{ 2 . 3² + [ 144 - 5² . ( 15 - 169 : 13 ) ] } - 1²⁰¹⁹

= { 2 . 9 + [ 144 - 25 . ( 15 - 13 ) ] } - 1

= { 18 + [ 144 - 25 . 2 ] } - 1

= { 18 + [ 144 - 50 ] } - 1

= 18 + 94 - 1

= 112 - 1

= 111

{2 . 3^2 + (144 - 5^2 . (15 - 169 : 13))} - 1^2019

= {2 . 9 + (144 - 25 . ( 15 - 169 : 13))} - 1

= {2 . 9 + (144 - 25 . ( 15 - 13))} - 1

= {2 . 9 + (144 - 25 . 2)} - 1

= {2 . 9 + (144 - 50)} - 1

= {2 . 9 + 94} - 1

= {18 + 94} - 1

= 112 - 1

= 111

\(\left(2\cdot3^2+\left(144-5^2\cdot\left(15-169:13\right)\right)\right)-9999^0\)

\(=\left(2\cdot9+\left(144-25\cdot\left(15-13\right)\right)\right)-1\)

\(=\left(18+\left(144-25\cdot2\right)\right)-1\)

\(=\left(18+\left(144-50\right)\right)-1\)

\(=\left(18+94\right)-1\)

\(=112-1\)

\(=111\)

a) \(96 : 2^4 + 3^2 - 2018^0 \)

= 96 : 16 + 9 - 1

= 6 + 9 - 1

= 15 - 1

= 14

b) 32 . 77 + 33 . 24 - 32

= 2541 + 768 - 32

= 3309 - 32

= 3327

c) \({2 . 3^2 + [144 - 5^2 . (15 - 169 : 13)]} - 1^2019\)

1^2019 nha bạn

= 2 . 9 + [144 - 25 . (15 - 169 : 13)]}- 1

= 2 . 9 + [144 - 25 . (15 - 13)]}- 1

= 2 . 9 + [144 - 25 . 2]}- 1

= 2 . 9 + [144 - 50]}- 1

= 2 . 9 + 94 - 1

= 18 + 94 - 1

= 112 - 1

= 111

d) 5^27 . 5 : 5^25 + -125 = 0

1: 8=2^3

2: 25=5^2

3: 4=2^2

4: 49=7^2

5: 81=9^2

6: 36=6^2

7: 100=10^2

8: 121=11^2

9: 144=12^2

10: 169=13^2

11: 27=3^3

12: 125=5^3

13: 1000=10^3

14: 32=2^5

15: 243=3^5

16: 343=7^3

17: 216=6^3

18: 64=4^3

19: 225=15^2

20: 128=2^7

Lời giải:
Áp dụng tính chất dãy tỉ số bằng nhau:

$\frac{3x+25}{144}=\frac{2y-169}{25}=\frac{z+144}{169}=\frac{3x+25+2y-169+z+144}{144+25+169}=\frac{(3x+2y+z)+25-169+144}{144+25+169}=\frac{1}{2}$

Suy ra:

$3x+25=144.\frac{1}{2}=72\Rightarrow x=\frac{47}{3}$

$2y-169=25.\frac{1}{2}\Rightarrow y=\frac{363}{4}$

$z+144=169.\frac{1}{2}\Rightarrow z=\frac{-119}{2}$

P/s: Lần sau bạn lưu ý ghi đầy đủ yêu cầu đề bài.

\(\frac{144}{17}x\frac{34}{12}=24\)

\(\frac{169}{34}:\frac{13}{68}=26\)

N is: 25

\(M=\frac{2^{13}.3^7}{2^{15}.3^2.9^2}=\frac{2^{13}.3^7}{2^{13}.2^2.3^2.\left(3.3\right)^2}=\frac{2^{13}.3^7}{2^{13}.2^2.3^8}=\frac{1}{4.3}=\frac{1}{12}\)

a)128-(x+56)=15

x+56=128-15

x+56=113

x=113-56

x=57

b)45+(34-x)=67

34-x=67-45=22

x=34-22

x=12

a) \(A=\dfrac{2^6\cdot9^2}{6^4\cdot8}\)

\(=\dfrac{2^6\cdot\left(3^2\right)^2}{3^4\cdot2^4\cdot2^3}\)

\(=\dfrac{2^6\cdot3^4}{3^4\cdot2^7}\)

\(=\dfrac{1}{2}\)

b) \(B=\dfrac{2^{13}\cdot3^7}{2^{15}\cdot3^2\cdot9^2}\)

\(=\dfrac{2^{13}\cdot3^7}{2^{15}\cdot3^2\cdot\left(3^2\right)^2}\)

\(=\dfrac{2^{13}\cdot3^7}{2^{15}\cdot3^6}\)

\(=\dfrac{3}{2^2}\)

\(=\dfrac{3}{4}\)

\(A=\dfrac{2^6.9^2}{6^4.8}=\dfrac{2^6.3^4}{2^7.3^4}=\dfrac{1}{2}\)

\(B=\dfrac{2^{13}.3^7}{2^{15}.3^2.9^2}=\dfrac{3^7}{2^2.3^6}=\dfrac{3}{4}\)