Bài 1L

a) \(\left(x-7\right)\left(x+3\right)< 0\)

TH1:

\(\hept{\begin{cases}x-7>0\\x+3< 0\end{cases}\Leftrightarrow\hept{\begin{cases}x>7\\x< -3\end{cases}}}\)( loại )

TH2:

\(\hept{\begin{cases}x-7< 0\\x+3>0\end{cases}\Leftrightarrow\hept{\begin{cases}x< 7\\x>-3\end{cases}\Leftrightarrow}-3< x< 7}\)( chọn )

Vậy \(-3< x< 7\)

Bài 2:

a) \(\left(5x+8\right)-\left(2x-15\right)+21=2x-5\)

\(\Leftrightarrow5x+8-2x+15+21=2x-5\)

\(\Leftrightarrow5x-2x-2x=-5-21-8-15\)

\(\Leftrightarrow x=-49\)

Vậy ...

Bài 1:

b) \(\left(2x+6\right)\left(x-5\right)\le0\)

TH1:

\(\hept{\begin{cases}2x+6\le0\\x-5\ge0\end{cases}\Leftrightarrow\hept{\begin{cases}x\le-3\\x\ge5\end{cases}}}\)( loại )

TH2:

\(\hept{\begin{cases}2x+6\ge0\\x-5\le0\end{cases}\Leftrightarrow\hept{\begin{cases}x\ge-3\\x\le5\end{cases}\Leftrightarrow}-3\le x\le5}\)

Vậy \(-3\le x\le5\)

20) -5-(x + 3) = 2 - 5x ⇔ -5 - x - 3 = 2 -5x ⇔ 4x = 10 ⇔ x = \(\frac{5}{2}\)

Vậy...

1) 16 - 8x = 0 ⇔ 8(2 - x) = 0⇔ 2 - x = 0 ⇔ x = 2

Vậy phương trình có nghiệm là x = 2

\(8x-75=5x+21\)

\(8x-5x=75+21\)

\(3x=96\)

\(x=32\)

Vậy \(x=32.\)

\(9x+25=-\left(2x-58\right)\)

\(9x+25=-2x+58\)

\(9x+2x=-25+58\)

\(11x=33\)

\(x=3\)

Vậy \(x=3.\)

\(15-\left|2x-1\right|=-8\)

\(\left|2x-1\right|=23\)

\(\Rightarrow\orbr{\begin{cases}2x-1=23\\2x-1=-23\end{cases}\Rightarrow}\orbr{\begin{cases}2x=24\\2x=-22\end{cases}}\Rightarrow\orbr{\begin{cases}x=12\\x=-11\end{cases}}\)

Vậy \(x\in\left\{12;-11\right\}\)

8x-5x=75+21

3x=96

x=32

9x+25=-2x+58

9x+2x=58-25

11x=33

x=3

Mấy cái này chuyển vế đổi dấu là xong í mà :3

1,

16-8x=0

=>16=8x

=>x=16/8=2

2, 

7x+14=0

=>7x=-14

=>x=-2

3,

5-2x=0

=>5=2x

=>x=5/2

Mk làm 3 cau làm mẫu thôi

Lúc đăng đừng đăng như v :>

chi ra khỏi ngt nản

từ câu 1 đến câu 8 cs thể làm rất dễ,bn tham khảo bài của bn muwaa r làm những câu cn lại

1, 16 - 8x = 0

<=>-8x = 16

<=> x = -2

Vậy_

2, 7x + 14 = 0

<=> 7x = -14

<=> x = -2

3, 5 - 2x = 0

<=> - 2x = -5

<=> x =\(\frac{5}{2}\)

Vậy_

4, 3x - 5 = 7

<=> 3x = 7 + 5

<=> 3x = 12

<=> x = 4

Vậy...

5, 8 - 3x = 6

<=> - 3x = 6 - 8

<=> -3x = - 2

<=> x =\(\frac{2}{3}\)

Vậy......

1) Ta có: \(2x\left(x-3\right)+5\left(x-3\right)=0\)

\(\Leftrightarrow\left(x-3\right)\left(2x+5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{5}{2}\end{matrix}\right.\)

2) Ta có: \(\left(x^2-4\right)-\left(x-2\right)\left(3-2x\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(x+2\right)+\left(x-2\right)\left(2x-3\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(3x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{1}{3}\end{matrix}\right.\)

3) Ta có: \(\left(2x-1\right)^2-\left(2x+5\right)^2=11\)

\(\Leftrightarrow4x^2-4x-1-4x^2-20x-25=11\)

\(\Leftrightarrow-24x=11+1+25=37\)

hay \(x=-\dfrac{37}{24}\)

5) Ta có: \(3x^2-5x-8=0\)

\(\Leftrightarrow3x^2+3x-8x-8=0\)

\(\Leftrightarrow3x\left(x+1\right)-8\left(x+1\right)=0\)

