b. Tim x nguyen de P = B(A-1) nguyen
giup minh voi a