`125/5^x=5`
`-> 125/5^x=5/1`
`-> 5*5^x=125`
`->`\(5^{1+x}=125\)
`->`\(5^{1+x}=5^3\)
`->`\(x+1=3\)
`-> x=3-1`
`-> x=2`
Vậy, `5^x=5^2`.
1/ (\(\left(-\dfrac{2}{3}\right)\)\(^2\) x \(\dfrac{-9}{8}\) - 25% x \(\dfrac{-16}{5}\)
2/ -1\(\dfrac{2}{5}\) x 75% + \(\dfrac{-7}{5}\) x 25%
3/ -2\(\dfrac{3}{7}\) x (-125%) + \(\dfrac{-17}{7}\) x 25%
4/ (-2)\(^3\) x (\(\dfrac{3}{4}\) x 0.25) : (2\(\dfrac{1}{4}\) - 1\(\dfrac{1}{6}\))
Tìm số tự nhiên x biết rằng
2x.4=128
x15=x
(2x+1)3=125
(x-5)4=(x-5)6
Tìm x, biết:
a) \(\dfrac{-2}{5}\) + \(\dfrac{4}{5}\) . x = \(\dfrac{3}{5}\)
b) \(\dfrac{-3}{7}\) - \(\dfrac{4}{7}\) : x = \(\dfrac{2}{5}\)
c) \(\dfrac{4}{7}\) . x + \(\dfrac{2}{3}\) = \(\dfrac{-1}{5}\)
d) \(\dfrac{5}{7}\) : x -1 = \(\dfrac{2}{3}\)
Tìm x biết :
\(x+\dfrac{1}{2}=\dfrac{33}{4}\)
\(\dfrac{5}{6}-x=\dfrac{1}{3}\)
\(x+\dfrac{4}{5}=\dfrac{-2}{3}\)
Tìm x biết:\(\dfrac{4}{5}-\dfrac{3}{5}:x=\dfrac{1}{2}\)
TÌm số nguyên x biết ( có các bước giải )
a \(\dfrac{x}{2}\) = \(\dfrac{2}{x}\) ; b \(\dfrac{x}{-5}\) = \(\dfrac{-5}{x}\)
Tìm x, biết:
a) \(-\dfrac{3}{5}\) - x = -0,75
b) \(1\dfrac{4}{5}\) = -0,15 - x
c) \(2\dfrac{1}{2}\) - x +\(\dfrac{4}{5}\) = \(\dfrac{2}{3}\) - ( \(-\dfrac{4}{7}\))
Tìm x biết:
|5.x+125|.x=300
Tìm x biết 5x-2=125
