\(2364.37+2364.62+2364+100\)

\(=2364.\left(37+62+1\right)+100\)

\(=2364.100+100\)

\(=236400+100\)

\(=236500\)

\(2\cdot\left|-21\right|-3\cdot\left|125\right|-5\cdot\left|-33\right|-\left|2\cdot21\right|\)

\(=2\cdot21-3\cdot125-5\cdot33-2\cdot21\)

\(=-3\cdot125-5\cdot33=-375-165=-540\)

= 2364 x (37 + 62 + 1) + 100

= 2364 x 100 + 100

=236500

236500 nha

Dương Hiểu Minh ơi bạn cộng 1 ở đâu đấy

a) 2 370 - 179 + 21 =  2 191 + 21 =  2 212

b) 100 : 5 . 4  =  20 . 4 = 8           

c) 396 : 18 : 2 = 22 : 2 = 11

a) 2 370 - 179 + 21 =  2 191 + 21 =  2 212

b) 100 : 5 . 4  =  20 . 4 = 80         

c) 396 : 18 : 2 = 22 : 2 = 11

a) 2 370 - 179 + 21 =  2 191 + 21 =  2 212

b) 100 : 5 . 4  =  20 . 4 = 8           

c) 396 : 18 : 2 = 22 : 2 = 11

`A = x/21 + y/21 + z/21.`

`= (x+y+z)/21 = 42/21 = 2`.

Vậy `A =2.`

Sửa đề: A=7/12-9/20+11/30-13/42+15/56

A=1/3+1/4-1/4-1/5+1/5+1/6-1/6-1/7+1/7+1/8

=1/3+1/8=11/24

\(A=\frac{1}{30}+\frac{1}{42}+....+\frac{1}{110}+\frac{1}{132}\)

\(A=\frac{1}{5.6}+\frac{1}{6.7}+....+\frac{1}{10.11}+\frac{1}{11.12}\)

\(A=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+....+\frac{1}{11}-\frac{1}{12}\)

\(A=\frac{1}{5}-\frac{1}{12}=\frac{7}{60}\)

Hình như bn ghi sai đề mk sửa cho

Ta có:\(A=\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{100}+\frac{1}{132}\)

\(\Leftrightarrow A=\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}+\frac{1}{10.11}+\frac{1}{11.12}\)

\(\Leftrightarrow A=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+....+\frac{1}{11}-\frac{1}{12}\)

\(\Leftrightarrow A=\frac{1}{5}-\frac{1}{12}\)

\(\Leftrightarrow A=\frac{7}{60}\)

\(a,ĐK:x\ne-1;x\ne-2\\ b,A=\dfrac{\left(x-1\right)\left(x+1\right)}{\left(x+1\right)\left(x+2\right)}=\dfrac{x-1}{x+2}\\ x=2020\Leftrightarrow A=\dfrac{2019}{2022}=\dfrac{673}{674}\\ c,A=0\Leftrightarrow x-1=0\Leftrightarrow x=1\left(tm\right)\)