\(\frac{31}{53}.\frac{17}{28}+\frac{31}{28}.\frac{11}{53}\)

=\(\frac{31}{28}.\frac{17}{53}+\frac{31}{28}.\frac{11}{53}\)

=\(\frac{31}{28}.\left(\frac{17}{53}+\frac{11}{53}\right)\)

=\(\frac{31}{28}.\frac{28}{53}\)

=\(\frac{31}{53}\)

Bài 1: Ta chỉ cần bỏ ngoặc rồi cộng hai phân số để ra kết quả là số tự nhiên là xong

Bài 2:

A = \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+............+\frac{1}{2003.2004}\)

A = \(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-.............-\frac{1}{2003}+\frac{1}{2003}-\frac{1}{2004}\)

A = \(1-\frac{1}{2004}\)

A = \(\frac{2004}{2004}-\frac{1}{2004}=\frac{2003}{2004}\)

Mk làm mẫu 1 bài nha 

Bài 1 :

a, = (1/4+3/4) - (5/13+8/13)+2/11

    = 1 - 1 + 2/11

    = 2/11

Tk mk nha

\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2003.2004}\)

\(\Leftrightarrow A=1\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2003}-\frac{1}{2004}\right)\)

\(\Leftrightarrow A=1\left(1-\frac{1}{2004}\right)\)

\(\Leftrightarrow A=\frac{2003}{2004}\)

a) \(\dfrac{25}{37}\times\dfrac{18}{29}+\dfrac{18}{29}\times\dfrac{12}{37}\)

\(=\dfrac{18}{29}\times\left(\dfrac{25}{37}+\dfrac{12}{37}\right)\)

\(=\dfrac{18}{29}\times\dfrac{37}{37}\)

\(=\dfrac{18}{29}\times1\)

\(=\dfrac{18}{29}\)

b) \(\dfrac{31}{85}\times\dfrac{11}{19}+\dfrac{31}{85}\times\dfrac{12}{19}-\dfrac{42}{19}\times\dfrac{31}{85}\)

\(=\dfrac{31}{85}\times\left(\dfrac{11}{19}+\dfrac{12}{19}-\dfrac{42}{19}\right)\)

\(=\dfrac{31}{85}\times\dfrac{-19}{19}\)

\(=\dfrac{31}{85}\times-1\)

\(=-\dfrac{31}{85}\)

c) \(\dfrac{16}{53}:\dfrac{17}{9}-\dfrac{16}{53}:\dfrac{17}{8}\)

\(=\dfrac{16}{53}:\left(\dfrac{9}{17}-\dfrac{8}{17}\right)\)

\(=\dfrac{16}{53}:\dfrac{1}{17}\)

\(=\dfrac{16}{901}\)

c) \(\dfrac{1}{5}\times\dfrac{12}{31}\times\dfrac{4}{3}+\dfrac{19}{31}\times\dfrac{4}{15}\)

\(=\dfrac{4}{15}\times\dfrac{12}{31}+\dfrac{19}{31}\times\dfrac{4}{15}\)

\(=\dfrac{4}{15}\times\left(\dfrac{12}{31}+\dfrac{19}{31}\right)\)

\(=\dfrac{4}{15}\times\dfrac{31}{31}\)

\(=\dfrac{4}{15}\times1\)

\(=\dfrac{4}{15}\)

a: =18/29*(25/37+12/37)

=18/29

b: =31/85(11/19+12/19-42/19)

=-31/85

c; =16/53(9/17+8/17)=16/53

d: =4/15(12/31+19/31)=4/15

1,35326087

-2/3

0

-6/29/44

-9

nha bạn

a ) 17 x 4 = ( 15 + 2 ) x 4 = 15 x 4 + 2 x 4 = 60 + 8 = 68

      25 x 28 = 25 x ( 20 + 8 ) = 25 x 20 + 25 x 8 = 500 + 200 = 700

b ) 13 x 12 = 13 x ( 10 + 2 ) = 13 x 10 + 13 x 2 = 130 + 26 = 156

      53 x 11 = 53 x ( 10 + 1 ) = 53 x 10 + 53 x 1 = 530 + 53 = 583

      39 x 101 = 39 x ( 100 + 1 ) = 39 x 100 + 39 x 1 = 3900 + 39 = 3939

a) Ta có:

\(17\times4=\left(15+2\right)\times4=15\times4+2\times4=60+8=68\)

\(25\times28=25\times\left(20+8\right)=25\times20+25\times8=500+200=700\)

b) Ta có:

\(13\times12=13\times\left(10+2\right)=13\times10+13\times2=130+26=156\)

\(53\times11=53\times\left(10+1\right)=53\times10+53\times1=530+53=583\)

\(39\times101=39\times\left(100+1\right)=39\times100+39\times1=3900+39=3939\)

25 x 28

= 25 x 4 x 7

= (25 x 4) x 7

= 100 x 7

= 700

bn l-ike cho mk trước đã

Ta có : A=20/11×13 + 20/13×15 +20/15×17+...+20/53×55

A = 10 ×( 2/11×13+2/13×15+...12/53×55)

A = 10 ×(1/11-1/13+1/13-1/15+1/15-1/17+...+1/53-1/55)

A = 10 × (1/11-1/55)

A =10 × 4/55

A = 8/11

a, 53 * 39 + 47 * 59 - 53 * 21 - 47 * 21     c, (4³ * 5^{2 -} 4³ ) : ( 4 * 4² ) 

= ( 53 + 47 ) *  39 - ( 53 + 47 ) * 21             = ( 64 * 25 - 64 ) : ( 4 * 16 )

= 100 * 39 - 100 * 21                                    = ( 1600 - 64 ) :  64

= ( 39 - 21 ) * 100                                         = 1536 : 64

= 18 * 100                                                     = 24

= 1800

Tính hợp lí:

a) 53 x 39 + 47 x 39 - 53 x 21 - 47 x 21.

b) 5 x 7 x 77- 7 x 60 + 49 x 25 - 15 x 42

c) ( 43 x 52 - 43 ) : ( 4 x 42 )

d) ( 2 + 5 + 11 +...+ 47 + 65

đ) ( 45 x 16 - 17 ) : ( 28 + 45 x 15 )

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