\(x^6-9x^5+30x^4-45x^3+30x^2-9x+1\)

\(=\left(x^2\right)^3-9x^5+30x^4-45x^3+30x^2-9x+1^3\)

\(=\left(x^3-3x+1\right)^3\)

\(3x^2-7x+4=\left(3x^2-3x\right)-\left(4x-4\right)=3x\left(x-1\right)-4\left(x-1\right)=\left(x-1\right)\left(3x-4\right)\)

3x^2 -7x+4

= 3x^2 -3x-4x+4

= 3x ( x-1) -4(x-1)

= (3x-4)(x-1)

3x^2 - 7x  + 4 =3x ^2 - 4x - 3x  + 4 = 3x(x-1) - 4 ( x+ 1)= (3x-4)(x-1)

1: \(x^2-2x-24=\left(x-6\right)\left(x+4\right)\)

2: \(x^2-8x+15=\left(x-3\right)\left(x-5\right)\)

3: \(x^2-9x+14=\left(x-2\right)\left(x-7\right)\)

\(9x^2+6x-4y^2+4y=\left(9x^2+6x+1\right)-\left(4y^2-4y+1\right)=\left(3x+1\right)^2-\left(2y-1\right)^2=\left(3x+1-2y+1\right)\left(3x+1+2y-1\right)\)

\(9x^2+6x-4y^2+4y=\left(9x^2+6x+1\right)-\left(4y^2-4y+1\right)=\left(3x+1\right)^2-\left(2x-1\right)^2=\left(3x+1-2y+1\right)\left(3x+1+2y-1\right)=\left(3x-2x+2\right)\left(3x+2y\right)\)

\(9x^2+6x-4y^2+4y\)

\(=\left(3x+2y\right)\left(3x-2y\right)+2\left(3x+2y\right)\)

\(=\left(3x+2y\right)\left(3x-2y+2\right)\)

7x-7y+ax-ay=(7x-7y)+(ax-ay)=7(x-y)+a(x-y)=(x-y)(7+a)

7x-7y+ax-ay

=(7x-7y)+(ax-ay)

=7(x-y)+a(x-y)

=(x-y)(7+a)

giúp mk phần a) nha

a) x^2-9x+20

= x^2+4x+5x+20

=(x^2+4x)+(5x+20)

=x(x+4)+5(x+4)

=(x+4)(x+5)

\(=x^2\left(x^2+2x+1\right)+x+1\)

\(=x^2\left(x+1\right)^2+x+1\)

\(=\left(x+1\right)\left[x^2\left(x+1\right)+1\right]\)

\(=\left(x+1\right)\left(x^3+x^2+1\right)\)

\(x^4+2x^3+x^2+x+1\)

\(=x^2\left(x+1\right)^2+\left(x+1\right)\)

\(=\left(x+1\right)\left(x^3+x^2+1\right)\)

4x+5xy-6x+9x²=9x²-2x+5xy=x(9x-2+5y)

hình như đề sai rồi

\(\left(x-5\right)\left(x-1\right)\left(x+3\right)\left(x+7\right)+60\)

\(=\left(x^2+2x-35\right)\left(x^2+2x-3\right)+60\)

\(=\left(x^2+2x\right)^2-38\left(x^2+2x\right)+105+60\)

\(=\left(x^2+2x\right)^2-3\left(x^2+2x\right)-35\left(x^2+2x\right)+165\)

\(=\left(x^2+2x-3\right)\left(x^2+2x-35\right)\)

\(=\left(x+3\right)\left(x-1\right)\left(x+7\right)\left(x-5\right)\)