( 2x + 3/5 )2 - 9/25 = 0
( 2x + 3/5 )2 = 0 + 9/25
( 2x + 3/5 )2 = 9/25
( 2x + 3/5 )2 = ( 3/5 )2
=> 2x + 3/5 = 3/5
=> 2x = 3/5 - 3/5
=> 2x = 0
=> x = 0 : 2
=> x = 0
\(\left(2x+\frac{3}{5}\right)^2-\frac{9}{25}=0\)
\(\left(2x+\frac{3}{5}\right)^2=\frac{9}{25}\)
\(\left(2x+\frac{3}{5}\right)^2=\left(\pm\frac{3}{5}\right)^2\)
\(2x+\frac{3}{5}=\pm\frac{3}{5}\)
TH1: TH2:
\(2x+\frac{3}{5}=\frac{3}{5}\) \(2x+\frac{3}{5}=-\frac{3}{5}\)
\(2x=\frac{3}{5}-\frac{3}{5}\) \(2x=-\frac{3}{5}-\frac{3}{5}\)
\(2x=0\) \(2x=-\frac{6}{5}\)
\(x=0:2\) \(x=-\frac{6}{5}:2\)
\(x=2\) \(x=-\frac{3}{5}\)