\(\Leftrightarrow\left(x+1\right)\left(3x-8\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=\dfrac{8}{3}\end{matrix}\right.\)

8) Ta có: \(\left|x-5\right|=3\)

\(\Leftrightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)

10) Ta có: \(\left|2x+1\right|=\left|x-1\right|\)

\(\Leftrightarrow\left[{}\begin{matrix}2x+1=x-1\\2x+1=1-x\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x-x=-1-1\\2x+x=1-1\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=0\end{matrix}\right.\)

a, 117 - \(x\) = 28 - (-7)

   117 - \(x\) = 28 + 7

    117 - \(x\) = 35

            \(x\) =  117 - 35

             \(x\) = 82

b, \(x\) - (-38 - 2\(x\)) = (-3) - 8 + 2\(x\) 

    \(x\) + 38 + 2\(x\) = - 11 + 2\(x\)

   3\(x\)  + 38       = - 11 + 2\(x\)

   3\(x\) - 2\(x\)        = - 11 - 38

   \(x\)                = - 49

a) \(\Rightarrow72-20x-36x+84=30x-240-6x-84\)

\(\Rightarrow80x=480\Rightarrow x=6\)

b) \(\Rightarrow15x+25-8x+12=5x+6x+36+1\)

\(\Rightarrow4x=0\Rightarrow x=0\)

c) \(\Rightarrow10x-16-12x+15=12x-16+11\)

\(\Rightarrow14x=4\Rightarrow x=\dfrac{2}{7}\)

a, \(\left|x-3\right|-16=-4\Leftrightarrow\left|x-3\right|=12\)

\(\Leftrightarrow\orbr{\begin{cases}x-3=12\\x-3=-12\end{cases}\Leftrightarrow\orbr{\begin{cases}x=15\\x=-9\end{cases}}}\)

b, \(26-\left|x+9\right|=-13\Leftrightarrow\left|x+9\right|=39\)

\(\Leftrightarrow\orbr{\begin{cases}x+9=39\\x+9=-39\end{cases}\Leftrightarrow\orbr{\begin{cases}x=30\\x=-48\end{cases}}}\)

f, \(9x+25=-\left(2x-58\right)\Leftrightarrow9x+25=-2x+58\)

\(\Leftrightarrow11x-33=0\Leftrightarrow x=3\)

Làm nốt nhé ! 

a. \(\left|x-3\right|-16=-4\)

\(\Rightarrow\left|x-3\right|=12\)

\(\Rightarrow\orbr{\begin{cases}x-3=12\\x-3=-12\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=15\\x=-9\end{cases}}\)

b. \(26-\left|x+9\right|=-13\)

\(\Rightarrow\left|x+9\right|=39\)

\(\Rightarrow\orbr{\begin{cases}x+9=39\\x+9=-39\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=30\\x=-48\end{cases}}\)

c. \(5-\left(10-x\right)=7\)

\(\Rightarrow10-x=-2\)

\(\Rightarrow x=12\)

d. \(11+\left(15-x\right)=1\)

\(\Rightarrow15-x=-10\)

\(\Rightarrow x=25\)

e. \(8x-75=5x+21\)

\(\Rightarrow8x-5x=75+21\)

\(\Rightarrow3x=96\)

\(\Rightarrow x=32\)

f. \(9x+25=-\left(2x-58\right)\)

\(\Rightarrow9x+25=-2x+58\)

\(\Rightarrow9x+2x=58-25\)

\(\Rightarrow11x=33\)

\(\Rightarrow x=3\)

g. \(\left|x+3\right|=4\)

\(\Rightarrow\orbr{\begin{cases}x+3=4\\x+3=-4\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=1\\x=-7\end{cases}}\)

h. \(15-\left|2x-1\right|=\left|-8\right|\)

\(\Rightarrow15-\left|2x-1\right|=8\)

\(\Rightarrow\left|2x-1\right|=7\)

\(\Rightarrow\orbr{\begin{cases}2x-1=7\\2x-1=-7\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=4\\x=-4\end{cases}}\)

a,\(|x-3|-16=-4\)

\(< =>|x-3|=-4+16\)

\(< =>|x-3|=12\)

\(< =>\orbr{\begin{cases}x-3=12\\x-3=-12\end{cases}< =>\orbr{\begin{cases}x=15\\x=-9\end{cases}}}\)

b, \(26-|x+9|=-13\)

\(< =>-|x+9|=-13-26\)

\(< =>|x+9|=39\)

\(< =>\orbr{\begin{cases}x+9=39\\x+9=-39\end{cases}< =>\orbr{\begin{cases}x=30\\x=-48\end{cases}}}\)

c, \(5-\left(10-x\right)=7\)

\(< =>5-10+x=7\)

\(< =>x=7+10-5=12\)

d, \(11+\left(15-x\right)=1\)

\(< =>11+15-x=1\)

\(< =>26-1=25=x\)