a) \(x-\dfrac{3}{4}=-\dfrac{5}{8}\Rightarrow x=-\dfrac{5}{8}+\dfrac{3}{4}\Rightarrow x=\dfrac{1}{8}\)
b) \(x+\dfrac{5}{8}=-\dfrac{1}{4}\Rightarrow x=-\dfrac{1}{4}-\dfrac{5}{8}\Rightarrow x=-\dfrac{7}{8}\)
c) \(\dfrac{5}{6}+\dfrac{3}{4}x=\dfrac{5}{24}\Rightarrow x=\left(\dfrac{5}{24}-\dfrac{5}{6}\right):\dfrac{3}{4}\Rightarrow x=-\dfrac{5}{6}\)
d) \(\dfrac{3}{8}-\dfrac{2}{3}:x=-\dfrac{5}{12}\Rightarrow\dfrac{2}{3}:x=\dfrac{3}{8}+\dfrac{5}{12}\Rightarrow\dfrac{2}{3}:x=\dfrac{19}{24}\Rightarrow x=\dfrac{2}{3}:\dfrac{19}{24}=\dfrac{16}{19}\)
a) \(x-\dfrac{3}{4}=-\dfrac{5}{8}\\ \Rightarrow x=\dfrac{1}{8}\)
b) \(x+\dfrac{5}{8}=-\dfrac{1}{4}\\ \Rightarrow x=-\dfrac{7}{8}\)
c) \(\dfrac{5}{6}+\dfrac{3}{4}x=\dfrac{5}{24}\\ \Rightarrow\dfrac{3}{4}x=-\dfrac{5}{8}\\ \Rightarrow x=-\dfrac{5}{6}\)
d) \(\dfrac{3}{8}-\dfrac{2}{3}:x=-\dfrac{5}{12}\\ \Rightarrow\dfrac{2}{3}:x=\dfrac{19}{24}\\ \Rightarrow x=\dfrac{16}{19}\)
e) \(\left(6,5-2x\right):\dfrac{5}{13}=\dfrac{13}{10}\\ \Rightarrow6,5-2x=\dfrac{1}{2}\\ \Rightarrow2x=6\\ \Rightarrow x=3\)
f) \(\left|\dfrac{1}{3}x+\dfrac{1}{2}\right|-\dfrac{3}{4}=-\dfrac{1}{6}\\ \Rightarrow\left|\dfrac{1}{3}x+\dfrac{1}{2}\right|=\dfrac{7}{12}\\ \Rightarrow\left[{}\begin{matrix}\dfrac{1}{3}x+\dfrac{1}{2}=\dfrac{7}{12}\\\dfrac{1}{3}x+\dfrac{1}{2}=-\dfrac{7}{12}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=-\dfrac{13}{4}\end{matrix}\right.\)
g) \(\dfrac{x-3}{3}=\dfrac{2x+3}{5}\\ \Rightarrow5x-15=6x+9\\ \Rightarrow-x=24\\ \Rightarrow x=-24\)
h) \(\dfrac{x-5}{6}=\dfrac{6}{x-5}\\ \Rightarrow\left(x-5\right)^2=6^2\\ \Rightarrow\left[{}\begin{matrix}x-5=-6\\x-5=6\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-1\\x=11\end{matrix}\right.\)
Bài 2:
a) \(x-\dfrac{3}{4}=-\dfrac{5}{8}\)
\(x=-\dfrac{5}{8}-\dfrac{3}{4}\)
\(x=-\dfrac{11}{8}\)
b) \(x+\dfrac{5}{8}=\dfrac{-1}{4}\)
\(x=\dfrac{-1}{4}-\dfrac{5}{8}\)
\(x=\dfrac{-7}{8}\)
e) \(\left(6,5-2x\right):\dfrac{5}{13}=\dfrac{13}{10}\Rightarrow6,5-2x=\dfrac{13}{10}.\dfrac{5}{13}=\dfrac{1}{2}\Rightarrow2x=6,5-\dfrac{1}{2}=6\Rightarrow x=3\)f) \(\left|\dfrac{1}{3}x+\dfrac{1}{2}\right|-\dfrac{3}{4}=-\dfrac{1}{6}\Rightarrow\left|\dfrac{1}{3}x+\dfrac{1}{2}\right|=-\dfrac{1}{6}+\dfrac{3}{4}\Rightarrow\left|\dfrac{1}{3}x+\dfrac{1}{2}\right|=\dfrac{7}{12}\)
\(\Rightarrow\left[{}\begin{matrix}\dfrac{1}{3}x+\dfrac{1}{2}=\dfrac{7}{12}\\\dfrac{1}{3}x+\dfrac{1}{2}=-\dfrac{7}{12}\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=-\dfrac{13}{4}\end{matrix}\right.\)
g) \(\dfrac{x-3}{3}=\dfrac{2x+3}{5}\Rightarrow5x-15=6x+9\Rightarrow x=-24\)
h) \(\dfrac{x-5}{6}=\dfrac{6}{x-5}\Rightarrow\left(x-5\right)^2=36\)
\(\Rightarrow\left[{}\begin{matrix}x-5=6\\x-5=-6\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=11\\x=-1\end{matrix}\right.\)
c) \(\dfrac{5}{6}+\dfrac{3}{4}.x=\dfrac{5}{24}\)
\(\dfrac{3}{4}.x=\dfrac{5}{24}-\dfrac{5}{6}\)
\(\dfrac{3}{4}.x=\dfrac{-5}{8}\)
\(x=\dfrac{-5}{8}:\dfrac{3}{4}\)
\(x=\dfrac{-5}{6}\)
a: Ta có: \(x-\dfrac{3}{4}=-\dfrac{5}{8}\)
nên \(x=\dfrac{1}{8}\)
b: Ta có: \(x+\dfrac{5}{8}=-\dfrac{1}{4}\)
nên \(x=-\dfrac{7}{8}\)
