Sửa đề:

B = 1 - 3 - 5 + 7 + 9 - 11 - 13 + 15 + ... + 2019 - 2021 - 2023 + 2025 + 2027

= (1 - 3 - 5 + 7) + (9 - 11 - 13 + 15) + ... + (2019 - 2021 - 2023 + 2025) + 2027

= 0 + 0 + ... + 0 + 2027

= 2027

Tính P = Chúc bạn học tốt nhé

P=1+1/3+1/6+1/10+…..+1/2021×2022÷2

P/2=1/2+1/6+1/12+1/20+…..+1/2021×2022

P/2=1/1×2+1/2×3+1/3×4+…….+1/2021×2022

P/2=1-1/2+1/2-1/3+1/3-1/4+….+1/2021-1/2022=1-1/2022=2021/2022

P=2021/1011

Chúc bn học tốt

=(1-2)-(3-4)+(5-6)-(7-8)+...+(2021-2022)-2023
=(-1)-(-1)+(-1)-...+(-1)-2023
=0-2023
=-2023

\(=\left(1+3+...+2021\right)\cdot\left[1001\cdot135\cdot137-1001\cdot135\cdot137\right]\)

\(=\left(1+3+...+2021\right)\cdot0\)

=0

= (1 + 3 + ... + 2021) x (135 x 1001 x 137 - 135 x 137 x 1001)

= (1 + 3 + ... + 2021) x 0

= 0

` ( 1+ 3 + 5 + 7 + ... + 2021 ).(135135.137 - 135.137137 )`

` = ( 1+ 3 + 5 + 7 + ... + 2021 ). ( 18513495 - 18513495)`

` = ( 1+ 3 + 5 + 7 + ... + 2021 ). 0`

` = 0`

-13.21-13.80+13

=-13.(21-80+1)

=-13.100

=-1300

-1+2-3+4-5+6-...-2021+2022

=(-1+2)+(-3+4)+...+(-2021+2022)

=1+1+1+...+1 (1011 số hạng)
=1011

-13 . 21 - 13 . 80 + 13

13 ( -21 - 80 + 1 )

13 . ( -100 )

- 1300

\(-13\cdot21-13\cdot80+13=13\left(-21-80+1\right)=13\cdot\left(-100\right)=-1300\)

(1+3+5+7+...+2019+2021)

A=1−3+5−7+......−2019+2021−2023

A=(1−3)+(5−7)+....+(2021−2023)A=(1−3)+(5−7)+....+(2021−2023)

A=−2+(−2)+....+(−2)(506)A=−2+(−2)+....+(−2)(506cặp)

a=−2.506A=−2.506

A=−1012A=−1012

(2+4+6+8+...+2020)

B=2+4+6+8+...+2018+2020
B = 2(1 + 2 + 3 + 4 + ... + 1009 + 1010)
B = 2 . (1011 . 1010 : 2)
B = 2 . 510555
B = 1 021 110

(1+3+5+7+......+2019+2021)-(2+4+6+8+.....+2020)

\(=\dfrac{\left(1+2021\right).\left[\left(2021-1\right):2+1\right]}{2}-\dfrac{\left(2+2020\right).\left[\left(2020-2\right):2+1\right]}{2}\)

\(=1011\)