a) \(24\times y+76\times y=100\)
\(\Rightarrow\left(24+76\right)\times y=100\)
\(\Rightarrow100\times y=100\)
\(\Rightarrow y=100:100\)
\(\Rightarrow y=1\)
b) \(125\times y-100\times y=1000\)
\(\Rightarrow\left(125-100\right)\times y=1000\)
\(\Rightarrow25\times y=1000\)
\(\Rightarrow y=1000:25\)
\(\Rightarrow y=40\)

a)\(=>y=1000:\left(24+76\right)=1000:100=10\)

b(\(=>y=1000:\left(125-100\right)=1000:25=40\)

\(\frac{2}{3}x\times125=1000\)

\(\frac{2}{3}x\)            \(=1000\div125\)

\(\frac{2}{3}x\)            \(=8\)

     \(x\)            \(=8\div\frac{2}{3}\)

     \(x\)            \(=8\times\frac{3}{2}\)

     \(x\)            \(=12\)

Bài làm

\(\frac{2}{3}x\times125=1000\)

\(\frac{2}{3}x=\frac{1000}{125}\)

\(\frac{2}{3}x=8\)

\(x=8:\frac{2}{3}\)

\(x=8X\frac{3}{2}\)

\(x=\frac{24}{2}\)

\(x=12\)

Vậy x = 12

2/3x=1000:125

2/3x=8

x=8:2/3

x=8X3/2

x=12

=>5^x=25

=>x=2

`125/5^x=5`

`-> 125/5^x=5/1`

`-> 5*5^x=125`

`->`\(5^{1+x}=125\)

`->`\(5^{1+x}=5^3\)

`->`\(x+1=3\)

`-> x=3-1`

`-> x=2`

Vậy, `5^x=5^2`.

a) 125 x 6 = ...6... × 125

b) 34 × (4 + 5) = 9 × ..34..

c) 18 x 1000=18000

d) 9000 : 100=90

a) 125 x 6 = ...6.. × 125

b) 34 × (4 + 5) = 9 × ..34..

c) 18 x 1000= 18000

d) 9000 : 100= 90

a) 6

b) 34

c) 18 000

d) 90

Có : \(\dfrac{x}{5}=\dfrac{125}{x}\)

\(\Leftrightarrow x^2=5.125\)

\(\Leftrightarrow x=\pm25\)

Có : \(\dfrac{x}{5}=\dfrac{125}{x}\)

\(\Leftrightarrow x^2=5.125\)

\(\Leftrightarrow x=\pm25\)

=>5x-19+3x+24=125

=>8x+5=125

hay x=15

( 5 x − 19 ) + ( 3 x + 24 ) = 125

. 5 x − 19 + 3 x + 24 = 125

8 x + 5 = 125

8 x = 120

x = 15

\(\left(5x-19\right)+\left(3x+24\right)=125\)

.\(5x-19+3x+24=125\)

\(8x+5=125\)

\(8x=120\)

\(x=15\)

ta có x *8 =125+19-24

        x*8=120

        x=120\8

       x=15