b: Tổng của N là:

\(\dfrac{49\cdot48}{2}=49\cdot24=1176\)

chào nick thứ 2 đây

a) \(3M=1.2.3+2.3.3+...+48.49.3=1.2.3+2.3.\left(4-1\right)+...+48.49.\left(50-47\right)=1.2.3+2.3.4-1.2.3+...+48.49.50-47.48.49=48.49.50\Rightarrow M=\dfrac{48.49.50}{3}\Rightarrow M=39200\)

b) Tương tự câu a

\(3A=1.2.3+2.3.\left(4-1\right)+...+100.101.\left(102-99\right)\)

\(3A=1.2.3+2.3.4-1.2.3+.......+100.101.102-99.100.101\)

\(3A=100.101.102\)

\(A=\frac{100.101.102}{3}\)

\(A=343400\)

3=1.2.3+2.3(4-1)+...+100.101(102-99)

3=1.2.3+2.3.4-1.2.3+.....+100.101.102-99.100.101

3=100.101.101

=100.101.102/3

=343400

mn ủng hộ ^--^

Gọi A là biểu thức ta có: 
A = 1.2+2.3+3.4+......+99.100 
Gấp A lên 3 lần ta có: 
A . 3 = 1.2.3 + 2.3.3 + 3.4.3 + … + 99.100.3 
A . 3 = 1.2.3 + 2.3.(4 - 1) + 3.4.( 5 - 2) + … + 99.100. (101 - 98) 
A . 3 = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + … + 99.100.101 - 98.99.100 
A . 3 = 99.100.101 
A = 99.100.101 : 3 
A = 33.100.101 
A = 333 300

  A= 1.2+2.3+3.4+...+99.100

3A=  1.2.3+2.3.4+3.4.3+...+99.100.3

3A= 1.2.(3-0)+2.3(4-1)+3.4(5-2)+...+ 99.100(101-98)

3A= (1.2.3+2.3.4+3.4.5+...+ 99.100.110)-(0.1.2+1.2.3+2.3.4+3.4.5+...+98.99.100)

3A= 99.100.101- 0.1.2

3A= 999 900-0

3A= 999 900

  A= 999 900:3

  A= 333 300

  GOOD LUCK !!!! ^ ^

A = 1.2 + 2.3 + 3.4 + ....... + 99.100

3A = 1.2.3 + 2.3.3 + 3.4.3 + ....... + 99 . 100 . 3

3A = 1.2.3 + 2.3.(4-1) + 3.4.(5-2)  +.... + 99.100.(101-98)

3A = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ..... + 99 . 100 . 101 - 98 . 99 . 100

3A = (1.2.3 - 1.2.3) + (2.3.4-2.3.4) + ... + (98.99.100 - 98.99.100) + 99  . 100 . 101

3A = 99 . 100 . 101 = 999900

A = 999900 : 3 = 333300

A=1*2+2*3+3*4+...+99*100

A=100*101*102:3

A=343400(công thức)

http://olm.vn/hoi-dap/question/96300.html

Program i: integer;

s: longint;

Begin

s:=0;

for i:=1 to 99 do s:=s + i*(i+1);

write('S=',s);

readln

end.

uses crt;

var i,s:longint;

begin

clrscr;

s:=0;

for i:=1 to 99 do 

  s:=s+i*(i+1);

writeln('S=',s);

readln;

end.

A = 1.2+2.3+3.4+......+99.100 
Gấp A lên 3 lần ta có: 
A . 3 = 1.2.3 + 2.3.3 + 3.4.3 + … + 99.100.3 
A . 3 = 1.2.3 + 2.3.(4 - 1) + 3.4.( 5 - 2) + … + 99.100. (101 - 98) 
A . 3 = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + … + 99.100.101 - 98.99.100 
A . 3 = 99.100.101 
A = 99.100.101 : 3 
A = 33.100.101 
A = 333 300

`S = 1.2 + 2.3 + 3.4 + 4.5 + ... + 99.100.`

`3S =  1.2.3 + 2.3.(4-1) + 3.4.(5-4) + 4.5.(6-3) + ... + 99.100.(101-98)`

`3S =  1.2.3 + 2.3.4-1.2.3 + 3.4.5-4.5.6 + 4.5.6-3.4.5 + ... + 99.100.101-98.99.100`

`3S =  99.100.101`

`S = 33.100.101`

`S = 333300`

3S=1.2(3-0)+2.3(4-1)+.....+99.100(101-98)

=1.2.3-0.1.2+2.3.4-1.2.3+4.5.6-2.3.4+....+99.100.101-98-99-100

=99.100.101

S=33.100.101

=333300

Gọi tổng là A

3.A=1.2.3+2.3.3+3.4.3+...+99.100.3

=1.2.(3-0)+2.3(4-1)+3.4(5-2)+...+99.100(101-98)

=(1.2.3-0.1.2)+(2.3.4-1.2.3)+(3.4.5-2.3.4)+...+(99.100.101-98.99.100)

=99.100.101-0.1.2(vì những số khác giản ước)

=999900-0

=999900

A=999900:3=333300

Vậy A=333300

Đặt P = 1.2+2.3+3.4+...+99.100

3P = 1.2.3+2.3.3+3.4.3+...+99.100+3

3P = 1.2 (3-0) +2.3(4-1)+3.4(5-2) +...+ 99.100( 101-98)

3P = ( 1.2.3 + 2.3.4 + 3.4.5 + 99.100.101 ) -( 0.1.2 + 1.2.3 + 2.3.4 + ....+ 98.99.100)

3P = 99.100.101 - 0.1.2

3P = 999900 - 0

3P = 999900

P = 999900 : 3

P = 333300

Gọi tổng là A

3.A=1.2.3+2.3.3+3.4.3+...+99.100.3

=1.2.(3-0)+2.3(4-1)+3.4(5-2)+...+99.100(101-98)

=(1.2.3-0.1.2)+(2.3.4-1.2.3)+(3.4.5-2.3.4)+...+(99.100.101-98.99.100)

=99.100.101-0.1.2(vì những số khác giản ước)

=999900-0

=999900

A=999900:3=333300

Vậy A=333300