c)\(\left(2x+\frac{3}{5}\right)^2-\frac{9}{25}=0\)

\(\Rightarrow\left(2x+\frac{3}{5}\right)^2=\frac{9}{25}\)

\(\Rightarrow2x+\frac{3}{5}=\pm\frac{3}{5}\)

\(\Rightarrow2x=0\Rightarrow x=0\)

\(\Rightarrow2x=-\frac{6}{5}\Rightarrow x=-\frac{3}{5}\)

a)x=10

b)x=61/114

c)x=0

d)sai cái gì đó

Đáp án là gì nhưng lời giải ???????

a. chia làm hai trường hợp

3x-1 = 0

-1/2x + 5 = 0

suy ra : 3x = 1

-1/2x = -5

x= 1/3

x= 10

câu1

(3x-1).(1/2x5)=0

=>3x-1=0               hoặc  1/2x5=0

=>x=1/3                            =>x=0

câu2

1/4+1/3 :(2x-1)=5

=> 1/3:(2x-1)=19/4

=>2x-1       =57/4

=>2x=61/4

=>x=61/8

còn hai câu sau bn ghi đề mik ko hỉu

1.

a)(3x-1)(1/2x5)=0

=>3x-1=0 hoặc 1/2x5=0

3x=0+1               x=0:1/2:5

x=1/3                  x=0

Vậy x=1/3 hoặc x=0

b)1/4+1/3:(2x-1)=5

1/3:(2x-1)=5-1/4=20/4-1/4=19/4

2x-1=1/3:19/4=1/3*4/19=4/57

2x=4/57+1=4/57+57/57=61/57

x=61/57:2=61/57*1/2=61/114

Vậy x=61/114

c)(2x+2/5)^2-9/25=0=0^2-9/25

=>2x+2/5=0

2x=0-2/5

x=-2/5:2=-2/5*1/2

x=-1/5

Vậy x=-1/5

d)(3x-1/2)^3+1/9=0=0^3+1/9

=>3x-1/2=0

3x=0+1/2

x=1/2:3=1/2*1/3

x=1/6

Vậy x=1/6

Làm nhiêu đó chết người đó bạn , đề nhiều số nữa

Bài 2: 

a: \(\Leftrightarrow\left(x-5\right)\left(x+5\right)-\left(x+5\right)=0\)

=>(x+5)(x-6)=0

=>x=-5 hoặc x=6

b: \(\Leftrightarrow4x^2-4x+1-4x^2+1=0\)

=>-4x+2=0

hay x=1/2

c: \(\Leftrightarrow\left(x^2+4\right)\left(x^2-1\right)=0\)

=>x=1 hoặc x=-1

a. x mũ 2 - 2x + 1 = 25 

= x^2 + 2.x.1 + 1^2

= ( x + 1 ) ^2

ko bt có đúng ko nữa, mấy câu kia tui ko bt lm

Sos

hahaha

(2x-3/5)^2-9/25=0

(2x-3/5)^2=9/25

2x-3,5=3/5

2x=3/5+3/5

x=6/5:2=3/5

\(\left(9^{30}-27^{19}\right):3^{57}+\left(125^9-25^{12}\right):5^{24}\)

\(=\left(3^{60}-3^{57}\right):3^{57}+\left(5^{27}-5^{24}\right):5^{24}\)

\(=3^{57}\left(3^3-1\right):3^{57}+5^{24}\left(5^3-1\right):5^{24}\)

\(=3^3-1+5^3-1\)

\(=27-1+125-1\)

\(=150\)

2 )

\(x^2-25-\left(x+5\right)=0\)

\(\Leftrightarrow\left(x+5\right)\left(x-5\right)-\left(x+5\right)=0\)

\(\Leftrightarrow\left(x+5\right)\left(x-5-1\right)=0\)

\(\Leftrightarrow\left(x+5\right)\left(x-6\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x+5=0\\x-6=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-5\\x=6\end{matrix}\right.\)

Vậy ...

b )

\(\left(2x-1\right)^2-\left(4x^2-1\right)=0\)

\(\Leftrightarrow4x^2-4x+1-4x^2+1=0\)

\(\Leftrightarrow2-4x=0\)

\(\Leftrightarrow4x=2\)

\(\Leftrightarrow x=\dfrac{1}{2}\)

Vậy ...

c )

\(x^2\left(x^2+4\right)-x^2-4=0\)

\(\Leftrightarrow x^2\left(x^2+4\right)-\left(4+x^2\right)=0\)

\(\Leftrightarrow\left(x^2-1\right)\left(x^2+4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x^2-1=0\\x^2+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x^2=1\\x^2=-4\left(L\right)\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-1\end{matrix}\right.\)

Vậy ...

b, x = -5/3 hoặc x = 4/3.

c, x = 0 hoặc x = 3, -3.

d, x = 0 hoặc x = 2, -2.

e, x = 1 hoặc x = \(\dfrac{-1}{2}\).

a: \(\Leftrightarrow x^2-40x+400-x^2-4x-3=-7\)

=>-44x+397=-7

=>-44x=-404

hay x=101

b: \(\Leftrightarrow\left[{}\begin{matrix}3x+5=0\\4-3x=0\end{matrix}\right.\Leftrightarrow x\in\left\{-\dfrac{5}{3};\dfrac{4}{3}\right\}\)

c: \(\Leftrightarrow x\left(x^2-9\right)=0\)

=>x(x-3)(x+3)=0

hay \(x\in\left\{0;3;-3\right\}\)

d: \(\Leftrightarrow x\left(x-2\right)\left(x+2\right)=0\)

hay \(x\in\left\{0;2;-2\right\}\)

e: =>(2x+1)(1-x)=0

=>x=-1/2 hoặc x=1