Ex1 ko có verb à

Ex2

1 like

2 listen

3 wears

4 teaches

5 do

6 goes

7 comes

8 goes

9 watch

10 walks

11 is

12 washes

13 studies

14 wants

15 plays

16 buys

17 studies

18 tries

19 washes

20 cries

21 says

22 flies

23 don't have

1 is

2 are

3 is

4 am

5 are

6 is

7 is

8 are

8 are

10 is

11 are

12 is

13 am

14 are

15 are

Bài 4: 

a: Xét ΔABD và ΔHBD có 

BA=BH

\(\widehat{ABD}=\widehat{HBD}\)

BD chung

Do đó: ΔABD=ΔHBD

a) \(x-\dfrac{3}{4}=-\dfrac{5}{8}\Rightarrow x=-\dfrac{5}{8}+\dfrac{3}{4}\Rightarrow x=\dfrac{1}{8}\)

b) \(x+\dfrac{5}{8}=-\dfrac{1}{4}\Rightarrow x=-\dfrac{1}{4}-\dfrac{5}{8}\Rightarrow x=-\dfrac{7}{8}\)

c) \(\dfrac{5}{6}+\dfrac{3}{4}x=\dfrac{5}{24}\Rightarrow x=\left(\dfrac{5}{24}-\dfrac{5}{6}\right):\dfrac{3}{4}\Rightarrow x=-\dfrac{5}{6}\)

d) \(\dfrac{3}{8}-\dfrac{2}{3}:x=-\dfrac{5}{12}\Rightarrow\dfrac{2}{3}:x=\dfrac{3}{8}+\dfrac{5}{12}\Rightarrow\dfrac{2}{3}:x=\dfrac{19}{24}\Rightarrow x=\dfrac{2}{3}:\dfrac{19}{24}=\dfrac{16}{19}\)

a) \(x-\dfrac{3}{4}=-\dfrac{5}{8}\\ \Rightarrow x=\dfrac{1}{8}\)

b) \(x+\dfrac{5}{8}=-\dfrac{1}{4}\\ \Rightarrow x=-\dfrac{7}{8}\)

c) \(\dfrac{5}{6}+\dfrac{3}{4}x=\dfrac{5}{24}\\ \Rightarrow\dfrac{3}{4}x=-\dfrac{5}{8}\\ \Rightarrow x=-\dfrac{5}{6}\)

d) \(\dfrac{3}{8}-\dfrac{2}{3}:x=-\dfrac{5}{12}\\ \Rightarrow\dfrac{2}{3}:x=\dfrac{19}{24}\\ \Rightarrow x=\dfrac{16}{19}\)

e) \(\left(6,5-2x\right):\dfrac{5}{13}=\dfrac{13}{10}\\ \Rightarrow6,5-2x=\dfrac{1}{2}\\ \Rightarrow2x=6\\ \Rightarrow x=3\)

f) \(\left|\dfrac{1}{3}x+\dfrac{1}{2}\right|-\dfrac{3}{4}=-\dfrac{1}{6}\\ \Rightarrow\left|\dfrac{1}{3}x+\dfrac{1}{2}\right|=\dfrac{7}{12}\\ \Rightarrow\left[{}\begin{matrix}\dfrac{1}{3}x+\dfrac{1}{2}=\dfrac{7}{12}\\\dfrac{1}{3}x+\dfrac{1}{2}=-\dfrac{7}{12}\end{matrix}\right.\)

   \(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=-\dfrac{13}{4}\end{matrix}\right.\)

g) \(\dfrac{x-3}{3}=\dfrac{2x+3}{5}\\ \Rightarrow5x-15=6x+9\\ \Rightarrow-x=24\\ \Rightarrow x=-24\)

h) \(\dfrac{x-5}{6}=\dfrac{6}{x-5}\\ \Rightarrow\left(x-5\right)^2=6^2\\ \Rightarrow\left[{}\begin{matrix}x-5=-6\\x-5=6\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-1\\x=11\end{matrix}\right.\)

Bài 2:

a) \(x-\dfrac{3}{4}=-\dfrac{5}{8}\)

    \(x=-\dfrac{5}{8}-\dfrac{3}{4}\)

    \(x=-\dfrac{11}{8}\)

b) \(x+\dfrac{5}{8}=\dfrac{-1}{4}\)

     \(x=\dfrac{-1}{4}-\dfrac{5}{8}\)

     \(x=\dfrac{-7}{8}\)

Bài 1:
b) \(B=A.\dfrac{-10}{x-4}=\dfrac{x-4}{x+5}.\dfrac{-10}{x-4}=\dfrac{-10}{x+5}\)

Để B nguyên <=> x+5 nguyên mà \(x\in Z\Rightarrow x+5\inƯ\left(-10\right)=\left\{\pm1;\pm2;\pm5;\pm10\right\}\)

\(\Leftrightarrow x\in\left\{-6;-4;-3;-7;0;-10;-15;5\right\}\) kết hợp với điều kiện của x

\(\Rightarrow x\in\left\{-15;-10;-6;-7;-3;0;5\right\}\)

Bài 5:

Có \(\left|x-2018\right|+\left|2x-2019\right|+\left|3x-2020\right|\ge0\) \(\forall\)x

\(\Rightarrow x-2021\ge0\) \(\Leftrightarrow x\ge2021\)

\(\Rightarrow x-2018>0,2x-2019>0,3x-2020>0\)

PT \(\Leftrightarrow x-2018+2x-2019+3x-2020=x-2021\)

\(\Leftrightarrow5x=4036\) \(\Leftrightarrow x=\dfrac{4036}{5}< 2021\) (L)

Vậy pt vô nghiệm

...

?

12,12 x 7,5 + 12,12 : 2 + 12,12 + 12,12

= 12,12 x 7,5 + 12,12 x 0,5 + 12,12 x 1 + 12,12 x 1

= 12,12 x (7,5 + 0,5 + 1 + 1)

= 12,12 x 10

= 121,2

121,2 nha bạn

File: undefined 

giúp mình với

4: Ta có: x+2x+...+18x=1368

\(\Leftrightarrow153x=1368\)

hay \(x=\dfrac{152}{17}\)