lỗi ảnh , up lại câu  hỏi

lỗi

Lỗi bạn nhé :)

\(25\cdot69+31\cdot25-150\)
\(=25\cdot\left(69+31\right)-150\)
\(=25\cdot100-150\)
\(=2500-150\)
\(=2350\)

= 25 . ( 69 + 31 ) -150

= 25 . 100 - 150

= 2500 - 150 = 2350

=(25.69+31.25)-150

=25(69+31)-150

=25.100-150

=2500-150

=24850

Bài 2

A =  (x + 2)^ 2 - x - 3 x (x + 1) = x² + 4x + 4 - x² + 2x + 3 = 6x + 7

B = x^3 - 2x² + 5x - 10 = x² x (x - 2) + 5 x (x - 2) = (x - 2) x (x² + 5)

Vậy x^3 - 2x² + 5x - 10 : (x - 2) = x² + 5

222+ 967 +178 -267 +209

= (222 + 178) + (967 - 267) +209

= 400+700+209

= 1309 

8.25.29. 2^2.125

= 8. 25. 29. 4. 125

=(25.4) . (8. 125) .29

=100. 1000. 29

= 2900000

\(\text{222+967+178-267+209}=1309 \)
\(\text{8.25.29.2^2.125=2^3}.5^2.29.2^2.5^3=2^5.5^5.29=10^5.29=2900000\)

222+ 967 +178 -267 +209

= (222 + 178) + (967 - 267) +209

= 400+700+209

= 1309

8.25.29. 2^2.125

= 8. 25. 29. 4. 125

=(25.4) . (8. 125) .29

=100. 1000. 29

= 2900000

a) (3a + 1)³ = (3a)³ + 3.(3a)².1 + 3.3a.1² + 1³

                   = 27a³ + 27a² + 9a + 1

b) (4 - 2b)³ = 4³ - 3.4².2b + 3.4.(2b)² - (2b)³

                   = 64 - 96b + 48b² - 8b³

a: Ta có: \(x\left(2-3x\right)+\left(3x^3-x^2\right):x\)

\(=2x-3x^2+3x^2-x\)

=x

b: Ta có: \(2x\left(x-3y\right)-\left(8x^3y-12x^2y^2\right):2xy\)

\(=2x^2-6xy-4x^2+6xy\)

\(=-2x^2\)

Đề bài lỗi rồi bạn, bạn xem lại nhé!

\(=\dfrac{-23-28}{24}=\dfrac{-51}{24}=\dfrac{-17}{8}\)

\(\dfrac{-17}{8}\)