ai giải dc cho 20 SP

là -10645 nha

10645 nha chúc bạn học tốt

=10645

a) Ta có 

43x=39.43-37.43

43x=43.(39-37)

43x=43x2

=>x=2

b) ta có

3x-136=2^3.3^2+2^2.5

3x-136=8.9+4.5

3x-136=72+20

3x-136=92

3x=228

x=76

a)  43x = 39.43 - 37.43

=> 43x = 43 . (39 - 37)

=> 43x = 43 . 2

=>     x = 43 : 43 . 2

=>     x = 1 . 2

  Vậy x = 2

b)  3x - 136 = 2³ . 3² + 2² . 5

=> 3x - 136 = 8 . 9 + 4 . 5

=> 3x - 136 = 72 + 20

=> 3x - 136 = 92

=> 3x          = 92 + 136

=> 3x          = 228

=>   x          = 228 : 3

Vậy x          = 76

= \(\dfrac{1}{3}\times\left(164+136+300\right)\)
= \(\dfrac{1}{3}\times600\)
= 200

a) 1 267 + 99 + 501 = 1 267 + (99 + 501)

                                = 1 267 + 600 = 1 867

     25 x 14 x 4 = (25 x 4) x 14

                       = 100 x 14 = 1 400

b) 3 905 x (50 – 1) = 3 905 x 50 – 3 905 x 1

                             = 195 250 – 3 905 = 191 345

     270 : ( 27 x 2 ) = 270 : 27 : 2

                             = 10 : 2 = 5

c) 115 x 58 + 115 x 42 = 115 x (58 + 42)

                                   = 115 x 100 = 11 500

136 x 67 – 136 x 66 = 136 x (67 – 66)

                              = 136 x 1 = 136

a) ( x - 2018 ) . 3 = 0

=> x - 2018 = 0

=> x = 2018

b) 2018 . ( 3x - 18 ) = 0

=> 3x - 18 = 0

=> 3x = 18

=> x = 6

c) 25 + ( 15 + x ) = 75

40 + x = 75

x = 35

d) 136 - 2 ( 164 - x ) = 30

2 ( 164 - x ) = 106

164 - x = 53

x = 111

e) 30 - ( 14 + 2x ) = 8

14 + 2x = 22

2x = 8

x = 4

f) 56 : ( 3x - 1 ) = 7

3x - 1 = 8

3x = 9

x = 3

\(a.\left(x-2018\right).3=0\)

\(x-2018=0\)

\(x=2018\)

~ mấy câu sau cx giống vậy nhé bạn ~

nếu bạn thấy câu nào khó thì nt cho mik nhe 

a) ( x - 2018 ) . 3 = 0

( x - 2018 ) = 0

x = 0 + 2018 

x= 2018

b) 2018( 3x - 18 ) = 0

3x - 18 = 0

3x = 18

x = 18 : 3 

x = 6

c) 25 + ( 15+x ) = 75

15 + x = 50

x = 50 - 15

x = 35

d) 136 - 2( 164 - x ) = 30

2( 164 - x ) = 106

164 - x = 53

x = 111

e) 30 - ( 14 + 2x ) = 8

14 + 2x = 22

2x = 8

x = 4

f) 56 : ( 3x - 1 ) = 7

3x - 1 = 8

3x = 9

x = 3

(x-35)-120=0

=>x-35    = 0+120

=>x-35=120

=>x=120+35

=>x=155

tíc mình nha

Bài 1: 

1) Ta có: \(\left(-12\right)+6\cdot\left(-3\right)\)

\(=-12-18\)

=-30

2) Ta có: \(\left(36-2020\right)+\left(2019-136\right)-27\)

\(=36-2020+2019-136-27\)

\(=1-100-27\)

\(=-126\)

3) Ta có: \(\left(144-97\right)-\left(244-197\right)\)

\(=144-97-244+197\)

\(=-100+100=0\)

4) Ta có: \(\left(-24\right)\cdot13-24\cdot\left(-3\right)\)

\(=-24\cdot13+24\cdot3\)

\(=24\cdot\left(-13+3\right)\)

\(=24\cdot\left(-10\right)=-240\)

5) Ta có: \(54+55+56+57+58-\left(64+65+66+67+68\right)\)

\(=54+55+56+57+58-64-65-66-67-68\)

\(=\left(54-64\right)+\left(55-65\right)+\left(56-66\right)+\left(57-67\right)+\left(58-68\right)\)

\(=\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)\)

=-50

6) Ta có: \(24\cdot\left(16-5\right)-16\cdot\left(24-5\right)\)

\(=24\cdot16-24\cdot5-16\cdot24+16\cdot5\)

\(=-24\cdot5+16\cdot5\)

\(=5\cdot\left(-24+16\right)\)

\(=-5\cdot8=-40\)

7) Ta có: \(47\cdot\left(23+50\right)-23\cdot\left(47+50\right)\)

\(=47\cdot23+47\cdot50-23\cdot47-23\cdot50\)

\(=47\cdot50-23\cdot50\)

\(=50\cdot\left(47-23\right)\)

\(=50\cdot24=1200\)

8) Ta có: \(\left(-31\right)\cdot47+\left(-31\right)\cdot52+\left(-31\right)\)

\(=-31\cdot\left(47+52+1\right)\)

\(=-31\cdot100=-3100\)

Bài 2: 

1) Ta có: \(-17-\left(2x-5\right)=-6\)

\(\Leftrightarrow-17-2x+5+6=0\)

\(\Leftrightarrow-2x-6=0\)

\(\Leftrightarrow-2x=6\)

hay x=-3

Vậy: x=-3

2) Ta có: \(10-2\left(4-3x\right)=-4\)

\(\Leftrightarrow10-8+6x+4=0\)

\(\Leftrightarrow6x+6=0\)

\(\Leftrightarrow6x=-6\)

hay x=-1

Vậy: x=-1

3) Ta có: \(-12+3\left(-x+7\right)=-18\)

\(\Leftrightarrow-12-3x+21+18=0\)

\(\Leftrightarrow-3x+27=0\)

\(\Leftrightarrow-3x=-27\)

hay x=9

Vậy: x=9

4) Ta có: \(-45:\left[5\cdot\left(-3-2x\right)\right]=3\)

\(\Leftrightarrow5\cdot\left(-3-2x\right)=-15\)

\(\Leftrightarrow-2x-3=-3\)

\(\Leftrightarrow-2x=0\)

hay x=0

Vậy: x=0

5) Ta có: x(x+3)=0

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)

Vậy: \(x\in\left\{0;-3\right\}\)

6) Ta có: (x-2)(x+4)=0

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)

Vậy: \(x\in\left\{2;-4\right\}\)

7) Ta có: \(x\left(x+1\right)\left(x-3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\\x=3\end{matrix}\right.\)

Vậy: \(x\in\left\{0;-1;3\right\}\)

Bài 1: 

1) Ta có: (−12)+6⋅(−3)(−12)+6⋅(−3)

=−12−18=−12−18

=-30

2) Ta có: (36−2020)+(2019−136)−27(36−2020)+(2019−136)−27

=36−2020+2019−136−27=36−2020+2019−136−27

=1−100−27=1−100−27

=−126

Tớ chcs cậu học thật giỏi nha !