\(7^{2x}+7^{2x}.7^3=344\)
\(7^{2x}+7^{2x+3}=344\)
\(7^{2x}+7^{2x+3}=344\)
\(7^{2x}+7^{2x}.7^3=344\)
\(7^{2x}+7^{2x}.343=344\)
\(7^{2x}.1+7^{2x}.343=344\)
\(7^{2x}.\left(1+343\right)=344\)
\(7^{2x}.344=344\)
\(7^{2x}=344:344\)
\(7^{2x}=1\)
\(\Rightarrow7^{2x}=7^0\)
\(2x=0\)
\(x=0:2\)
\(x=0\)
\(7^{2x}+7^{2x+3}=344\)
\(7^{2x}+7^{2x+3}=344\\\Rightarrow7^{2x}+7^{2x}\cdot7^3=344\\\Rightarrow7^{2x}\cdot(1+7^3)=344\\\Rightarrow7^{2x}\cdot(1+343)=344\\\Rightarrow7^{2x}\cdot344=344\\\Rightarrow7^{2x}=1\\\Rightarrow2x=0\\\Rightarrow x=0\)
tìm x biết 7^2x+7^2x+3=344
\(7^{2x}+7^{2x+3}=344\\ 7^{2x}\left(1+343\right)=344\\ 7^{2x}.344=344\\ 7^{2x}=1\\ 2x=0\\ x=0\)
Vậy x = 0
Ta có: \(7^{2x}+7^{2x+3}=344\)
\(\Leftrightarrow7^{2x}+7^{2x}\cdot7^3=344\)
\(\Leftrightarrow7^{2x}\left(1+7^3\right)=344\)
\(\Leftrightarrow7^{2x}=1\)
\(\Leftrightarrow2x=0\)
Vì 2>0
nên x=0
Vậy: x=0
tìm x biết
a)1/6+x=5/12
b3/4+1/4x=-1/2
c)7 mũ 2x +7 mũ 2x +3=344
\(\dfrac{1}{6}+x=\dfrac{5}{12}\)
\(=>x=\dfrac{5}{12}-\dfrac{2}{12}=\dfrac{1}{4}\)
\(\dfrac{3}{4}+\dfrac{1}{4}x=-\dfrac{1}{2}\)
\(=>\dfrac{1}{4}x=-\dfrac{5}{4}\)
\(=>x=-\dfrac{5}{4}.4=-5\)
\(7^{2x}+7^{2x+3}=344\)
\(< =>49^x+49^x.343=344\)
\(=>x=?\)
\(7^{2x}+7^{2x+3}=344\)
Giúp mik vs
mink cần gấp
\(7^{2x}+7^{2x+3}=344\)
\(\Leftrightarrow7^{2x}+7^{2x}.343=344\)
\(\Leftrightarrow7^{2x}\left(1+343\right)=344\)
\(\Leftrightarrow7^{2x}.344=344\)
\(\Leftrightarrow7^{2x}=1\)
\(\Leftrightarrow7^{2x}=7^0\)
\(\Leftrightarrow2x=0\)
\(\Leftrightarrow x=0\)
Vậy \(x=0\)
\(\Leftrightarrow7^{2x}\left(1+7^3\right)=344\)
\(\Leftrightarrow7^{2x}.344=344\)
\(\Leftrightarrow7^{2x}=1\)
\(\Rightarrow x=0\)
Tìm x biết
7x + 72x+3 = 344
7^x + 7^2x+3=344
7^x + 7^2x . 7^3 =344
7^x + 7^2 . 7^x . 7^3 =344
7^x . (7^2+1) . 7^3 = 344
7^x . 50 . 343 =344
làm tiếp ........
tim x
7x + 72x+3 = 344
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bác nhắn linh tinh cái gì thế ???
Muốn đc tick hơm -_- , vô đây cho zui
\(7^x+7^{2x+3}=344\)
Nếu x = 0 => \(7^0+7^{2.0+3}=344\)
=> \(344=344\) (luôn đúng)
Vậy x = 0 là nghiệm của pt
Nếu x > 0 => VP= \(344\equiv1\left(mod7\right)\)
VT = \(7^x+7^{2x+3}⋮7\)
=> VT \(\ne\)VP => x > 0 không là nghiệm của pt
Nếu x < 0 => \(7^x+7^{2x+3}< 344\)
=> x < 0 không là nghiệm của pt
Vậy x = 0
7^x + 7^x+3 = 344
mk làm đen :
7^x * 1 + 7^x * 7^3 = 344
7^x ( 1 + 7^3 ) = 344
7 ^x * ( 1+343 ) = 344
7^x * 344 = 344
7 ^x = 344 : 344
7 ^x = 1
k bt làm nx
- giúp mk vs ạ