A=\(\frac{3\sqrt{x}-6}{x-2\sqrt{x}}\) + \(\frac{\sqrt{x}-3}{\sqrt{x}}\) -\(\frac{1}{2-\sqrt{x}}\) (x>0, x≠4)
B=\(\frac{\sqrt{x}-2}{\sqrt{x}+9}\)
a) Tính B khi 2x=\(\frac{1}{\sqrt{2}-1}\)-\(\frac{1}{\sqrt{2}+1}\)
b)Rút gọn P=A.B
c)Tìm x nguyên để \(\sqrt{P}\)<\(\frac{1}{3}\)